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\(8xy^3+x\left(x-y\right)^3\)
\(=x\left[8y^3+\left(x-y\right)^3\right]\)
\(=x\left[\left(2y\right)^3+\left(x-y\right)^3\right]\)
\(=x\left(2y+x-y\right)\left[\left(2y\right)^2-2y\left(x-y\right)+\left(x-y\right)^2\right]\)
\(=x\left(x+y\right)\left(4y^2-2xy+2y^2+x^2-2xy+y^2\right)\)
\(=x\left(x+y\right)\left(7y^2+x^2-4xy\right)\)
1. \(xy\left(a^2+2b^2\right)-ab\left(2x^2+y^2\right)\)
\(=xya^2+2xyb^2-2abx^2-aby^2\)
\(=xya^2-aby^2-2abx^2+2xyb^2\)
\(=ay\left(ax-by\right)-2bx\left(ax-by\right)\)
\(=\left(ay-2bx\right)\left(ax-by\right)\)
2. \(xy\left(a^2+2b^2\right)+ab\left(2x^2+y^2\right)\)
\(=xya^2+2xyb^2+2abx^2+aby^2\)
\(=xya^2+aby^2+2abx^2+2xyb^2\)
\(=ay\left(ax+by\right)+2bx\left(ax+by\right)\)
\(=\left(ay+2bx\right)\left(ax+by\right)\)
1. Ta có: \(3xy\left(a^2+b^2\right)+ab\left(x^2-9y^2\right)\)
\(=3xya^2+3xyb^2+abx^2+ab9y^2\)
\(=\left(3xya^2+abx^2\right)+\left(3xyb^2+ab9y^2\right)\)
\(=ax\left(3ya+bx\right)+3by\left(xb+3ya\right)\)
\(=\left(3ya+xb\right)\left(3yb+ax\right)\)
2.Check lại đề hộ mình nha:((
Câu 2 nên sủa lại đề nha
2. xy(a2+2b2)+ab(2x2+y2)
=xya2+xy2b2+ab2x2+aby2
=(xya2+aby2)+(xy2b2+ab2x2)
=ay(ax+by)+2bx(by+ax)
=(ax+by(ay+2bx)
\(x^6-y^6\)
\(=\left(x^3\right)^2-\left(y^3\right)^2\)
\(=\left(x^3+y^3\right)\left(x^3-y^3\right)\)
\(x^6-y^6\)
\(=\left(x^3\right)^2-\left(y^3\right)^2\)
\(=\left(x^3+y^3\right)\left(x^3-y^3\right)\)
a) 27x^3 –27x^2 +18x –4
= 27x^3 –9x^2–18x^2+6x + 12x –4
= 9x^2 (3x–1) – 6x (3x–1) +4(3x–1)
= (3x-1) (9x^2–6x+4)
b)2x^3–2x^2+5x+3
= 2x^3+x^2–2x^2–x+6+3
= x^2(2x+1)-x^2(2x+1)+3(2x+1)
= (2x+1) 3
c) 2x^4 + 5x^3+13x^2+25x+15
=2x^3(x+1)+3x^2(x+1)+10x(x+1)+15(x+1)
=(x+1)(x^2(2x+3)+5(2x+3))
=(x+1)(2x+3)(x^2+5)
\(\left(2a+b\right)^2-\left(2a+a\right)^2\)
\(=\left(2a+b-2a-a\right)\left(2a+b+2a+a\right)\)
\(=\left(b-a\right)\left(5a+b\right)\)
\(\left(2a+b\right)^2-\left(2a+a\right)^2\)
\(=\left(2a+b\right)^2-\left(3a\right)^2\)
\(=\left(2a+b-3a\right)\left(2a+b+3a\right)\)
\(=\left(b-a\right)\left(5a+b\right)\)
Đề sai nhé .Sửu lại
\(x^2-4x^2y^2+4+4x\)
\(=\left(x^2+4x+4\right)-4x^2y^2\)
\(=\left(x+2\right)^2-\left(2xy\right)^2\)
\(=\left(x+2+2xy\right)\left(x+2-2xy\right)\)
x2+(2a+b)xy+2aby2
=x2+2axy+bxy+2aby2
=(x2+bxy)+(2axy+2aby2)
=x(x+by)+2ay(x+by)
=(x+by)(x+2ay)
cảm ơn bn