K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
HD
2
24 tháng 3 2019
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}\)
\(\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}\)
\(\Rightarrow\frac{43}{8}+x=\frac{199}{8}\)
\(\Rightarrow x=\frac{199}{8}-\frac{43}{8}\)
\(\Rightarrow x=\frac{156}{8}=\frac{39}{2}\)
KM
24 tháng 3 2019
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)
\(< =>\frac{43}{8}+x-\frac{173}{24}=0\)
\(< =>\frac{43}{8}+x=\frac{173}{24}\)
\(< =>x=\frac{173}{24}-\frac{43}{8}\)
\(< =>x=\frac{11}{6}\)
NT
1
14 tháng 8 2015
\(2-\left(\frac{5}{3}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(\Rightarrow2-\left(\frac{5}{3}+x-\frac{173}{24}\right)=16\frac{2}{3}.0=0\)
\(\Rightarrow\frac{5}{3}+x-\frac{173}{24}=2\)
\(\Rightarrow1\frac{2}{3}+x=2+\frac{173}{24}=9\frac{5}{24}\)
\(\Rightarrow1\frac{2}{3}+x=9\frac{5}{24}\Rightarrow x=9\frac{5}{24}-1\frac{2}{3}\Rightarrow x=\frac{181}{24}=7\frac{13}{24}\)
DP
26 tháng 6 2017
Bài 3 :
\(A=\frac{1}{1\times2}+\frac{1}{2\times3}+....+\frac{1}{99\times100}\)
Ta có : \(\frac{1}{1\times2}=\frac{2-1}{1\times2}=\frac{2}{1\times2}-\frac{1}{1\times2}=1-\frac{1}{2}\)
\(\frac{1}{2\times3}=\frac{3-2}{2\times3}=\frac{3}{2\times3}-\frac{2}{2\times3}=\frac{1}{2}-\frac{1}{3}\)
\(\frac{1}{99\times100}=\frac{100-99}{99\times100}=\frac{100}{99\times100}-\frac{99}{99\times100}=\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}\)
\(A=\frac{99}{100}\)
\(B=\frac{1}{10\times11}+\frac{1}{11\times12}+...+\frac{1}{38\times39}\)
Ta có : \(\frac{1}{10\times11}=\frac{11-10}{10\times11}=\frac{11}{10\times11}-\frac{10}{10\times11}=\frac{1}{10}-\frac{1}{11}\)
\(\frac{1}{11\times12}=\frac{12-11}{11\times12}=\frac{12}{11\times12}-\frac{11}{11\times12}=\frac{1}{11}-\frac{1}{12}\)
\(\frac{1}{38\times39}=\frac{39-38}{38\times39}=\frac{39}{38\times39}-\frac{38}{38\times39}=\frac{1}{38}-\frac{1}{39}\)
\(\frac{1}{39\times40}=\frac{40-39}{39\times40}=\frac{40}{39\times40}-\frac{39}{39\times40}=\frac{1}{39}-\frac{1}{40}\)
\(\Rightarrow B=\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+....+\frac{1}{38}-\frac{1}{39}+\frac{1}{39}-\frac{1}{40}\)
\(B=\frac{1}{10}-\frac{1}{40}\)
\(B=\frac{3}{40}\)
ML
26 tháng 6 2017
3.
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}\)
\(A=\frac{99}{100}\)
\(B=\frac{1}{10.11}+\frac{1}{11.12}+...+\frac{1}{38.39}+\frac{1}{39.40}\)
\(B=\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{38}-\frac{1}{39}+\frac{1}{39}-\frac{1}{40}\)
\(B=\frac{1}{10}-\frac{1}{40}\)
\(B=\frac{3}{40}\)
15 tháng 9 2019
\(\frac{x}{3}=\frac{16}{24}\Rightarrow x.24=16.3\)
\(\Rightarrow x.24=48\)
\(\Rightarrow x=2\)
\(\frac{x}{4}=\frac{9}{x}\Rightarrow x^2=4.9\)
\(\Rightarrow x^2=36\)
\(\Rightarrow x=\pm6\)
Chúc em học tốt
ND
1
25 tháng 11 2016
\(1\frac{2}{24}\times5\frac{2}{5}\times2\times3\frac{7}{9}\times2\)x2/17
\(=\frac{26}{24}\times\frac{27}{5}\times2\times\frac{34}{9}\times2\times\frac{2}{17}\)
\(=\frac{351}{60}\times2\times\frac{34}{9}\times2\times\frac{2}{17}\)
\(=\frac{351}{30}\times\frac{34}{9}\times2\times\frac{2}{17}\)
\(=\frac{5967}{135}\times2\times\frac{2}{17}\)
\(=\frac{11934}{135}\times\frac{2}{17}\)
\(=\frac{2652}{255}\)
31 tháng 7 2017
\(\frac{2}{5}\)x m + 25% x m + m = 16,5
m x ( \(\frac{2}{5}\) + 25% + 1 ) = 16,5
m x \(\frac{33}{20}\)= 16,5
m = 16,5 : \(\frac{33}{20}\)
m = 10
31 tháng 7 2017
\(\frac{24}{400}+50\%+\frac{3}{100}+25\%\)
\(=0,24\%+50\%+0,03\%+25\%\)
\(=50,52\%\)
9 tháng 7 2017
Ta có: \(\frac{3}{4}\)x+\(\frac{x}{5}\)=\(\frac{1}{6}\)
\(\Leftrightarrow\)\(\frac{3x}{4}\)+ \(\frac{x}{5}\)=\(\frac{1}{6}\)
\(\Leftrightarrow\)\(\frac{15x}{20}\)+ \(\frac{4x}{20}\)=\(\frac{1}{6}\)
\(\Leftrightarrow\)\(\frac{19x}{20}\)= \(\frac{1}{6}\)
\(\Leftrightarrow\)19x= \(\frac{1}{6}\)x20
\(\Leftrightarrow\)19x=\(\frac{10}{3}\)\(\Leftrightarrow\)x=\(\frac{10}{57}\)
9 tháng 7 2017
Ta có: x+x=24\(\frac{1}{4}\)
\(\Leftrightarrow\)x+x= 24\(\frac{1}{4}\)- 3\(\frac{1}{2}\)
\(\Leftrightarrow\)2x= \(\frac{83}{4}\)\(\Leftrightarrow\)x= \(\frac{83}{8}\)
N
3
\(\frac{x+24}{16}=\frac{45}{24}\)
<=> \(\frac{\left(x+24\right)x24}{16x45}\)
<=> \(\frac{\left(x+24\right)x24}{720}\)
<=> x+24 = 720 : 24
<=> x+24 = 30
<=> x = 30-24
<=>x = 6
vậy x=6
=>(x+24)x24=45x16
=>(x+24)x24=720
=>x+ 24=30
=>x=6