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\(a,1⋮\left(x+7\right)\)
\(\Rightarrow x+7\inƯ\left(1\right)=\left\{\pm1\right\}\)
Ta lập bảng xét giá trị
| x+7 | 1 | -1 |
| x | -6 | -8 |
\(b,4⋮x-5\)
\(x-5\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
Ta lập bảng xét giá trị
| x-5 | 1 | -1 | 2 | -2 | 4 | -4 |
| x | 6 | -4 | 7 | 3 | 9 | 1 |
a)\(\left(x-1\right)^3=8\)
\(\Leftrightarrow\left(x-1\right)^3=\left(2\right)^3\)
\(\Leftrightarrow x-1=2\)
\(\Leftrightarrow x=3\)
b)\(2^{x+2}-2^x=96\)
\(\Leftrightarrow2^x.2^2-2^x=96\)
\(\Leftrightarrow2^x\left(2^2-1\right)=96\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Leftrightarrow x=5\)
c)\(\left(2x+1\right)^3=343\)
\(\Leftrightarrow\left(2x+1\right)^3=7^3\)
\(\Leftrightarrow\left(2x+1\right)=7\)
\(\Leftrightarrow x=3\)
d)\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Leftrightarrow720:\left[46-2x\right]=40\)
\(\Leftrightarrow46-2x=18\)
\(\Leftrightarrow2x=28\)
\(\Leftrightarrow x=14\)
a) x = 17
b) x = 23
c) x = 63
d) x = 2499
e) x = -3
j) x = 3
g) x = 7
h) x = 3
a/\(\left|x-1\right|=-10-3\)
\(\Leftrightarrow[\frac{x-1=-13}{x-1=13}\)
\(\Leftrightarrow[\frac{x=-13+1}{x=13+1}\)
\(\Leftrightarrow[\frac{x=-12}{x=14}\)
\(\Rightarrow x=\left\{-12;14\right\}\)
Vậy \(x=\left\{-12;14\right\}\)
b/ \(\left|x\right|-1=?\)
c/ \(3^{2x-3}-2\times5^2=5^2\times3\)
\(9^{x-3}-2=3\)
\(9^x\div9^3-2=3\)
\(9^x\div9^3=5\)
\(9^x=5\times9^3\)
\(9^x=3645\)
\(\Rightarrow x\in\varnothing\)
Vậy \(x\in\varnothing\)
d/ \(3^{2x-4}-x^0=8\)
\(9^x\div9^4-1=8\)( x0 =1 vì mọi lũy thừa mũ 0 đều bằng 1 )
\(9^x\div9^4=9\)
\(9^x=9\times9^4\)
\(9^x=9^5\)
\(x=5\)
Vậy \(x=5\)
Nhiều câu quá >.<
a/ \(2x\left(x+5\right)=\left(x+3\right)^2+\left(x-1\right)^2+20.\)
\(2x^2+10x=x^2+6x+9+x^2-2x+1+20.\)
\(10x=4x+30\)
\(6x=30\Rightarrow x=5\)
các câu còn lại tương tự
\(a,2x\left(x+5\right)=\left(x+3\right)^2+\left(x-1\right)^2+20\)
\(\Leftrightarrow2x^2+10x=x^2+6x+9+x^2-2x+1+20\)
\(\Leftrightarrow2x^2+10x=2x^2+4x+30\)
\(\Leftrightarrow2x^2+10x-2x^2-4x=30\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=5\)
Vậy ...........
\(b,\left(2x-2\right)^2=\left(x+1\right)^2+3\left(x-2\right)\left(x+5\right)\)
\(\Leftrightarrow4x^2-8x+4=x^2+2x+1+3x^2+15x-6x-30\)
\(\Leftrightarrow4x^2-8x+4=4x^2+11x-29\)
\(\Leftrightarrow4x^2-8x-4x^2-11x=-29-4\)
\(\Leftrightarrow-19x=-33\)
\(\Leftrightarrow x=\frac{33}{19}\)
Vậy...........
\(c,\left(x-1\right)^2+\left(x+3\right)^2=2\left(x-2\right)\left(x+1\right)+38\)
\(\Leftrightarrow x^2-2x+1+x^2+6x+9=2x^2+2x-4x-4+38\)
\(\Leftrightarrow2x^2+4x+10=2x^2-2x+34\)
\(\Leftrightarrow2x^2+4x-2x^2+2x=34-10\)
\(\Leftrightarrow6x=24\)
\(\Leftrightarrow x=4\)
Vậy.............
\(d,\left(x+2\right)^3-\left(x-2\right)^3=12x\left(x-1\right)-18\)
\(\Leftrightarrow x^3+6x+12x+8-\left(x^3-6x+12x-8\right)=12x^2-12x-8\)
\(\Leftrightarrow x^3+6x+12x+8-x^3+6x-12x+8=12x^2-12x-8\)
\(\Leftrightarrow12x=-24\)
\(\Leftrightarrow x=-2\)
Vậy............