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a) x3-2x2-x+2
=x(x2-1)+2(-x2+1)
=x(x2-1)-2(x2-1)
=(x2-1)(x-2)
b)
x2+6x-y2+9
=x2+6x+9-y2
=(x+3)2-y2
=(x+3-y)(x+3+y)
\(x^2\left(y-z\right)+y^2\left(z-x\right)+z^2\left(x-y\right)\)
\(=x^2\left(y-z\right)+y^2\left(z-y+y-x\right)+z^2\left(x-y\right)\)
\(=x^2\left(y-z\right)+y^2\left(z-y\right)+y^2\left(y-x\right)+z^2\left(x-y\right)\)
\(=\left[x^2\left(y-z\right)-y^2\left(y-z\right)\right]+\left[y^2\left(y-x\right)-z^2\left(y-x\right)\right]\)
\(=\left(x^2-y^2\right)\left(y-z\right)+\left(y^2-z^2\right)\left(y-x\right)\)
\(=\left(x-y\right)\left(x+y\right)\left(y-z\right)+\left(y-z\right)\left(y+z\right)\left(y-x\right)\)
\(=\left(x-y\right)\left(y-z\right)\left[\left(x+y\right)-\left(y+z\right)\right]\)
\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\)
a)x6-y6+
=[(x2)3-(y2)3]+(x4+x2y2+y4)
=[(x2-y2)(x4+x2y2+y4)]+(x4+x2y2+y4)
=(x4+x2y2+y4)[(x2-y2)+1]
=(x2-xy+y2)(x2+xy+y2)(x2-y2+1)
Bạn dặt 3 làm nhân tử chung là xong, dơn giản thui :)))))
k nha!!!!
\(\left(a+b+c\right)^3-a^3-\left(b^3+c^3\right)=\left(b+c\right)\left[\left(a+b+c\right)^2+a\left(a+b+c\right)+a^2\right]-\left(b+c\right)\left(b^2-bc+c^2\right)\)\(=\left(b+c\right)\left(3a^2+3ab+3bc+3ca\right)=3\left(a+b\right)\left(b+c\right)\left(c+a\right)\)