Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, 7/5 : x + 3/2 = 16/3
7/5 : x = 16/3 - 3/2
7/5 : x = 23/6
x = 7/5 : 23/6
x = 42/115
b, x : 1/5 + 1/7 = 3/5 . 18/21
x : 1/5 + 1/7 = 18/35
x : 1/5 = 18/35 - 1/7
x : 1/5 = 13/35
x = 13/35 . 1/5
x = 13/175
c, x - 1 và 1/3 : 2 = 5/7
x - 4/3 : 2 = 5/7
x - 4/3 = 5/7 . 2
x - 4/3 = 10/7
x = 10/7 + 4/3
x = 58/21
d, x + 2 và 3/5 . 1/6 = 35/36
x + 13/5 . 1/6 = 35/36
x + 13/5 = 35/36 : 1/6
x + 13/5 = 35/6
x = 35/6 - 13/5
x = 97/30
e, ( x + 3/2 ) : 2 = 7/10 + 1/5
( x + 3/2 ) : 2 = 9/10
x + 3/2 = 9/10 . 2
x + 3/2 = 9/5
x = 9/5 - 3/2
x = 3/10
a ) \(3\frac{4}{5}-2\frac{3}{4}:1\frac{1}{8}=\frac{19}{5}-\frac{11}{4}:\frac{9}{8}=\frac{19}{5}-\frac{22}{9}=\frac{61}{45}\)
b ) \(4\frac{5}{7}:1\frac{5}{6}+2\frac{7}{15}.\frac{21}{74}=\frac{33}{7}:\frac{11}{6}+\frac{37}{15}.\frac{21}{74}=\frac{18}{7}+\frac{7}{10}=\frac{229}{70}\)
a) MC :24
\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}=\frac{1\times8+3\times3-7\times2}{24}=\frac{3}{24}=\frac{1}{8}\)
b)MC : 56
\(\frac{3}{14}+\frac{5}{8}-\frac{1}{2}=\frac{3\times4+5\times7-1\times28}{56}=\frac{19}{56}\)
c) MC: 36
\(\frac{1}{4}-\frac{2}{3}-\frac{11}{18}=\frac{1\times9-2\times12-11\times2}{36}=\frac{-37}{36}\)
d) MC: 312
\(\frac{1}{4}+\frac{5}{12}-\frac{1}{13}-\frac{7}{8}=\frac{1\times78+5\times26-1\times24-7\times39}{312}=\frac{-89}{312}\)
Câu b:
\(\frac{21}{8}:\frac{5}{6}+\frac{1}{2}:\frac{5}{6}\)
= \(\frac{63}{20}+\frac{3}{5}\)
= \(\frac{15}{4}\)
\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)
\(\frac{25}{8}:\frac{5}{6}\)
\(\frac{25}{8}.\frac{6}{5}\)
\(\frac{30}{8}\)
1)
a) \(x+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=5\)
\(x+\frac{64}{128}+\frac{32}{128}+\frac{16}{128}+\frac{8}{128}+\frac{4}{128}+\frac{2}{128}+\frac{1}{128}=5\)
\(x+\frac{127}{128}=5\)
\(x=5-\frac{127}{128}=\frac{513}{128}\)
b) \(x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}+\frac{1}{2187}=3\)
\(x+\frac{729}{2187}+\frac{243}{2187}+\frac{81}{2187}+\frac{27}{2187}+\frac{9}{2187}+\frac{3}{2187}+\frac{1}{2187}=3\)
\(x+\frac{2186}{2187}=3\)
\(x=3-\frac{2186}{2187}=\frac{4375}{2187}\)
2)
a) \(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}=\frac{5}{6}\)
b) \(5\frac{1}{2}+3\frac{5}{6}+\frac{2}{3}\)
\(=\left(5+3\right)+\left(\frac{1}{2}+\frac{2}{3}+\frac{5}{6}\right)\)
\(=8+\left(\frac{3}{6}+\frac{4}{6}+\frac{5}{6}\right)\)
\(=8+2=10\)
c) \(7\frac{7}{8}+1\frac{4}{6}+3\frac{3}{5}\)
\(=\left(7+1+3\right)+\left(\frac{7}{8}+\frac{2}{3}+\frac{3}{5}\right)\)
\(=11+\left(\frac{105}{120}+\frac{80}{120}+\frac{72}{120}\right)\)
\(=11+\frac{257}{120}=\frac{1577}{120}\)
3) Gọi số đó là x. Theo đề ta có :
\(\frac{16-x}{21+x}=\frac{5}{7}\)
\(7\left(16-x\right)=5\left(21+x\right)\)
\(112-7x=105+5x\)
\(112-105=7x-5x\)
\(7=2x\)
\(x=\frac{7}{2}=3,5\) ( vô lí )
Vậy không có số tự nhiên để thõa mãn điều kiện trên.
Tại cô giáo chưa dậy đến đã giao bài về nhà nên mình mới không biết làm !!!
\(a,2\frac{1}{18}+3\frac{5}{6}+1\frac{2}{3}\)
\(=2+\frac{1}{18}+3+\frac{5}{6}+1+\frac{2}{3}\)
\(=(2+3+1)+(\frac{1}{18}+\frac{5}{6}+\frac{2}{3})\)
\(=6+(\frac{1}{18}+\frac{15}{18}+\frac{12}{18})\)
\(=6+\frac{28}{18}\)
\(=6+\frac{14}{9}=7\frac{5}{9}=\frac{68}{9}\)
\(b,5\frac{3}{7}+(2\frac{5}{21}-1\frac{2}{3})\)
\(=5+\frac{3}{7}+2+\frac{5}{21}-1-\frac{2}{3}\)
\(=(5+2-1)+(\frac{3}{7}+\frac{5}{21}-\frac{2}{3})\)
\(=6+(\frac{9}{21}+\frac{5}{21}-\frac{14}{21})\)
\(=6+0=6\)
Chúc bạn học tốt
a) \(2\frac{1}{8}+3\frac{5}{6}+1\frac{2}{3}\)
\(=2\frac{3}{24}+3\frac{20}{24}+1\frac{16}{24}\)
\(=\left(2+3+1\right)+\frac{3+20+16}{24}\)
\(=6+\frac{13}{8}\)
\(=7\frac{5}{8}=\frac{61}{8}\)
b)\(5\frac{3}{7}+\left(2\frac{5}{21}-1\frac{2}{3}\right)\)
\(=5\frac{9}{21}+\left(2\frac{5}{21}-1\frac{14}{21}\right)\)
\(=5\frac{9}{21}+2\frac{5}{21}-1-\frac{14}{21}\)
\(=\left(5+2-1\right)+\frac{9+5-14}{21}\)
\(=6+0=6\)