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a) CĂN ký hiệu =v nhé
8 = 2.22 ; x2 -4xy + (2y)2 = (x-2y)2
=> A = 2v2/(x-2y)
b;c tương tự
a) \(\sqrt{25\cdot96}=\sqrt{5^2\cdot2^5\cdot3}=\sqrt{5^2\cdot\left(2^2\right)^2\cdot2\cdot3}\)
\(=20\sqrt{6}\)
b) \(\sqrt{21\cdot75\cdot14}=\sqrt{2\cdot3^2\cdot5^2\cdot7^2}=105\sqrt{2}\)
c) \(y^2\sqrt{x^6\cdot y^8}=\sqrt{x^6\cdot y^4\cdot y^8}=\sqrt{\left(x^3\right)^2\cdot\left(y^6\right)^2}=x^3\cdot y^6\)
hì,giúp bn đc phần a thôi nha!!!
\(a,\sqrt{25.96}=\sqrt{25.16.6}=\sqrt{25}.\sqrt{16}.\sqrt{6}=5.4.\sqrt{6}=20\sqrt{6}\)
=.= hok tốt!!!
a) \(\sqrt{27x^2}=\sqrt{3.\left(3x\right)^2}=\left|3x\right|.\sqrt{3}=3x\sqrt{3}\left(x>0\right)\)
b) \(\sqrt{8xy^2}=\left|y\right|.2\sqrt{2x}=-2y\sqrt{2x}\left(x\ge0,y\le0\right)\)
1) \(x\sqrt{13}=\sqrt{13x^2}\left(x\ge0\right)\)
2) \(x\sqrt{-15x}=-\left|x\right|\sqrt{15x}=-\sqrt{15x^3}\left(x< 0\right)\)
3) \(x\sqrt{2}=-\left|x\right|\sqrt{2}=-\sqrt{2x^2}\left(x\le0\right)\)
\(\frac{1}{x-y}.\sqrt{x^4\left(x^2+y^2-2xy\right)}\)
\(=\frac{1}{x-y}.\sqrt{\left(x^2\right)^2.\left(x-y\right)^2}\)
\(=\frac{1}{x-y}\left(x-y\right)x^2\)
\(=x^2\)
a,\(-\sqrt{10x^2\cdot y\left(3-\sqrt{2}\right)^2}=-\left|x\right|\) \(\cdot\left(3-\sqrt{2}\right)\cdot\sqrt{10y}\)
xet th \(x\ge0\) ta co \(-x\cdot\left(3-\sqrt{2}\right)\sqrt{10y}\)
xet th \(x< 0\) ta có \(x\left(3-\sqrt{2}\right)\sqrt{10y}\)
b,\(\sqrt{3\left(x^2-2xy+y^2\right)}=\) \(\sqrt{3\cdot\left(x-y\right)^2}=\left|x-y\right|\sqrt{3}\)