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PT
0
YB
1
TN
3 tháng 1 2017
a)\(\left(x^2-x+2\right)^2+\left(x-2\right)^2\)
\(=x^4-2x^3+6x^2-8x+8\)
\(=x^4-2x^3+2x^2+4x^2-8x+8\)
\(=x^2\left(x^2-2x+2\right)+4\left(x^2-2x+2\right)\)
\(=\left(x^2+4\right)\left(x^2-2x+2\right)\)
b)\(6x^5+15x^4+20x^3+15x^2+6x+1\)
\(=6x^5+3x^4+12x^4+6x^3+14x^3+7x^2+8x^2+4x+2x+1\)
\(=3x^4\left(2x+1\right)+6x^3\left(2x+1\right)+7x^2\left(2x+1\right)+4x\left(2x+1\right)+\left(2x+1\right)\)
\(=\left(3x^4+6x^3+7x^2+4x+1\right)\left(2x+1\right)\)
\(=\left[3x^4+3x^3+x^2+3x^3+3x^2+x+3x^2+3x+1\right]\left(2x+1\right)\)
\(=\left[x^2\left(3x^2+3x+1\right)+x\left(3x^2+3x+1\right)+\left(3x^2+3x+1\right)\right]\left(2x+1\right)\)
\(=\left(x^2+x+1\right)\left(3x^2+3x+1\right)\left(2x+1\right)\)
PT
0
MA
1 tháng 10 2016
1) \(6x^2-15x+6\)
\(=6x^2-3x-12x+6\)
\(=3x\left(2x-1\right)-6\left(2x-1\right)\)
\(=\left(3x-6\right)\left(2x-1\right)\)
\(=3\left(x-2\right)\left(2x-1\right)\)
b) \(6x^2-20x+6\)
\(=6x^2-2x-18x+6\)
\(=2x\left(3x-1\right)-6\left(3x-1\right)\)
\(=\left(2x-6\right)\left(3x-1\right)\)
\(=2\left(x-3\right)\left(3x-1\right)\)
c) \(-10x^2-7x+6\)
\(=5x-10x^2+6-12x\)
\(=5x\left(1-2x\right)+6\left(1-2x\right)\)
\(=\left(5x+6\right)\left(1-2x\right)\)
d) \(10x^2-7x-12\)
\(=10x^2-15x+8x-12\)
\(=5x\left(2x-3\right)+4\left(2x-3\right)\)
\(=\left(5x+4\right)\left(2x-3\right)\)
QD
1 tháng 10 2016
1) 6x^2 - 15x + 6
= 6x^2 - 12x - 3x +6
= 6x (x - 2) - 3 (x - 2)
= (x - 2) (6x - 3)
= 3 (x - 2) (x - 1)
2) 6x^2 - 20x + 6
= 6x^2 - 18x - 2x + 6
= 6x (x - 3) - 2 (x - 3)
= (x - 3) (6x - 2)
= 2 (x - 3) (3x - 1)
3) -10x^2 - 7x + 6
= -10x^2 + 5x - 12x + 6
= 5x (1 - 2x) + 6 (1 - 2x)
= (1 - 2x) (5x + 6)
4) 10x^2 - 7x - 12
= 10x^2 - 15x + 8x - 12
= 5x (2x - 3) + 4 (2x - 3)
= (2x - 3) (5x + 4)
good luck !
DV
1
NV
Nguyễn Việt Lâm
Giáo viên
16 tháng 3 2019
a/ \(\left(x^2-x+2\right)^2+\left(x-2\right)^2=\left(x^2-x+2\right)^2-x^2+x^2+\left(x-2\right)^2\)
\(=\left(x^2-2x+2\right)\left(x^2+2\right)+2x^2-4x+4\)
\(=\left(x^2-2x+2\right)\left(x^2+2\right)+2\left(x^2-2x+2\right)\)
\(=\left(x^2-2x+2\right)\left(x^2+4\right)\)
b/ \(6x^5+15x^4+20x^3+15x^2+6x+1\)
\(=6x^5+6x^4+2x^3+9x^4+9x^3+3x^2+9x^3+9x^2+3x+3x^2+3x+1\)
\(=2x^3\left(3x^2+3x+1\right)+3x^2\left(3x^2+3x+1\right)+3x\left(3x^2+3x+1\right)+3x^2+3x+1\)
\(=\left(3x^2+3x+1\right)\left(2x^3+3x^2+3x+1\right)\)
\(=\left(3x^2+3x+1\right)\left(x^3+\left(x+1\right)^3\right)\)
\(=\left(3x^2+3x+1\right)\left(2x+1\right)\left(x^2-\left(x+1\right)x+\left(x+1\right)^2\right)\)
\(=\left(3x^2+3x+1\right)\left(3x+1\right)\left(x^2+x+1\right)\)
29 tháng 1 2020
a) \(6x^2-x-1\)
\(=6x^2-3x+2x-1\)
\(=3x\left(2x-1\right)+\left(2x-1\right)\)
\(=\left(3x+1\right)\left(2x-1\right)\)
DT
2
T
16 tháng 9 2018
a) Ta có \(6x^2-15x+9=3.\left(2x^2-5x+3\right)=3.\left(2x^2-2x^2-3x+3\right)\)
\(=3.\left[2x.\left(x-1\right)-3.\left(x-1\right)\right]=3.\left(2x-3\right).\left(x-1\right)\)
b) Ta có \(5x^2+12x+7=5x^2+5x+7x+7=5x.\left(x+1\right)+7.\left(x+1\right)\)
\(=\left(x+1\right)\left(5x+7\right)\)
16 tháng 9 2018
a) \(6x^2-15x+9\)
\(=3\left(2x^2-5x+3\right)\)
\(=3\left(x-1\right)\left(2x-3\right)\)
b) \(5x^2+12x+7\)
\(=\left(5x^2+5x\right)+\left(7x+7\right)\)
\(=5x\left(x+1\right)+7\left(x+1\right)\)
\(=\left(x+1\right)\left(5x+7\right)\)
(2x+1)(x2+x+1)(3x2+3x+1)
6x^5+15x^4+20x^3+15x^2+6x+1
=3x^4(2x+1)+6x^3(2x+1)+7x^2(2x+1)+4x(2x+1)+(2x+1)
=(2x+1)(3x^4+6x^3+7x^2+4x+1)
=(2x+1)(3x^2(x^2+x+1)+3x(x^2+x+1)+(x^2+x+1)
=(2x+1)(x^2+x+1)(3x^2+3x+1)