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a) \(\frac{1}{12}+\frac{3}{15}+\frac{11}{12}+\frac{1}{71}-\frac{12}{10}=\left(\frac{1}{12}+\frac{11}{12}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)+\frac{1}{71}\)

\(=\frac{12}{12}+0+\frac{1}{71}=1+\frac{1}{71}=1\frac{1}{71}=\frac{72}{71}\)

b) \(\frac{2}{3}-4\left(\frac{1}{2}+\frac{3}{4}\right)=\frac{2}{3}-4.\frac{5}{4}=\frac{2}{3}-5=\frac{2}{3}-\frac{15}{3}=-\frac{13}{3}\)

c) \(\frac{-4}{13}.\frac{3}{17}+\frac{-12}{13}.\frac{4}{7}+\frac{4}{13}=\frac{4}{13}.\frac{-3}{17}+\frac{4}{13}.\frac{-12}{17}+\frac{4}{13}.1\)

\(=\frac{4}{13}\left(\frac{-3}{17}+\frac{-12}{17}+1\right)=\frac{4}{13}\left(\frac{-15}{17}+\frac{17}{17}\right)=\frac{4}{13}.\frac{2}{17}=\frac{8}{221}\)

d) \(\frac{10^3+2.5+5^3}{55}=\frac{1000+10+125}{55}=\frac{1135}{55}=\frac{227}{11}\)

4 tháng 9 2018

\(A=\dfrac{5}{4}\left(5-\dfrac{4}{3}\right)\left(-\dfrac{1}{11}\right)\)

\(A=\dfrac{5}{4}.\dfrac{11}{3}.\left(-\dfrac{1}{11}\right)\)

\(A=-\dfrac{5}{12}\)

\(B=\dfrac{3}{4}:\left(-12\right).\left(-\dfrac{2}{3}\right)\)

\(B=\dfrac{3}{4}.\left(-\dfrac{1}{12}\right).\left(-\dfrac{2}{3}\right)\)

\(B=\dfrac{1}{24}\)

\(C=\dfrac{5}{4}:\left(-15\right).\left(-\dfrac{2}{5}\right)\)

\(C=\dfrac{5}{4}.\left(-\dfrac{1}{15}\right).\left(-\dfrac{2}{5}\right)\)

\(C=\dfrac{1}{30}\)

\(D=\left(-3\right)\left(\dfrac{2}{3}-\dfrac{5}{4}\right):\left(-7\right)\)

\(D=\left(-3\right)\left(-\dfrac{7}{12}\right)\left(-\dfrac{1}{7}\right)\)

\(D=-\dfrac{1}{4}\)

Sắp xếp theo thứ tự tăng dần:

\(A,D,C,B\)

14 tháng 9 2017

A=\(\dfrac{5}{4}\).(5-\(\dfrac{4}{3}\)).(\(-\dfrac{1}{11}\))

= \(\dfrac{5}{4}\).\(\dfrac{11}{3}\).(\(-\dfrac{1}{11}\))

=\(\dfrac{5}{4}\).[\(\dfrac{11}{3}.\left(-\dfrac{1}{11}\right)\text{]}\)

=\(\dfrac{5}{4}.\dfrac{1}{3}\)

=\(\dfrac{5}{12}\) (1)

B=\(\dfrac{3}{4}:\left(-12\right).\left(-\dfrac{2}{3}\right)\) =\(\dfrac{3}{4}:\text{[}\left(-12\right).\left(-\dfrac{2}{3}\right)\text{]}\)

=\(\dfrac{3}{4}:8\) =\(\dfrac{3}{4}.\dfrac{1}{8}\)=\(\dfrac{3}{32}\)(2)

C=\(\dfrac{5}{4}:\left(-15\right).\left(-\dfrac{2}{5}\right)\) =\(\dfrac{5}{4}:\text{[}\left(-15\right).\left(-\dfrac{2}{5}\right)\text{]}\)

=\(\dfrac{5}{4}:6=\dfrac{5}{4}.\dfrac{1}{6}=\dfrac{5}{24}\left(3\right)\)

D=(-3).\(\left(\dfrac{2}{3}-\dfrac{5}{4}\right):\left(-7\right)\) =(-3).\(\left(-\dfrac{7}{12}\right)\):(-7)=\(\dfrac{7}{4}:\left(-7\right)\)=\(\dfrac{7}{4}\).\(\left(\dfrac{-1}{7}\right)\)=\(\dfrac{-1}{4}\) (4)

Từ (1),(2),(3)và(4)=>Ta có thể sắp xếp các kết quả trên theo thứ tự tăng dần là:

(Bạn tự làm nhé! mình bận đi học rồileuleu)

\(A=\dfrac{5}{4}\cdot\dfrac{15-4}{3}\cdot\dfrac{-1}{11}=\dfrac{5}{4}\cdot\dfrac{11}{3}\cdot\dfrac{-1}{11}=\dfrac{-5}{12}\)=-50/120

\(B=\dfrac{3}{4}\cdot\dfrac{-1}{12}\cdot\dfrac{-2}{3}=\dfrac{3\cdot2}{4\cdot12\cdot3}=\dfrac{2}{4\cdot12}=\dfrac{1}{24}\)=5/120

\(C=\dfrac{5}{4}\cdot\dfrac{-1}{15}\cdot\dfrac{-2}{5}=\dfrac{2}{4\cdot15}=\dfrac{1}{30}\)=4/120

\(D=3\cdot\dfrac{8-15}{12}\cdot\dfrac{-1}{7}=\dfrac{1}{4}\)=30/120

Vì -50<4<5<30

nên A<C<B<D

Vì A= \(\frac{605}{36}\)

B=\(\frac{-1}{24}\)

C=\(\frac{-1}{30}\)

D= \(\frac{-1}{4}\)

tức là  : A= \(\frac{6050}{360}\)

B=\(\frac{-15}{360}\)

C=\(\frac{-12}{360}\)

D=\(\frac{-90}{360}\)

nÊN được sắp xếp theo thứ tự tăng dần là B < C  < D < A

D=

11 tháng 9 2017

A = \(\frac{5}{4}.\left(5-\frac{4}{3}\right).\frac{1}{11}\)

A = \(\frac{5}{44}\left(5-\frac{4}{3}\right)\)

A = \(\frac{25}{44}-\frac{5}{33}\)

A = \(\frac{25.3}{4.11.3}-\frac{5.4}{3.11.4}\)

A = \(\frac{75}{132}-\frac{20}{132}\)

A = \(\frac{55}{132}\)

B = \(\frac{3}{4}:\left(-12\right).\left(-\frac{2}{3}\right)\)

B = \(\frac{-1}{16}.\left(-\frac{2}{3}\right)\)

B = \(\frac{1}{24}\)

C = \(\frac{5}{4}:\left(-15\right).\left(-\frac{2}{5}\right)\)

C = \(\frac{-1}{12}.\left(-\frac{2}{5}\right)\)

C = \(\frac{1}{30}\)

D = \(\left(-3\right).\left(\frac{2}{3}-\frac{5}{4}\right):\left(-7\right)\)

D = \(\frac{3}{7}.\left(\frac{8}{12}-\frac{15}{12}\right)\)

D = \(\frac{3}{7}.\left(-\frac{7}{12}\right)\)

D = \(\frac{-3}{12}\)

D = \(\frac{-1}{4}\)