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a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)
b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)
d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)
\(\dfrac{-63}{72}=\dfrac{-7}{8}\)
\(\dfrac{20}{-140}=\dfrac{-1}{7}\)
\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)
\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)
\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)
a) 4.79.32=4.79.4.8=79.8=7724.79.32=4.79.4.8=79.8=772
b) 3.2114.15=3.3.72.7.3.5=32.5=3103.2114.15=3.3.72.7.3.5=32.5=310
c) 2.5.1326.35=2.5.132.13.5.7=172.5.1326.35=2.5.132.13.5.7=17
d) 9.6–9.318=9.(6–3)9.2=6–32=329.6–9.318=9.(6–3)9.2=6–32=32
e) 17.5–173–20=17.(5–1)–17=5–1–1=–417.5–173–20=17.(5–1)–17=5–1–1=–4
f) 49+7.4949=49.(1+7)49=1+7=8
\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot8\cdot4}=\frac{7}{8\cdot9}=\frac{7}{72}\)
\(\frac{2\cdot5\cdot13}{26\cdot35}=\frac{2\cdot5\cdot13}{2\cdot13\cdot7\cdot5}=\frac{1}{7}\)
\(\frac{3\cdot21}{14\cdot15}=\frac{3\cdot3\cdot7}{2\cdot7\cdot3\cdot5}=\frac{3}{2\cdot5}=\frac{3}{10}\)
\(\frac{9\cdot6-9\cdot3}{18}=\frac{9\cdot\left(6-3\right)}{9\cdot2}=\frac{9\cdot3}{9\cdot2}=\frac{3}{2}\)
\(\frac{17\cdot5-17}{3-20}=\frac{17\cdot\left(5-1\right)}{-17}=\frac{17\cdot4}{17\cdot\left(-1\right)}=\frac{4}{-1}=-4\)
\(45dm^2=0,45m^2\)
\(300cm^2=0,03m^2\)
\(57500mm^2=0,0575m^2\)
a) \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{72}\) b) \(\dfrac{3.21}{14.15}=\dfrac{3.7.3}{7.2.3.5}=\dfrac{3}{10}\)
c) \(\dfrac{2.5.13}{26.35}=\dfrac{2.5.13}{2.13.5.7}=\dfrac{1}{7}\) d)\(\dfrac{9.6-9.3}{18}\) \(=\dfrac{9.\left(6-3\right)}{9.2}=\dfrac{9.3}{9.2}=\dfrac{3}{2}\)
e) \(\dfrac{17.5-17}{3-20}=\dfrac{17.\left(5-1\right)}{-17}=-\dfrac{17.4}{17}=-4\) f) \(\dfrac{49+7.49}{49}=\dfrac{49.\left(1+7\right)}{49}=8\)
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