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\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+....+\frac{1}{x.\left(x+2\right)}=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{x.\left(x+2\right)}\right)=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(1-\frac{1}{x+2}\right)=\frac{20}{41}\)
\(\Rightarrow1-\frac{1}{x+2}=\frac{20}{41}:\frac{1}{2}\)
\(\Rightarrow1-\frac{1}{x+2}=\frac{40}{41}\)
\(\Rightarrow\frac{1}{x+2}=1-\frac{40}{41}=\frac{1}{41}\)
=> x + 2 = 41
=> x = 39
bạn nguễn đăng khôi có thể làm có cả biểu thức a,b,c được ko
a)10+2(x+1)=20
2(x+1)=20-10
2(x+1)=10
(x+1)=10/2
x+1=5
x=5-1
x=4
a) 2115 : x = 21
=> x = 2115 : 21 = \(\frac{705}{7}\) ( sai đề )
b) \(\left(9\times x-21\right):3=2\)
=> \(\left(9\times x-21\right)=2\times3=6\)
=> \(9\times x=6+21=27\)
=> \(x=27:9=3\)
Vậy x = 3
c) 231 + ( 312 - x ) = 531
=> 231 + 312 - x = 531
=>. 543 - x = 531
=> x = 543 - 531 = 12
Vậy x = 12
a) 2115 : x = 21
x= 705/7
b) ( 9 * x - 21) : 3 = 2
9 * x - 21 = 6
9 * x = 27
x = 3
c) 231 + ( 312 - x) = 531
231 + 312 - x = 531
543 - x = 531
x =12
Bai 1 :
a/ \(x:1,4+2,8=8,4\)
\(x:1,4=8,4-2,8\)
\(x:1,4=5,6\)
\(x=5,6\times1,4\)
\(x=7,84\)
b/ \(2,8:x-1,5=2,3:5,75\)
\(2,8:x-1,5=\frac{2}{5}\)
\(2,8:x=\frac{2}{5}+1,5\)
\(2,8:x=\frac{19}{10}=1,9\)
\(\Rightarrow x=2,8:1,9=\frac{28}{19}\)
Bai 2 :
a/ \(575-\left(6\times x+70\right)=445\)
\(6\times x+70=575-445\)
\(6\times x+70=130\)
\(6\times x=130-70\)
\(\Rightarrow6\times x=60\Rightarrow x=10\)
b/ \(315+\left(125-x\right)=435\)
\(125-x=435-315\)
\(125-x=120\)
\(\Rightarrow x=5\)
c/ \(\left(x-105\right):21=15\)
\(x-105=15\times21\)
\(x-105=315\)
\(\Rightarrow x=420\)
d/ \(3636:\left(12\times x-91\right)=36\)
\(12\times x-91=3636:36\)
\(12\times x-91=101\)
\(12\times x=101+91\)
\(12\times x=192\)
\(\Rightarrow x=16\)
e/ \(12\times\left(x-5\right)+73=20\)
\(12\times\left(x-5\right)=20-73\)
\(12\times\left(x-5\right)=-53\)
\(x-5=-53:12\)
\(x-5=\frac{-53}{12}\)
\(\Rightarrow x=\frac{-53}{12}+5\)
\(\Rightarrow x=\frac{7}{12}\)
f/ \(\left[\left(10-x\right)\times2+5\right]:3-2=3\)
\(\left[\left(10-x\right)\times2+5\right]:3=3+2\)
\(\left[\left(10-x\right)\times2+5\right]:3=5\)
\(\left[\left(10-x\right)\times2+5\right]=5\times3\)
\(\left(10-x\right)\times2+5=15\)
\(\left(10-x\right)\times2=15-5\)
\(\left(10-x\right)\times2=10\)
\(10-x=10:2\)
\(10-x=5\)
\(\Rightarrow x=5\)
Tất cả dùng nhân chéo
a.3x=2.54=>x=36
b.15x=60=>x=4
c.2/3=4/6=>x=5
d.x=5;4(câu này ss từng phần)
x * 3 +x * 10 + x * 21 + 36 * x + x * 30 = 190
x * ( 3 + 10 + 21 + 36 + 30 ) = 190
x * 100 = 190
x = 190 : 100
x = 1,9
a, 3x X +122=21
\(3xX=21-122\)
\(3xX=-101\)
\(X=-101:3\)
\(X=-\frac{101}{3}\)
b,(36-X):2=10
\(36-X=10x2\)
\(36-X=20\)
\(X=36-20\)
\(X=16\)
c, 36-X:2 = 10
\(36-X:2=10\)
\(X:2=36-10\)
\(X:2=26\)
\(X=26x2\)
\(X=52\)
a.3xX+122=21
3xX =21-122
3xX =-101
X =-101:3
X =\(\frac{-101}{3}\)