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a) \(-5x^2+16x-3=-5x^2+15x+x-3=-5x\left(x-3\right)+x-3=\left(x-3\right)\left(1-5x\right).\)
b) \(x^4+64=x^4+16x^2+64-16x^2=\left(x^2+8\right)^2-\left(4x\right)^2=\left(x^2+4x+8\right)\left(x^2-4x+8\right).\)
c) \(64x^2+4y^4=4\left(16x^2+y^4\right)\)
d) \(x^5+x-1\)đa thức này có nghiệm vô tỷ. Mik ko phân tích được.
mình chỉ làm được câu b) thôi ^^
a^2-2ab+b^2-4x^2
= (a-b)^2-(2x)^2
= (a-b+2x)(a-b-2x)
a/ x2+2x-y2+1=x2+2x+1-y2
= x2+x+x+1-y2
= x(x+1)+(x+1)-y2
= (x+1)2-y2
= (x+1-y)(x+1+y)
b/ a2-2ab+b2-4x2=a2-ab-ab+b2-(2x)2
=a(a-b)-b(a-b)-(2x)2
=(a-b)2-(2x)2
= (a-b-2x)(a-b+2x)
a) \(\left(x-7\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
a) x2 - 9x + 8
= x2 - 9x - 1 + 9
= (x2 - 1) + (-9x + 9)
= (x + 1) (x - 1) - 9(x - 1)
= (x - 1) (x + 1 - 9)
= (x - 1) (x - 8)
b) x2 + 6x + 8
= x2 + 2x + 4x + 8
= (x2 + 2x) + (4x + 8)
= x(x + 2) + 4(x + 2)
= (x + 2) (x + 4)
ok mk nha!!! 6476775758766925353464565645645765687687676976924563464554
a) x2 - 9x + 8
= x2 - 9x - 1 + 9
= (x2 - 1) + (-9x + 9)
= (x + 1) (x - 1) - 9(x - 1)
= (x - 1) (x + 1 - 9)
= (x - 1) (x - 8)
b) x2 + 6x + 8
= x2 + 2x + 4x + 8
= (x2 + 2x) + (4x + 8)
= x(x + 2) + 4(x + 2)
= (x + 2) (x + 4)
a) 5x2 - 5xy - 3x + 3y
= 5x.(x - y) - 3.(x - y)
= (x - y).(5x - 3)
b) x3 - 2x2 - x + 2
= x2.(x - 2) - (x - 2)
= (x - 2).(x2 - 1)
= (x - 2).(x - 1).(x + 1)
a/ 5x2-5xy-3x+3y
=5x.(x-y)-3(x-y)
=(5x-3).(x-y)
b/ x3-2x2-x+2
=x2.(x-2)-(x-2)
=(x2-1).(x-2)
=(x-1).(x+1).(x-2)
a) 3x2 + 10x + 8
= 3x2 + 6x + 4x + 8
= 3x.(x + 2) + 4.(x + 2)
= (x + 2).(3x + 4)
b) 2x2 + x - 6
= 2x2 + 4x - 3x - 6
= 2x.(x + 2) - 3.(x + 2)
= (x + 2).(2x - 3)
a) \(\left(3x+4\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
a/ 16x2 - 4y2 = (4x + 2y)(4x - 2y)
b/ x4 + 1 = (x2 + √2 x + 1)(x2 - √2 x + 1)
a/ 16x2-4y2=(4x)2-(2y)2=(4x+2y)(4x-2y)
b/ x4+1=(x2)2+12=(x2+1)(x2-1)
k minh nha