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a, = 2^30.3^30.3^11.7-2^31.5.3^40
= 2^30.3^41.7-2^31.5.3^40
= 2^30.3^40.(3.7-2.5) = 2^30.3^40.11
b, = 2^28.17.3^38-2^27.3^27.3^11
= 2^28.17.3^38-2^27.3^38
= 2^27.3^38.(2.17-1) = 2^27.3^38.33
k mk nha
k) \(2x-49=5.3^2\)
\(2x-49=45\)
\(2x=49+45\)
\(2x=94\)
\(x=47\)
l) \(3^2.\left(x+14\right)-5^2=5.2^2\)
\(9.\left(x+14\right)-25=20\)
\(9.\left(x+14\right)=45\)
\(x+14=5\)
\(x=-9\)
m) \(6x+x=5^{11}:5^9+3^1\)
\(7x=5^{11-9}+3\)
\(7x=5^2+3\)
\(7x=28\)
\(x=4\)
n) \(7x-x=5^{21}:5^{19}+3.2^2-\left(-7^{-0}\right)\)
\(6x=5^{21-19}+12-1\)
\(6x=5^2+11\)
\(6x=36\)
\(x=6\)
o) \(7x-2x=6^{17}:6^{15}+44:11\)
\(5x=6^{17-15}+4\)
\(5x=6^2+4\)
\(5x=40\)
\(x=8\)
o)7x-x=521:519+3.22-70
=> 6x = 5^2 + 12 -1
=> 6x = 36
=> x = 36/6 = 6
Kết quả 6
Học tốt
a,\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right).\left(-5\right)^{20}}{\left(-5\right)^{20}.3^{10}.3^2}\)\(=\frac{-5}{3^2}\)
b,\(\frac{-11^5.13^7}{11^5.13^8}=\frac{-11^5.13^7}{\left(-11\right)^5.\left(-1\right)^5.13^7.13}\)\(=\frac{1}{-1^5.13}\)
\(\frac{3^{10}.\left(-5\right)^{21}}{\cdot\left(-5\right)^{20}.3^{12}}=\frac{\left(-5\right)}{3^2}=\frac{-5}{9}\)
\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=\frac{-1}{13}\)