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E = x^3 - 3x^2 + 7x^2 - 21x - 8x + 24
= x^2 ( x- 3 ) + 7x ( x- 3 ) - 8 ( x- 3 )
= ( x- 3 )(x^2 + 7x - 8 )
= ( x- 3 )[ x^2 + 8x - x - 8 )
= ( x -3 ) [ x(x + 8 ) - ( x + 8 ) ]
= ( x- 3 )( x - 1 )( x + 8)
=a3-3a2+7a2-21a-8a+24
=a2(a-3)+7a(a-3)-8(a-3)
=(a-3)(a2+7a-8)
=(a-3)(a2-a+8a-8)
=(a-3)(a+8)(a-1)
a) \(a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)\)
\(=a^2\left(b-c\right)+b^2\left[\left(c-b\right)-\left(a-b\right)\right]+c^2\left(a-b\right)\)
\(=a^2\left(b-c\right)-b^2\left(b-c\right)-b^2\left(a-b\right)+c^2\left(a-b\right)\)
\(=\left(b-c\right)\left(a^2-b^2\right)-\left(a-b\right)\left(b^2-c^2\right)\)
\(=\left(b-c\right)\left(a-b\right)\left(a+b\right)-\left(a-b\right)\left(b-c\right)\left(b+c\right)\)
\(=\left(b-c\right)\left(a-b\right)\left(a+b-b-c\right)\)
\(=\left(b-c\right)\left(a-b\right)\left(a-c\right)\)
c) \(\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)
\(=\left(x+1\right)\left(x+7\right)\left(x+3\right)\left(x+5\right)+15\)
\(=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\left(1\right)\)
Đặt \(x^2+8x+11=y\)Thay vào (1) ta được
\(\left(y-4\right)\left(y+4\right)+15\)
\(=y^2-16+15\)
\(=y^2-1\)
\(=\left(y-1\right)\left(y+1\right)\)
\(=\left(x^2+8x+10\right)\left(x^2+8x+11\right)\)
<=> [(x + 2)(x + 5)][(x + 3)(x + 4) - 24 = (x2 + 7x + 10) (x2 + 7x + 12) - 24 (1)
đặt x2 + 7x + 11 = t
=> ( 1 ) <=> (t - 1)(t + 1) - 24 = t2 - 1 - 24 = t2 - 25 = (t - 5)(t + 5)
=> (x2 + 7x + 11 - 5) (x2 + 7x + 11 + 5) = (x2 + 7x + 6) (x2 + 7x + 16) (x + 1) (x + 6) (x2 + 7x + 16)
chúc you học tốt!! ^^
ok mk nhé!! 4545454353434636565454676345345346654767567567587676345346334534534565646756
Đặt \(A=\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24\)
\(\Rightarrow A=\left(x+2\right)\left(x+5\right)\left(x+3\right)\left(x+4\right)-24\)
\(=\left(x^2+7x+10\right)\left(x^2+7x+12\right)-24\)
Đặt \(x^2+7x+11=t\)
\(\Rightarrow A=\left(t-1\right)\left(t+1\right)-24=t^2-1-24=t^2-25=\left(t-5\right)\left(t+5\right)\)
\(=\left(x^2+7x+11-5\right)\left(x^2+7x+11+5\right)=\left(x^2+7x+6\right)\left(x^2+7x+16\right)\)
\(=\left(x+1\right)\left(x+6\right)\left(x^2+7x+16\right)\)
\(15a^3+16a^2-29a+2\)
\(=\left(15a^3-15a^2\right)+\left(31a^2-31a\right)-\left(2a-2\right)\)
\(=\left(a-1\right)15a^2+31a\left(a-1\right)-2\left(a-1\right)\)
\(=\left(a-1\right)\left(15a^2+31a-2\right)\)
Ta có:
\(3b^2-4a^4=11ab\)
\(\Leftrightarrow3b^2-11ab-4a^4=0\)
\(\Leftrightarrow\left(3b^2-12ab\right)+\left(ab-4a^4\right)=0\)
\(\Leftrightarrow3b\left(b-4a\right)+a\left(b-4a^3\right)=0\)
mik chỉ biết (x+2)(x+3)(x+4)(x+5)-24=(x+6)(x+1)(x2+7x+16 bằng cách đặt ẩn phụ thui còn lại ko biết sorry nha
\(2^{16}-16=2^{16}-2^4=2^4.\left(2^{12}-1\right)\)
\(=2^4.3^2.5.7.13\)
=> Thừa số lớn nhất là 13.
\(a^3+4a^2-29a+24\)
\(=a^3-a^2+5a^2-5-24a+24\)
\(=a^2\left(a-1\right)+5a\left(a-1\right)-24\left(a-1\right)\)
\(=\left(a-1\right)\left(a^2+5a-24\right)\)
\(=\left(a-1\right)\left(a^2-3a+8a-24\right)\)
\(=\left(a-1\right)\left(a\left(a-3\right)+8\left(a-3\right)\right)\)
\(=\left(a-1\right)\left(a-3\right)\left(a-8\right)\)
ban co hoi thieu mot ti