Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(3x-1\le23\)
\(\Leftrightarrow3x-1+1\le23+1\)
\(\Leftrightarrow3x\le24\)
\(\Leftrightarrow x\le8\)
a,<=>3x<=24
<=>x<=8
Vậy ....
b, <=>4x-8>=9x-3-2x-1
<=>4x-9x+2x>=8-3-1
<=>-3x>=4
<=>x>=-4/3 Vậy ....
a) 3x-7>4x+2
\(\Leftrightarrow3x-4x>2+7\)
\(\Leftrightarrow-x>9\Leftrightarrow x< -9\)
Vậy S={x<9|x\(\in R\)}
b) 2(x-3)<3-5(2x-1)+4x
\(\Leftrightarrow2x-6< 3-10x+5+4x\)
\(\Leftrightarrow2x+10x-4x< 3+5+6\)
\(\Leftrightarrow8x< 14\Leftrightarrow x< \dfrac{7}{4}\)
Vậy S={x<\(\dfrac{7}{4}\)|x\(\in R\)}
c) (x-2)2+x(x-3)<2x(x-3)+1
\(\Leftrightarrow x^2-4x+4+x^2-3x< 2x^2-6x+1\)
\(\Leftrightarrow-x< -3\)
\(\Leftrightarrow x>3\)
Vậy S =\(\left\{x>3|x\in R\right\}\)
d) \(\dfrac{x-1}{3}-x+1>\dfrac{2x-3}{2}\)
\(\Leftrightarrow2x-2-6x+6>6x-9\)
\(\Leftrightarrow-10x>-13\Leftrightarrow x< \dfrac{13}{10}\)
Vậy S=\(\left\{x< \dfrac{13}{10}|x\in R\right\}\)
Biểu diễn tập nghiệm thì bạn tự làm
a: =>2x<=-8
=>x<=-4
b: =>x+5<0
=>x<-5
c: =>2x>8
=>x>4
d: =>3x>=9
=>x>=3
1:
a: 2x-3=5
=>2x=8
=>x=4
b: (x+2)(3x-15)=0
=>(x-5)(x+2)=0
=>x=5 hoặc x=-2
2:
b: 3x-4<5x-6
=>-2x<-2
=>x>1
\(a,2x-6< 0\Leftrightarrow2x>6\Leftrightarrow x>3\)
\(b,5x+2x< 4+25\Leftrightarrow7x< 29\Leftrightarrow x< \frac{29}{7}\)
\(c,-5x+6>8-10+8x\Leftrightarrow-5x-8x>8-10-6\)
\(-13x>-8\Leftrightarrow x< \frac{8}{13}\)
\(d,3x-12\le2-4x\Leftrightarrow3x+4x\le2+12\)
\(\Leftrightarrow7x\le14\Leftrightarrow x\le2\)
\(e,\frac{3\left(x-3\right)}{6}>\frac{2\left(2x-5\right)}{6}+\frac{6}{6}\Rightarrow3x-9>4x-10+6\)
\(\Leftrightarrow3x-4x>-4+9\Leftrightarrow x>-5\)
\(f,3\left(2x-3\right)>1+2\left(2+2x\right)\Leftrightarrow6x-9>1+4+4x\)
\(6x-4x>14\Leftrightarrow2x>14\Leftrightarrow x>7\)
Tự biểu diễn nha!
a)\(\dfrac{x-5}{4}\ge\dfrac{3-2x}{5}\)
\(\Leftrightarrow\dfrac{5x-25}{20}\ge\dfrac{12-8x}{20}\)
\(\Leftrightarrow5x-25\ge12-8x\)
\(\Leftrightarrow5x+8x\ge12+25\)
\(\Leftrightarrow13x\ge37\)
\(\Leftrightarrow x\ge\dfrac{37}{13}\)
b)\(2x\left(6x-1\right)-3< 3x\left(4x+3\right)-5x\)
\(\Leftrightarrow12x^2-2x-3< 12x^2+9x-5x\)
\(\Leftrightarrow12x^2-12x^2-2x-9x+5x< 3\)
\(\Leftrightarrow-6x< 3\)
\(\Leftrightarrow x>-\dfrac{1}{2}\)
c)\(\left|x-4\right|=5-3x\)
\(\Leftrightarrow\left[{}\begin{matrix}5-3x=x-4\\5-3x=4-x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}5+4=x+3x\\5-4=-x+3x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=9\\2x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{1}{2}\end{matrix}\right.\)
p/s: tui làm đúng đề
a.
\(\dfrac{x-5}{4}\ge\dfrac{3-2x}{5}\)
\(\Leftrightarrow5x-25\ge12-8x\)
\(\Leftrightarrow13x\ge37\)
\(\Leftrightarrow x\ge\dfrac{37}{13}\)
0 37 13
b.
\(2x\left(6x-1\right)-3< 3x\left(4x+3\right)-5x\)
\(\Leftrightarrow12x^2-2x-3< 12x^2+9x-5x\)
\(\Leftrightarrow-6x>3\)
\(\Leftrightarrow x< \dfrac{-1}{2}\)
0 -1 2
1:
a: =>3x=6
=>x=2
b: =>4x=16
=>x=4
c: =>4x-6=9-x
=>5x=15
=>x=3
d: =>7x-12=x+6
=>6x=18
=>x=3
2:
a: =>2x<=-8
=>x<=-4
b: =>x+5<0
=>x<-5
c: =>2x>8
=>x>4