Câu hỏi của Đỗ Nguyễn Quỳnh Anh

Question

Bài 2 : Tính bằng cách thuận tiện nhất

a) $\frac{4^{17}x3^4x9^6}{6^{13}}$

b) $\frac{2^{16}+2^8}{2^{13}+2^5}$

headsot96 · Accepted Answer

$a)\frac{4^{17}.3^4.9^6}{6^{13}}=\frac{2^{34}.3^4.3^{12}}{2^{13}.3^{13}}=\frac{2^{21}.3^{16}}{3^{13}}=2^{21}.3^3$

$b)\frac{2^{16}+2^8}{2^{13}+2^5}=\frac{2^8\left(2^8+1\right)}{2^5\left(2^8+1\right)}=\frac{2^3\left(2^8+1\right)}{2^8+1}=2^3=8$

Câu trả lời:

$a)\frac{4^{17}.3^4.9^6}{6^{13}}=\frac{2^{34}.3^4.3^{12}}{2^{13}.3^{13}}=\frac{2^{21}.3^{16}}{3^{13}}=2^{21}.3^3$

$b)\frac{2^{16}+2^8}{2^{13}+2^5}=\frac{2^8\left(2^8+1\right)}{2^5\left(2^8+1\right)}=\frac{2^3\left(2^8+1\right)}{2^8+1}=2^3=8$

Serein · Answer

$a,\frac{4^{17}\times3^4\times9^6}{6^{13}}$

$=\frac{2^{34}\times3^4\times3^{12}}{2^{13}\times3^{13}}$

$=\frac{2^{34}\times3^{16}}{2^{13}\times3^{13}}$

$=2^{21}\times3^3$

$b,\frac{2^{16}+2^8}{2^{13}+2^5}$

$=\frac{2^8\left(2^8+2^0\right)}{2^5\left(2^8+2^0\right)}$

$=\frac{2^8}{2^5}$

$=8$

~Study well~