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TT
1
SG
2
VT
21 tháng 6 2017
a,\(x^2+4x+3\)
=\(x^2+3x+x+3\)
=\(x\left(x+3\right)+\left(x+3\right)\)
=(x+3)(x+1)
b,\(2x^2+3x-5\)
=\(2x^2+5x-2x-5\)
=x(2x+5)-(2x+5)
=(2x+5)(x-1)
c,\(16x-5x^2-3\)
=\(-\left(5x^2-16x+3\right)\)
=\(-\left(5x^2-x-15x+3\right)\)
=-[x(5x-1)-3(5x-1)]
=-[(5x-1)(x-3)]
=-(5x-1)(x-3)
5 tháng 8 2017
\(a.\) \(x^2+4x+3\)
\(=x^2+x+3x+3\)
\(=x\left(x+1\right)+3\left(x+1\right)\)
\(=\left(x+3\right)\left(x+1\right)\)
\(b.\) \(2x^2+3x-5\)
\(=2x^2-2x+5x-5\)
\(=2x\left(x-1\right)+5\left(x-1\right)\)
\(=\left(x-1\right)\left(2x+5\right)\)
\(c.\)\(16x-5x^2-3\)
\(=-5x^2+16x-3\)
\(=-5x^2+15x+x-3\)
\(=-5x\left(x-3\right)+\left(x-3\right)\)
\(=\left(x-3\right)\left(1-5x\right)\)
29 tháng 9 2018
\(16x^4+y^4+4x^2y^2\)
\(=\left(4x^2\right)^2+2.4x^2.y^2+\left(y^2\right)^2-4x^2y^2\)
\(=\left(4x^2+y^2\right)-\left(2xy\right)^2\)
\(=\left(4x^2-2xy+y^2\right)\left(4x^2+2xy+y^2\right)\)
\(x^3-2x-4\)
\(=x^3-2x^2+2x^2-4x+2x-4\)
\(=x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\)
\(=\left(x-2\right)\left(x^2+2x+2\right)\)
\(x^3+x^2+4\)
\(=x^3+2x^2-x^2-2x+2x+4\)
\(=x^2\left(x+2\right)-x\left(x+2\right)+2\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-x+2\right)\)
TH
1
15 tháng 10 2016
a) \(x^4-2x^3+2x-1\)
\(=x^4-x^3-x^3+2x-2+1\)
\(=\left(x^4-x^3\right)+\left(2x-2\right)-\left(x^3-1\right)\)
\(=x^3\left(x-1\right)+2\left(x-1\right)-\left(x-1\right)\left(x^2+x+1\right)\)
\(=\left(x-1\right)\left(x^3+2-x^2-x-1\right)\)
\(=\left(x-1\right)\left(x^3-x^2-x+1\right)\)
\(=\left(x-1\right)\left[\left(x^3-x^2\right)-\left(x-1\right)\right]\)
\(=\left(x-1\right)\left[x^2\left(x-1\right)-\left(x-1\right)\right]\)
\(=\left(x-1\right)\left(x^2-1\right)\left(x-1\right)\)
\(=\left(x-1\right)^2\left(x-1\right)\left(x+1\right)\)
\(=\left(x-1\right)^3\left(x+1\right)\)
b) \(x^4+2x^3+2x^2+2x+1\)
\(=\left(x^4+2x^2+1\right)+\left(2x^3+2x\right)\)
\(=\left(x^2+1\right)^2+2x\left(x^2+1\right)\)
\(=\left(x^2+1\right)\left(x^2+1+2x\right)\)
\(=\left(x^2+1\right)\left(x+1\right)^2\)
NT
1
6 tháng 10 2018
\(x^6-x^4+2x^3+2x^2\)
\(=x^2\left(x^4-x^2+2x+2\right)\)
\(=x^2\left[x^4-2x^3+x^2+2x^3-4x^2+2x+2x^2-4x+2\right]\)
\(=x^2\left[x^2\left(x^2-2x+1\right)+2x\left(x^2-2x+1\right)+2\left(x^2-2x+1\right)\right]\)
\(=x^2\left(x^2-2x+1\right)\left(x^2+2x+2\right)\)
\(=x^2\left(x-1\right)^2\left(x^2+2x+2\right)\)
TH
5
M
7 tháng 8 2019
A, (x+2)² - x² +2x -1
= (x+2)² -(x² - 2x +1)
= (x+2)² - (x -2)²
= (x +2 + x -2).(x+2-x+2)
=2x.2 =4x
B, 16x² -y²
= (4x)² - y²
= (4x - y).(4x + y)
Tk mình với bạn ơi. Đúng rồi nhé!!
CHÚC BẠN HỌC TỐT ✓✓
7 tháng 8 2019
1, \(\left(x+2\right)^2-x^2+2x-1\)
\(=\left(x+2\right)^2-\left(x-1\right)^2\)
\(=\left(2x+1\right)\left(x+3\right)\)
\(2,16x^2-y^2=\left(4x+y\right)\left(4x-y\right)\)
\(x^4+2x^3-16x^2-2x+15\)
\(=x^4+5x^3-3x^3-15x^2-x^2-5x+3x+15\)
\(=x^3\left(x+5\right)-3x^2\left(x+5\right)-x\left(x+5\right)+3\left(x+5\right)\)
\(=\left(x+5\right)\left(x^3-3x^2-x+3\right)\)
\(=\left(x+5\right)\left[x^2\left(x-3\right)-\left(x-3\right)\right]\)
\(=\left(x+5\right)\left(x-3\right)\left(x^2-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(x-3\right)\left(x+5\right)\)