Question

[Thế anh Đào]

Giúp mik với mn ơi mik cần gấp

Answer 1

[TV Cuber]

a)\(=>x=\left(-\dfrac{1}{2}+\dfrac{1}{4}\right):2=-\dfrac{1}{8}\)

Answer 2

[★彡✿ทợท彡★]

a) \(2x-\dfrac{1}{4}=\dfrac{-1}{2}\)

    \(2x=\dfrac{-1}{2}+\dfrac{1}{4}\)

   \(2x=-\dfrac{1}{4}\)

    \(x=-\dfrac{1}{4}\div2\)

    \(x=-\dfrac{1}{8}\)

b) \(\dfrac{13}{3}-\dfrac{1}{3}\cdot\left(x+1\right)=\dfrac{4}{3}\)

              \(\dfrac{1}{3}\cdot\left(x+1\right)=\dfrac{13}{3}-\dfrac{4}{3}\)         

              \(\dfrac{1}{3}\cdot\left(x+1\right)=3\)

                     \(x+1=3\div\dfrac{1}{3}\)

                    \(x+1=9\)

                   \(x=9-1\)

                   \(x=8\)