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a: =x(4x^2+4x+1)
=x(2x+1)^2
b: =(x-y)^2-49
=(x-y-7)(x-y+7)
1, \(4b^2+a^2+4ab=\left(2b+a\right)^2\)
2, \(-49-2a^4+14\sqrt{2}a^2=-\left(2a^4-2.7\sqrt{2}a^2+49\right)=-\left(\sqrt{2}a^2-7\right)^2\)
1: \(a^2+4ab+4b^2=\left(a+2b\right)^2\)
2: \(-49-2a^4+14\sqrt{2a^2}\)
\(=-\left(2a^4-2\cdot\sqrt{2a^2}\cdot7+49\right)\)
\(=-\left(\sqrt{2a^2}-7\right)^2\)
a) Ta có: \(4\left(x-2\right)^2+xy-2y\)
\(=4\left(x-2\right)^2+y\left(x-2\right)\)
\(=\left(x-2\right)\left(4x-8+y\right)\)
b) Ta có: \(x\left(x-y\right)^3-y\left(y-x\right)^2-y^2\left(x-y\right)\)
\(=x\left(x-y\right)^3-y\left(x-y\right)^2-y^2\left(x-y\right)\)
\(=\left(x-y\right)\left[x\left(x-y\right)^2-y\left(x-y\right)-y^2\right]\)
a, x2-x-y2-y = ( x2-y2)-(x+y)=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)
b. x2-2xy+y2-z2= (x-y)2 - z2= (x-y-z)(x-y+z)
Ta thấy:
a) \(x^2-x-y^2-y\)
\(=\left(x^2-y^2\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y-1\right)\)
b) \(x^2-2xy+y^2-z^2\)
\(=\left(x-y\right)^2-z^2\)
\(=\left(x-y+z\right)\left(x-y-z\right)\)
a, \(2xy-x^2+49-y^2=49-\left(x^2-2xy+y^2\right)\)
\(=7^2-\left(x-y\right)^2\)
\(=\left(7-x+y\right)\left(7+x-y\right)\)
b, \(x^3+2x^2+x=x\left(x^2+2x+1\right)=x\left(x+1\right)^2\)
Bài này dễ mà. Chúc bạn học tốt.
a) \(2xy-x^2+49-y^2\)
\(=49-\left(x^2-2xy+y^2\right)\)
\(=49-\left(x-y\right)^2\)
\(=\left(7+x-y\right)\left(7-x+y\right)\)
b) \(x^3+2x^2+x\)
\(=x\left(x^2+2x+1\right)\)
\(=x\left(x+1\right)^2\)
x2 - 49 - 2xy + y2
= x2 - 2xy + y2 - 49
= (x - y)2 - 72
= (x - y + 7)(x - y - 7)