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a) 8x2 - 2x - 1
=8x2+2x-4x-1
=2x.(4x+1)-(4x+1)
=(4x+1)(2x-1)
b) x2 - y2 + 10x - 6y + 16
=x2+10x+25-y2-6y-9
=(x+5)2-(y+3)2
=(x+5-y-3)(x+5+y+3)
=(x-y+2)(x+y+8)
a) 8x2-2x-1=8x2+4x-2x-2x-1=(8x2+4x)-(2x+1)=4x.(2x+1)-(2x+1)=(2x+1).(4x-1)
b) x2-y2+10x-6y+16x=x2-y2+10x+10y-16y+16x=(x-y)(x+y)+10(x+y)-16(y+x)=(x+y)(x-y+10+16)
\(x^3+3x^2-4\)
\(=\left(x^3+4x^2\right)-\left(x^2+4\right)\)
\(=\left(x^2+4\right)\left(x-1\right)\)
Mình nhìn nhầm đề
\(x^3+3x^2-4\)
\(=\left(x^3+2x^2\right)+\left(x^2-4\right)\)
\(=x^2\left(x+2\right)+\left(x-2\right)\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2+x-2\right)\)
\(=\left(x+2\right)\left[\left(x^2+x\right)-\left(2x+2\right)\right]\)
\(=\left(x+2\right)\left(x+2\right)\left(x-1\right)\)
\(=\left(x+2\right)^2\left(x-1\right)\)
\(2m^2+10m+8\)
\(=2\left(m^2+5m+4\right)\)
\(=2\left(m^2+4m+m+4\right)\)
\(=2\left(m+4\right)\left(m+1\right)\)
=2m2+8m+2m+8
=(2m2+2m)+(8m+8)
=2m(m+1)+8(m+1)
=(m+1)(2m+8)
=(m+1)2(m+4)
=2(m+1)(m+4)
HT~
\(x^3-4x^2+4x-1\)
\(=x^3-x^2-3x^2+3x+x-1\)
\(=x^2\left(x-1\right)-3x\left(x-1\right)+\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2-3x+1\right)\)
\(10\left(x-y\right)-8y\left(y-x\right)\)
\(=10\left(x-y\right)+8y\left(x-y\right)\)
\(=\left(x-y\right)\left(10+8y\right)\)
\(=2\left(x-y\right)\left(5+4y\right)\)
a) 10(x-y)-8y(y-x)= 10(x-y)+8y(x-y) = (x-y)(10+8y)=2(x-y)(5+4y)
b) Bạn xem lại đầu bài nhé !
\(x^2-y^2+10x-6y+16=\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)(tách 16 thành 25 - 9 xog nhóm vào)
\(=\left(x+5\right)^2-\left(y+3\right)^2=\left(x+5+y+3\right).\left(x+5-y-3\right)\)
\(=\left(x+y+8\right).\left(x-y+2\right)\)
Chúc bạn học tốt .
x^2−y^2+10x−6y+16
=(x^2+10x+25)-(y^2+6y+9)
=(x+5)^2-(y+3)^2
=(x+5+y+3)(x+5-y-3)
=(x+y+8)(x-y+2)