Question

[Trần Quốc Dương]

a,\(\frac{-6}{21}.\frac{3}{2}\)

b,\(\left\{-3\right\}.\left\{\frac{-7}{12}\right\}\)

c,\(\left\{\frac{11}{12}:\frac{33}{16}\right\}.\frac{3}{5}\)

d,\(\sqrt{\left\{-7\right\}^2}+\sqrt{\frac{2}{16}}-\frac{3}{2}\)

e,\(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left\{\frac{1}{3}\right\}^0\)

Answer 1

[Vũ Cao Minh⁀ᶦᵈᵒᶫ ( ✎﹏IDΣΛ亗 )]

a) \(\frac{-6}{21}.\frac{3}{2}=-\frac{3}{7}\)          b) \(\left(-3\right).\left(\frac{-7}{12}\right)=\frac{21}{12}=\frac{7}{4}\)

c) \(\left(\frac{11}{12}:\frac{33}{16}\right).\frac{3}{5}=\frac{11}{12}.\frac{16}{33}.\frac{3}{5}=\frac{4}{15}\)

d) \(\sqrt{\left(-7\right)^2}+\sqrt{\frac{2}{16}}=7+\sqrt{\frac{1}{8}}\)

c) \(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0=\frac{1}{2}.10-\frac{1}{4}+1=5\frac{3}{4}\)