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YF
1
13 tháng 8 2017
x^2+6xy+9y^2-3x-9y+2
=( x^2+6xy+9y^2)-3(x+3y)+9/4 -1/4
=(x+3y)^2-3(x+3y)+(3/2)^2- 1/4
=(x+3y+3/2)^2-(1/2)^2
=(x+3y+3/2+1/2)(x+3y+3/2-1/2)=(x+3y+2)(x+3y+1)
TP
3
DN
23 tháng 9 2018
a) 7(x-y)
b) (x-3y)2
c) xy(x+y)-(x+y)=(xy-1)(x+y)
d) x2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)
KC
3
28 tháng 8 2018
a) ( x-3y ) ( x + 1 )
b) ( x+y+5 ) ( x+y-5 )
c) ( x-5 ) ( x+2 )
Hk tốt
PA
23 tháng 12 2016
\(1-2y+y^2=\left(1-y\right)^2\)
\(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)
\(1-4x^2=\left(1-2x\right)\left(1+2x\right)\)
\(27+27x+9x^2=9\left(3+3x+x^2\right)\)
\(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)
\(3x^2-6xy+9y^2=3\left(x^2-2xy+3y^2\right)\)
\(x^2+4x+3=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)
\(x^2-4x-5=x^2+x-5x-5=x\left(x+1\right)-5\left(x+1\right)=\left(x-5\right)\left(x+1\right)\)
23 tháng 12 2016
a ) \(1-2y+y^2=y^2-2y+1=\left(y-1\right)^2\)
b ) \(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right).\)
c ) \(1-4x^2=\left(1-2x\right)\left(1+2x\right).\)
d ) \(27+27x+9x^2=9\left(3+3x+x\right)=9\left(3+4x\right).\)
e ) \(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)
f ) \(3x^2-6xy+9y^2=3\left(x^2-2xy+3y^2\right).\)
g ) \(x^2+4x+3==x^2+3x+x+3=\left(x+1\right)\left(x+3\right)\)
h ) \(x^2-4x-5=x^2+x-5x-5=\left(x-5\right)\left(x+1\right).\)
NN
2
TM
13 tháng 9 2017
a)\(x^2-6xy+9y^2-25z^2=\left[x^2-2.x.3y+\left(3y\right)^2\right]-\left(5z\right)^2\)
\(=\left(x-3y\right)^2-\left(5z\right)^2=\left(x-3y-5z\right)\left(x-3y+5z\right)\)
b)\(xyz+x^2yz-6yz=yz\left(x^2+x-6\right)=yz\left(x^2+3x-2x-6\right)\)
\(=yz\left[x\left(x+3\right)-2\left(x+3\right)\right]=yz\left(x-2\right)\left(x+3\right)\)
13 tháng 9 2017
a.x2-6xy+9y2-25z2
= ( x2-6xy+9y2)-25z2
= [x2-2x3y+(3y)2]-25z2
= (x-3y)2-252
= (x-3y+25)(x-3y-25)
NV
1
15 tháng 12 2016
a)\(x^2-6xy+9y^2=x^2-2\cdot x\cdot3y+\left(3y\right)^2=\left(x-3y\right)^2\)
b) \(\left(x^2+1\right)^2-4x^2\)
\(=\left(x^2+1+2x\right)\left(x^2+1-2x\right)\)
\(=\left(x+1\right)^2\left(x-1\right)^2\)
27 tháng 10 2020
a) 2x3 + 6xy - x2z - 3yz
= ( 2x3 + 6xy ) - ( x2z + 3yz )
= 2x( x2 + 3y ) - z( x2 + 3y )
= ( x2 + 3y )( 2x - z )
b) x2 - 6xy + 9y2 - 49
= ( x2 - 6xy + 9y2 ) - 49
= ( x - 3y )2 - 72
= ( x - 3y - 7 )( x - 3y + 7 )
c) x3 + 4x2 + 16x + 64
= ( x3 + 4x2 ) + ( 16x + 64 )
= x2( x + 4 ) + 16( x + 4 )
= ( x + 4 )( x2 + 16 )
27 tháng 10 2020
a) =(2x^3-x^2z)+(6xy-3yz)
=x^2(2x-z)+3y(2x-z)
=(x^2+3y)(2x-z)
b) =(x^2-6xy+9y^2)-7^2
=(x-3y)^2-7^2
=(x-3y+7)(x-3y-7)
c) =(x^3+4x^2)+(16x+64)
=x^2(x+4)+16(x+4)
=(x^2+16)(x+4)
A
19 tháng 12 2020
a) 15x2 + 10x = 5x ( 3x +2 )
b) x2 - y2 +2x -2y
= (x-y) (x+y) + 2(x-y)
= (x - y) ( x + y + 2)
c) 3x2 + 6xy + 3y2 -12 z2
= 3 ( x2 +2xy+y2) -12z2
= 3 (x+y)2 - 12 z2
= 3 [(x+y)2 - 4z2 ]
= 3( x + y - 2z )( x + y + 2z)
d) x2 - 5 -6 = x2 -11
= (x - √11)(x+√11)
19 tháng 12 2020
a, \(15x^2+10x=5x\left(3x+2\right)\)
b, \(x^2-y^2+2x-2y=\left(x-y\right)\left(x+y\right)+2\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y+2\right)\)
c, \(3x^2+6xy+3y^2-12z^2\)
\(=3\left(x^2+2xy+y^2-4z^2\right)\)
\(=3\left[\left(x+y\right)^2-\left(2z\right)^2\right]=3\left(x+y-2z\right)\left(x+y+2z\right)\)
d, \(x^2-5x-6=x^2-6x+x-6=x\left(x+1\right)-6\left(x+1\right)=\left(x-6\right)\left(x+1\right)\)
10 tháng 7 2018
a) xy – 3x + 2y – 6
= (xy - 3x) + (2y - 6)
= x(y - 3) + 2(y - 3)
= (y - 3)(x + 2)
b) x2y + 4xy + 4y – y3
= y(x2 + 4x + 4 - y2)
= y[(x2 + 4x + 4) - y2]
= y[(x + 2)2 - y2]
= y(x + 2 + y)(x + 2 - y)
c) x2 + y2 + xz + yz + 2xy
= (x2 + 2xy + y2) + (xz + yz)
= (x + y)2 + z(x + y)
= (x + y)(x + y + z)
d) x3 + 3x2 – 3x – 1
= (x3 - 1) + (3x2 - 3x)
= (x - 1)(x2 + x + z) + 3x(x - 1)
= (x - 1)(x2 + 4x + 1)
AK
10 tháng 7 2018
a )
\(xy-3x+2y-6\)
\(=\left(xy+2y\right)-3x-6\)
\(=y\left(x+2\right)-3\left(x+2\right)\)
\(=\left(y-3\right)\left(x+2\right)\)
b )
\(x^2y+4xy+4y-y^3\)
\(=y\left(x^2+4x+4-y^2\right)\)
\(=y\left[\left(x+2\right)^2-y^2\right]\)
\(=y\left(x+2-y\right)\left(x+2+y\right)\)
c )
\(x^2+y^2+xz+yz+2xy\)
\(=\left(x+y\right)^2+z\left(x+y\right)\)
\(=\left(x+y\right)\left(x+y+z\right)\)
\(xy-3x-2y+6=x\left(y-3\right)-2\left(y-3\right)=\left(y-3\right)\left(x-2\right)\)
\(x^2-6xy-4z^2+9y^2=\left(x-3y\right)^2-\left(2z\right)^2=\left(x-3y-2z\right)\left(x-3y+2z\right)\)