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\(=2.34\left(2+2\cdot2+3\cdot2-2\right)=2.34\cdot10=23.4\)
\(0,18\text{×}1230+0,9\text{×}1567\text{×}2-3\text{×}690\\ =221,4+2820,6-2070=1015\)
\(\left(x+2\right)+\left(x+4\right)+...+\left(x+1996\right)=9800\)
\(\Leftrightarrow998x+\left(2+4+...+1996\right)=9800\)
\(\Leftrightarrow998x+\frac{\left(1996+2\right)\left[\left(1996-2\right)\div2+1\right]}{2}=9800\)
\(\Leftrightarrow998x+997002=9800\)
\(\Leftrightarrow998x=9800-997002\)
\(\Leftrightarrow998x=-987202\)
\(\Leftrightarrow x=-987202\div998\)
\(\frac{75}{100}+\frac{3}{4}\times29+75\%\times30+0,75\times40\)
\(=0,75+0,75\times29+\frac{75}{100}\times30+0,75\times40\)
\(=0,75\times1+0,75\times29+0,75\times30+0,75\times40\)
\(=0,75\times\left(1+29+30+40\right)\)
\(=0,75\times100\)
\(=75\)
4,25 x (X+41,53)-125=53,5
4,25 x (X+41,53)=53,5+125
4,25x(X+41,53)=178,5
X+41,53=178,5:4,25
X+41,53=42
X=42-41,53
X=0,47
vậy...........
a: =20,23(15,75+85,25-1)
=20,23*100
=2023
b: =0,66+3,34+2,8+1,2
=4+4
=8
\(\frac{2006x2005-1}{2004x2006+2005}\)
=\(\frac{2005-1}{2004+2005}\)
=\(\frac{2004}{4009}\)
Lời giải:
$2,5\times 20,23\times 8\times 5=2,5\times 20,23\times 4\times 2\times 5$
$=(2,5\times 4)\times 20,23\times (2\times 5)$
$=10\times 20,23\times 10=20,23\times 100=2023$
\(x\times\dfrac{1}{4}+x\times75\%=20,23\times90+202,3\)
\(x\times\dfrac{1}{4}+x\times\dfrac{3}{4}=20,23\times90+20,23\times10\)
\(x\times\left(\dfrac{1}{4}+\dfrac{3}{4}\right)=20,23\times\left(90+10\right)\)
\(x\times1=20,23\times100\)
\(x=2023\)
X x 1/4+ X x 75% = 20,23 x 90 +202,3
X x 1/4+ X x 3/4 = 2023
X x ( 1/4 +3/4 ) = 2023
X x 1 = 2023
x = 2023