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b,\(7^5\)\(.(3x-2^3\)\()=7^6\)
\(3x-2^3\)\(=7^6:7^5=7^1=7\)
\(3x=7+8\)
\(3x=15\)
\(x=15:3\)
\(x=5\)
c,\(96-3(x-5)=57\)
\(3(x-5)=96-57\)
\(3(x-5)=39\)
\(x-5=39:3\)
\(x-5=13\)
\(x=13+5\)
\(x=18\)
d,\([(6x-72):2-84].28=5628\)
\((6x-72):2-84=5628:28\)
\((6x-72):2-84=201\)
\((6x-72):2=201+84\)
\((6x-72):2=285\)
\((6x-72)=285.2\)
\(6x-72=570\)
\(6x=570+72\)
\(6x=642\)
\(x=642:6\)
\(x=107\)
b)
75 . ( 3x - 23 ) = 74 . 72
75 . ( 3x - 8 ) = 76
3x - 8 = 7
3x = 15
x = 5.
Vậy x = 5.
c)
96 - 3( x - 5 ) = 57
3( x - 5 ) = 39
x - 5 = 13
x = 18.
Vậy x = 18.
d)
[ ( 6x - 72 ) : 2 - 84 ] . 28 = 5628
( 6x - 72 ) : 2 - 84 = 201
( 6x - 72 ) : 2 = 285
6x - 72 = 570
6x = 642
x = 107.
Vậy x = 107.
b)75. (3x - 23) = 74 .72
\(3x-8=7^6:7^5\)
\(3x-8=7\)
\(3x=15\)
\(x=5\)
\(\text{c) 96 - 3(x - 5) = 57}\)
\(3.\left(x-5\right)=39\)
\(x-5=13\)
\(x=18\)
\(\text{d) [(6x - 72):2 - 84].28 = 5628}\)
\(\left(6x-72\right):2-84=201\)
\(\left(6x-72\right):2=285\)
\(6x-72=142,5\)
\(6x=214,5\)
\(x=35,75\)
chúc bạn học tốt
Bài 1 :
\(2^x.8=512\)
\(2^x=512:8\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
\(b,\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(c,x^{20}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
\(d,\left(x-3\right)^{10}=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
câu 1 :
10 . 72 - 10 . 5 + 10 + 32
= 10( 72 - 5 + 1 ) + 32
= 10 . 45 + 32
= 450 + 482
câu 2 :
54 : [ 452 - ( 2020 - 20180 . 12019 ) ]
= 54 : [ 2025 - ( 2020 - 1 . 1 ) ]
= 54 : [ 2025 - 2019 ]
= 54 : 6
= 9
B1. 2x + 3 + 22 = 72
=> 2x + 3 + 4 = 72
=> 2x + 3 = 72 - 4
=> 2x + 3 = 68
=> ko có gtri x
B2 : Ta có : A = 1 + 2 + 22 + 23 + 24 + 25 + 26 + ... + 22001 + 22002
= (1 + 2) + (22 + 23 + 24) + (25 + 26 + 27) + ... + (22000 + 22001 + 22002)
= 3 + 22.(1 + 2 + 22) + 25.(1 + 2 + 22 ) + ... + 22000 . (1 + 2 + 22)
= 3 + 22.7 + 25.7 + ... + 22000 . 7
= 3 + (22 + 25 + .... + 22000) . 7
=> Số dư của 7 là 3
Trả lời :......................................
77.................................................
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
a) \(6x-39=6528:28\)
\(6x-39=\frac{1632}{7}\)
\(6x=\frac{1632}{7}+39\)
\(6x=\frac{1905}{7}\)
\(x=\frac{1905}{7}:6\)
\(x=\frac{635}{14}\)
b) \(2^{x+1}+54=86\)
\(2^{x+1}=32\)
\(2x.2^2=32\)
\(2x=8\)
\(x=4\)
c) \(\left|x-18\right|.2^{2018}=2^{2020}\)
\(\left|x-18\right|=2^{2020}:2^{2018}\)
\(\left|x-18\right|=2^{2020-2018}=2^2=4\)
\(\Rightarrow\orbr{\begin{cases}x-18=4\\x-18=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=14\end{cases}}}\)
d) \(6x-36=2^3.3^2\)
\(6x-36=72\)
\(6x=108\)
\(x=18\)
e) \(\left|x-5\right|=8\)
\(\Rightarrow\orbr{\begin{cases}x-5=8\\x-5=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=13\\x=-3\end{cases}}}\)
hok tốt!!