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a) \(92.4-27=\frac{x+350}{x}+315\)
\(368-27=1+\frac{350}{x}+315\)
\(341=\frac{350}{x}+316\)
\(341-316=\frac{350}{x}\)
\(25=\frac{350}{x}\)
\(25x=350\)
\(x=14\)
b) \(\left(\frac{3}{2}-x\right).\frac{1}{3}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{\frac{3}{2}}{3}-\frac{x}{3}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{1}{2}-\frac{x}{2}-\frac{2}{3}.\left(\frac{1}{2}-x\right)=\frac{1}{3}\)
\(\frac{3}{2}-x-2.\left(\frac{1}{2}-x\right)=1\)
\(\frac{3}{2}-x-1+2x=1\)
\(\frac{1}{2}+x=1\)
\(x=1-\frac{1}{2}\)
\(x=\frac{1}{2}\)
khỏi chép đề nha
a\Câu 1:
200 : ( 15 - x ) = 15 + 5
200 : ( 15 - x ) = 20
15 - x = 200 : 20
15 - x = 10
x = 15 - 10
x = 5
Câu 2:
63 : ( x - 5 ) = 22 -1
63 : ( x - 5 ) = 21
x - 5 = 63 : 21
x - 5 = 3
x = 3 + 5
x = 8
a.
150 + x : 3 = 620 : 4
150 + x : 3 = 155
x : 3 = 155 - 150
x : 3 = 5
x = 5 x 3
x = 15
b.
x * 0,1 = 1/2 -2/5
x * 1/10 = 5/10 - 4/10
x * 1/10 = 1/10
x = 1/10 : 1/10
x = 1
c.
4/9 + 5/9 : x = 1
5/9 : x = 1 - 4/9
5/9 :x = 5/9
x = 5/9 : 5/9
x = 1
1) \(150+x.\frac{1}{3}=155\)
\(\frac{1}{3}x=5\)
\(x=15\)
2) \(x.\frac{1}{10}=\frac{1}{2}-\frac{2}{5}\)
\(\frac{1}{10}x=\frac{5}{10}-\frac{4}{10}\)
\(\frac{1}{10}x=\frac{1}{10}\)
\(x=1\)
3) \(\frac{4}{9}+\frac{9}{5}x=1\)
\(\frac{9}{5}x=\frac{9}{9}-\frac{4}{9}\)
\(\frac{9}{5}x=\frac{5}{9}\)
\(x=1\)
Câu 1:
= 3,45 x ( 123 + 4 - 27 )
= 345
Câu 2:
3 x x = 3,45 : 5
3 x x = 0,69
x= 0,69 : 3 = 0,23
Nhớ k cho mình
câu 2 (3*x)*5 = 3.45
3xx =3,45/5
3xx =0,69
3xx =0,69/3
x =0,23
#)Giải :
Câu 1 :
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\left(x+1\right):2}=\frac{2009}{2011}\)
\(=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x\left(x+1\right)}=2\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{x\left(x+1\right)}\right)\)
\(=2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{x+1}\right)=1-\frac{2}{x+1}=\frac{2009}{2011}\Rightarrow x=2010\)