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a,(5x-2y)(x2-xy+1)=5x3-5x2+5x-2yx2+2xy2-2y
=5x3-7x2y+2xy2+5x-2y
b,(x-2)(x+2)(\(\dfrac{1}{2}\) x-5)=x2-4.\(\left(\dfrac{1}{2}x-5\right)\)
=\(\dfrac{1}{2}x^3-5x^2-2x+20\)
c,\(\left(x^2-2x+3\right)\left(\dfrac{1}{2}x-5\right)\)
=\(\dfrac{1}{2}x^3-5x^2-1x^2+10x+\dfrac{3}{2}x-15\)
=\(\dfrac{1}{2}x^3-6x^2+\dfrac{23}{2}x-15\)
d,\(\left(x^2-5\right)\left(x+3\right)+\left(x+4\right)\left(x-x^2\right)\)
=\(x^3+3x^2-5x-15+x^2-x^3+4x-4x^2\)
=\(-5x+4x-15\)
=\(-x-15\)
Chúc bạn học tốt(mỏi tay quá)
\(A=\left(2n-1\right)^3-2n+1\)
\(A=8n^3-6n+6n-1-2n+1\)
\(A=8n^3-2n=2n\left(4n^2-1\right)\)
\(A=2n\left(2n+1\right)\left(2n-1\right)\)
\(A=\left(2n-1\right)2n\left(2n+1\right)⋮6\) ( 3 số tự nhiên liên tiếp)
Bài 1 : \(2\left(3x-1\right)-3x=10\)
\(\Leftrightarrow6x-2-3x=10\)
\(\Leftrightarrow3x=12\)
\(\Leftrightarrow x=4\)
Vậy...................
b ) \(\dfrac{x+1}{x}+1=\dfrac{3x-1}{x+1}+\dfrac{1}{x\left(x+1\right)}\left(1\right)\)
ĐKXĐ : \(x\ne0;x\ne-1\)
\(\left(1\right)\Rightarrow\left(x+1\right)^2+x\left(x+1\right)=x\left(3x-1\right)+1\)
\(\Leftrightarrow x^2+2x+1+x^2+x-3x^2+x-1=0\)
\(\Leftrightarrow-x^2+4x=0\)
\(\Leftrightarrow x\left(-x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(KTMĐKXĐ\right)\\x=4\left(TMĐKXĐ\right)\end{matrix}\right.\)
Vậy .......................
c ) \(\dfrac{2x+1}{3}-\dfrac{3x-2}{2}>\dfrac{1}{6}\)
\(\Leftrightarrow2\left(2x+1\right)-3\left(3x-2\right)>1\)
\(\Leftrightarrow4x+2-9x+6>1\)
\(\Leftrightarrow-5x>-7\)
\(\Leftrightarrow x< \dfrac{7}{5}.\)
Vậy .......
a ) \(A=\left(\dfrac{x^2-3}{x^2-9}+\dfrac{1}{x-3}\right):\dfrac{x}{x+3}.ĐKXĐ:x\ne3;x\ne-3\)
\(A=\left(\dfrac{x^2-3}{\left(x-3\right)\left(x+3\right)}+\dfrac{1}{\left(x-3\right)}\right).\dfrac{x+3}{x}\)
\(A=\dfrac{x^2-3x+x^2+3x}{x\left(x-3\right)\left(x+3\right)}.\dfrac{x+3}{x}\)
\(A=\dfrac{x+1}{x-3}\)
b ) \(\left|A\right|=3.\) thì x là ?
\(\left|\dfrac{x+1}{x-3}\right|=3\)
Kẻ bảng ra làm nha :D
có, nick Như Huỳnh, avt có chữ Như Huỳnh
mk là Trôi's Của 's Cua's , avt là 1 cậu con trai tai thỏ hồng