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\(\text{ 2x² + 6x - 8 }\)
\(2\left(x^2+3x-4\right)=2\left(x-1\right)\left(x+4\right)\)
a) x3 + 4x2 – 2x – 8
= (x3 + 4x2) - (2x + 8)
= x2(x + 4) - 2(x + 4)
= (x + 4)(x2 - 2)
= (x + 4)(x + √2)(x - √2)
x^3+x^2-2x-8
= (x-2)(x^2+3x+4)
nah bạn chúc bạn học tốt nha
x3 + x2 - 2x - 8
= ( x3 - 8 ) + ( x2 - 2x )
= ( x - 2 ) . ( x2 + 2x + 4 ) + x ( x - 2 )
= ( x - 2 ) .( x2 + 2x + 4 + x )
= ( x-2 ) . ( x2 + 3x + 4 )
\(x^3-8+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4+2x\right)=\left(x-2\right)\left(x^2+4x+4\right)\\ =\left(x-2\right)\left(x+2\right)^2\)
=\(\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\)
=\(\left(x-2\right)\left(x^2+4x+4\right)\)
=\(\left(x-2\right)\left(x+2\right)^2\)
\(2x^4-8x^3-7x^3+28x^2+7x^2-28x-2x+8\\ =2x^3\left(x-4\right)-7x^2\left(x-4\right)+7x\left(x-4\right)-2\left(x-4\right)\\ =\left(x-4\right)\left(2x^3-7x^2+7x-2\right)\\ =\left(x-4\right)\left(2x^3-4x^2-3x^2+6x+x-2\right)\\ =\left(x-4\right)\left[2x^2\left(x-2\right)-3x\left(x-2\right)+\left(x-2\right)\right]\\ =\left(x-4\right)\left(x-2\right)\left(2x^2-2x-x+1\right)\\ =\left(x-4\right)\left(x-2\right)\left(2x-1\right)\left(x-1\right)\)
\(2x+8=2\left(x+4\right)\)
\(=2\left(x+4\right)\)