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28 tháng 6 2018
a) \(\frac{16.17-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)1
b ) \(\frac{5}{30}+\frac{15}{90}+\frac{25}{150}+\frac{35}{210}+\frac{45}{270}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\)
\(=\frac{1}{6}.5=\frac{5}{6}\)
28 tháng 6 2018
a) (16x17-5)/(16x16+11)=(16x16-5+16)/(16x16+11)=1
b) (1x5)/(6x5)+(3x5)/(18x5)+...+(9x5)/(54x5)
=1/6+1/6+1/6+1/6+1/6
=5/6
22 tháng 9 2020
a)\(\frac{16.17-5}{16.16+11}=\frac{16.17-16+11}{16.16+11}\)\(=\frac{16.\left(17-1\right)+11}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
b) \(\frac{45.16-17}{28+45.15}=\frac{45.\left(15+1\right)-17}{28+45.15}\)\(=\frac{45.15+45-17}{28+45.15}=\frac{45.15+28}{28+45.15}=1\)
c) \(\frac{7256.4375-725}{3650+4375.7255}=\frac{\left(7255+1\right).4375-725}{3650+4375.7255}\)\(=\frac{7255.4375+4375-725}{3650+4375.7255}\)\(=\frac{7255.4375+3650}{3650+4375.7255}=1\)
AF
22 tháng 9 2020
Câu C nhớ sửa 725 thành 7255 nha !
Bài giải
\(a,\text{ }\frac{16\cdot17-5}{16\cdot16+11}=\frac{16\cdot16+16-5}{16\cdot16+11}=\frac{16\cdot16+11}{16\cdot16+11}=1\)
\(b,\text{ }\frac{45\cdot16-17}{28+45\cdot15}=\frac{45\cdot15+45-17}{45\cdot15+28}=\frac{45\cdot15+28}{45\cdot15+28}=1\)
\(c,\text{ }\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{4375\cdot7255+4375-725}{4375\cdot7255+3650}=\frac{4375\cdot7255+3650}{4375\cdot7255+3650}=1\)
19 tháng 4 2018
C1 : \(\frac{7}{11}\):\(\frac{3}{5}\)+\(\frac{4}{11}\):\(\frac{3}{5}\)
=\(\frac{7}{11}\)x\(\frac{5}{3}\)+\(\frac{4}{11}\)x\(\frac{5}{3}\)
=\(\frac{35}{33}\)+\(\frac{20}{33}\)
=\(\frac{55}{33}\)=\(\frac{5}{3}\)
C2: \(\frac{7}{11}\):\(\frac{3}{5}\)+\(\frac{4}{11}\):\(\frac{3}{5}\)
= \(\frac{3}{5}\)x (\(\frac{7}{11}\)+\(\frac{4}{11}\))
=\(\frac{3}{5}\)x 1= \(\frac{3}{5}\)
SA
19 tháng 4 2018
\(C1:\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
\(=\frac{7}{11}x\frac{5}{3}+\frac{4}{11}x\frac{5}{3}\)
\(=\frac{35}{33}+\frac{20}{33}\)
\(=\frac{55}{33}=\frac{5}{3}\)
\(C2:\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
\(=\frac{7}{11}x\frac{5}{3}+\frac{4}{11}x\frac{5}{3}\)
\(=\frac{5}{3}x\left(\frac{7}{11}+\frac{4}{11}\right)\)
\(=\frac{5}{3}x1=\frac{5}{3}\)
TN
1
AK
15 tháng 4 2018
\(3\frac{5}{11}+\frac{4}{17}-\frac{5}{11}-\frac{3}{17}\)
\(=\left(3\frac{5}{11}-\frac{5}{11}\right)+\left(\frac{4}{17}-\frac{3}{17}\right)\)
\(=3+\frac{1}{17}\)
\(=\frac{51}{17}+\frac{1}{17}\)
\(=\frac{52}{17}\)
Chúc bạn học tốt !!!
14 tháng 5 2019
\(A=11\frac{2}{1.3}+11\frac{2}{3.5}+11\frac{2}{5.7}+11\frac{2}{7.9}+11\frac{2}{9.11}\)
\(A=11+\frac{2}{1.3}+11+\frac{2}{3.5}+11+\frac{2}{5.7}+11+\frac{2}{7.9}+11+\frac{2}{9.11}\)
\(A=55+\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\)
\(A=55+\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\)
\(A=55+\frac{1}{1}-\frac{1}{11}\)
\(A=56-\frac{1}{11}\)
\(A=\frac{616}{11}-\frac{1}{11}=\frac{615}{11}\)
Vậy A = 615 / 11
\(\frac{16.17-5}{16.16+11}\)
= \(\frac{16.\left(16+1\right)-5}{16.16}\)
= \(\frac{16.16+16-5}{16.16+11}\)
= \(\frac{16.16+11}{16.16+11}\)
= \(1\)
\(\frac{16.17-5}{16.16+11}=\frac{17-5}{16+11}=\frac{8}{27}\)
Hok tốt ~~
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