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NQ
1
12 tháng 10 2021
\(=\dfrac{3^{30}\cdot2^{100}}{2^{30}\cdot3^{30}\cdot2^{75}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
DM
10 tháng 12 2021
\(\frac{\left(-27\right)^{10}.16^{25}}{-3.\left(-32\right)^{15}}=\frac{\left(-3\right)^{30}.\left(-2\right)^{100}}{\left(-3\right).\left(-2\right)^{75}}=\frac{\left(-3\right).\left(-3\right)^{29}.\left(-2\right)^{75}.\left(-2\right)^{25}}{\left(-3\right).\left(-2\right)^{75}}\)
= \(\left(-3\right)^{29}.\left(-2\right)^{25}\)
TT
17 tháng 12 2017
a,\(3\dfrac{17}{24}+\left(2\dfrac{8}{15}-4\dfrac{8}{15}\right):\left(2\dfrac{11}{30}-\dfrac{11}{30}\right)\)
\(=\dfrac{89}{24}-2:2\)
\(=\dfrac{65}{24}\)
b,\(0,5:\sqrt{625}-\sqrt{\dfrac{4}{25}}+0,18.\left(\sqrt{1\dfrac{9}{16}}-\sqrt{\dfrac{9}{16}}\right)\)
\(=0,5:25-\dfrac{2}{5}+0,18.\dfrac{1}{2}\)
\(=-\dfrac{29}{100}\)
22 tháng 5 2022
1: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{18}\)
=>4x=18
hay x=9/2
2: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{108}\)
=>4x=108
hay x=27
3: \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
\(\Leftrightarrow\left(\dfrac{1}{3}\right)^{4x}=\left(\dfrac{1}{3}\right)^{12}\)
=>4x=12
hay x=3
9 tháng 10 2017
\((\dfrac{1}{2})^{15}\times(\dfrac{1}{2})^{20}=(\dfrac{1}{2})^{15+20}=(\dfrac{1}{2})^{35}\) \([(\dfrac{1}{3})^2]^{25}\div(\dfrac{1}{3})^{30}=(\dfrac{1}{3})^{50}\div(\dfrac{1}{3})^{30}=(\dfrac{1}{3})^{50-30}=(\dfrac{1}{3})^{20}\) \((\dfrac{1}{16})^3\div(\dfrac{1}{8})^2=[(\dfrac{1}{2})^4]^3\div[(\dfrac{1}{2})^3]^2=(\dfrac{1}{2})^{12}\div(\dfrac{1}{2})^6=(\dfrac{1}{2})^{12-6}=(\dfrac{1}{2})^6\) (x^3)^2 : ( x^2)^3= x^6 :x^6=1
23 tháng 11 2018
\(\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{2}\right)^{20}=\left(\dfrac{1}{2}\right)^{15+20}=\left(\dfrac{1}{2}\right)^{35}\)
\(\left(\dfrac{1}{9}\right)^{25}:\left(\dfrac{1}{3}\right)^{30}=\left[\left(\dfrac{1}{3}\right)^2\right]^{25}:\left(\dfrac{1}{3}\right)^{30}=\left(\dfrac{1}{3}\right)^{50}:\left(\dfrac{1}{3}\right)^{30}=\left(\dfrac{1}{3}\right)^{50-30}=\left(\dfrac{1}{30}\right)^{20}\)\(\left(\dfrac{1}{16}\right)^3:\left(\dfrac{1}{8}\right)^2=\left[\left(\dfrac{1}{2}\right)^4\right]^3:\left[\left(\dfrac{1}{2}\right)^3\right]^2=\left(\dfrac{1}{2}\right)^{12}:\left(\dfrac{1}{2}\right)^6=\left(\dfrac{1}{2}\right)^{12-6}=\left(\dfrac{1}{2}\right)^6\)
\(\left(x^3\right)^2:\left(x^2\right)^3=x^6:x^6=x^0=1\)
6 tháng 10 2022
a: \(=\dfrac{2^{13}\cdot5^7\left(2^{17}+5^{20}\right)}{2^{10}\cdot5^7\left(2^{17}+5^{20}\right)}=2^3\)
b: \(M=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}\)
\(=3^{2\cdot1\cdot13\cdot12}=3^{312}\)
21 tháng 6 2022
Câu 2:
\(B=\dfrac{5^{21}\cdot\left(2\cdot5-9\right)}{5^{20}}\cdot\dfrac{7^{15}\left(7+3\right)}{15\cdot7^{15}-95\cdot7^{14}}\)
\(=\dfrac{5\cdot1}{1}\cdot\dfrac{7^{15}\cdot10}{7^{14}\cdot\left(15\cdot7-95\right)}\)
\(=5\cdot\dfrac{7\cdot10}{105-95}=5\cdot7=35\)
Đặt giá trị biểu thức là A, ta có:
\(A=\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
\(A=\dfrac{\left(\left(-3\right)^3\right)^{10}.\left(2^4\right)^{25}}{2^{30}.3^{30}.\left(\left(-2\right)^5\right)^{15}}\)
\(A=\dfrac{\left(-3\right)^{30}.2^{100}}{2^{30}.3^{30}.\left(-2\right)^{75}}\)
\(A=\dfrac{3^{30}.2^{100}}{2^{30}.2^{75}.3^{30}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)