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15 tháng 8 2017

\(\dfrac{5}{7} *\dfrac{-4}{19}-\dfrac{5*2}{7}*\dfrac{15}{19*2} =\dfrac{5}{7}*(\dfrac{-4}{19}-\dfrac{15}{19}) =\dfrac{5}{7}*(\dfrac{-19}{19})=\dfrac{-5}{7}\)

1: \(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}\right)+\dfrac{16}{15}\left(\dfrac{4}{7}-\dfrac{5}{9}\right)\)

\(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}+\dfrac{4}{7}-\dfrac{5}{9}\right)=0\)

2: \(=\dfrac{29}{9}\left(15+\dfrac{4}{7}-8-\dfrac{1}{7}+\dfrac{15}{7}-\dfrac{1}{7}\right)\)

\(=\dfrac{20}{9}\cdot\left(7\cdot\dfrac{18}{7}\right)=\dfrac{20}{9}\cdot18=40\)

1: \(=-\dfrac{7}{80}\cdot\dfrac{4}{7}-\dfrac{2}{9}:\dfrac{16}{3}+\dfrac{5}{24}\cdot\left(\dfrac{-50+38}{15}\right)^2\)

\(=\dfrac{-1}{20}-\dfrac{2}{9}\cdot\dfrac{3}{16}+\dfrac{5}{24}\cdot\dfrac{16}{25}\)

\(=\dfrac{-1}{20}-\dfrac{1}{24}+\dfrac{2}{15}\)

\(=\dfrac{-6-5+16}{120}=\dfrac{5}{120}=\dfrac{1}{24}\)

2: \(=1500-\left\{10^3-11\cdot\left[49-5\cdot8\right]\right\}\)

\(=1500-\left\{1000-11\cdot9\right\}\)

\(=1500-1000+99=599\)

23 tháng 4 2017

\(\dfrac{4}{7}.\dfrac{89}{5}-\dfrac{4}{5}.\dfrac{82}{7}\)

\(=\dfrac{4}{7}.\dfrac{89}{5}-\dfrac{4}{7}.\dfrac{82}{5}\)

\(=\dfrac{4}{7}.\left(\dfrac{89}{5}-\dfrac{82}{5}\right)\)

\(=\dfrac{4}{7}.\dfrac{7}{5}\)

\(=\dfrac{4}{5}\)

\(\dfrac{5}{7}.\dfrac{-4}{19}+\dfrac{-15}{7}.\dfrac{5}{19}\)

\(=\dfrac{5}{7}.\dfrac{-4}{19}+\dfrac{5}{7}.\dfrac{-15}{19}\)

\(=\dfrac{5}{7}.\left(\dfrac{-4}{19}+\dfrac{-15}{19}\right)\)

\(=\dfrac{5}{7}.\left(-1\right)\)

\(=\dfrac{-5}{7}\)

23 tháng 4 2017

- cảm ơn cậu nha khocroi

25 tháng 4 2017

\(-2\dfrac{1}{4}.\)\(\left(3\dfrac{5}{12}-1\dfrac{2}{9}\right)\)

=\(\dfrac{-9}{4}\).\(\left(\dfrac{41}{12}-\dfrac{11}{9}\right)\)

=\(\dfrac{-9}{4}.\dfrac{41}{12}-\dfrac{-9}{4}.\dfrac{11}{9}\)

=\(\dfrac{-123}{16}-\dfrac{-11}{4}\)

=\(\dfrac{-123}{16}-\dfrac{-44}{16}\)

=\(\dfrac{-79}{16}\)

25 tháng 4 2017

\(\left(-25\%+0,75+\dfrac{7}{12}\right)\div\left(-2\dfrac{1}{8}\right)\)

=\(\left(\dfrac{-1}{4}+\dfrac{3}{4}+\dfrac{7}{12}\right)\div\left(\dfrac{-17}{8}\right)\)

=\(\left(\dfrac{-3}{12}+\dfrac{9}{12}+\dfrac{7}{12}\right).\dfrac{-8}{17}\)

=\(\dfrac{13}{12}.\dfrac{-8}{17}=\dfrac{-26}{51}\)

21 tháng 4 2017

= ( 5/7 + -15/7 ) . ( -4/19 + 5/19 )

=10/7 . 1/19

=10/133

21 tháng 4 2017

sai rùi

8 tháng 4 2017

\(3\dfrac{1}{2}+15\dfrac{4}{9}:\dfrac{26}{7}-2\dfrac{4}{9}:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\dfrac{139}{9}:\dfrac{26}{7}-\dfrac{22}{9}:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\left(\dfrac{139}{9}-\dfrac{22}{9}\right):\dfrac{26}{7}\)

\(=\dfrac{7}{2}+13:\dfrac{26}{7}\)

\(=\dfrac{7}{2}+\dfrac{7}{2}\)

\(=7.\)

8 tháng 4 2017

\(3\dfrac{1}{2}+15\dfrac{4}{9}:\dfrac{26}{7}-2\dfrac{4}{9}:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+\dfrac{139}{9}:\dfrac{26}{7}-\dfrac{22}{9}:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+\left(\dfrac{139}{9}-\dfrac{22}{9}\right):\dfrac{26}{7}\)

=\(\dfrac{7}{2}+13:\dfrac{26}{7}\)

=\(\dfrac{7}{2}+13.\dfrac{7}{26}\)

=\(\dfrac{7}{2}+\dfrac{7}{2}\)

= 7

24 tháng 7 2017

2)

\(2+\dfrac{5}{7}+\left(\dfrac{\dfrac{3}{19}+\dfrac{3}{23}-\dfrac{3}{28}}{\dfrac{5}{19}+\dfrac{5}{23}-\dfrac{5}{28}}\right)\cdot x=\dfrac{20}{7}\\ \left[\dfrac{3\cdot\left(\dfrac{1}{19}+\dfrac{1}{23}-\dfrac{1}{28}\right)}{5\cdot\left(\dfrac{1}{19}+\dfrac{1}{23}-\dfrac{1}{28}\right)}\right]\cdot x=\dfrac{20}{7}-\dfrac{5}{7}-2\\ \dfrac{3}{5}x=\dfrac{15}{7}-2\\ \dfrac{3}{5}x=\dfrac{1}{7}\\ x=\dfrac{5}{21}\)

29 tháng 4 2018

c,

= \(\dfrac{5}{9}.\left(\dfrac{7}{13}+\dfrac{9}{13}+\dfrac{-3}{13}\right)\)

= \(\dfrac{5}{9}.1\)

= \(\dfrac{5}{9}\)

29 tháng 4 2018

a,

= \(\dfrac{1}{3}.\left(\dfrac{4}{5}+\dfrac{6}{5}\right)+\dfrac{-4}{3}\)

= \(\dfrac{1}{3}.\dfrac{10}{5}+\dfrac{-4}{3}\)

= \(\dfrac{2}{3}+\dfrac{-4}{3}\)

= \(\dfrac{-2}{3}\)

1 tháng 8 2017

\(\dfrac{1}{6}.x+\dfrac{1}{10}.x-\dfrac{4}{15}.x+1=0\)

=> \(\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{4}{15}\right).x+1\)= 0

=> \(0.x+1=0\)

=> 0 . x = 0 - 1

=> 0 . x = -1

=> x = 0 : -1

=> x = 0

~ Chúc bạn học giỏi ! ~

1 tháng 8 2017

\(\dfrac{1}{6}x+\dfrac{1}{10}x-\dfrac{4}{15}x+1=0\)

\(\Leftrightarrow\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{4}{15}\right)x+1=0\)

\(\Leftrightarrow0x+1=0\)\(\)

Vì 0x luôn = 0 => 0x + 1 > 0

<=> x \(\in\varnothing\)