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mình thiếu 1 câu hhi
b) {( 10 - 2 . 3 ) .5] + 2 -2 . 6 } : 2 + ( 4 . 5 ) 2
a) (3x-24)73=2.74
3x-24=2.7 (Chia cả hai vế cho 73)
3x-16=14
3x=30
X=10
b)[(10 -x).2+5] : 3 -2 =3
(20-2x+5):3=5
25-2x=15
2x=10
X=5
Bài 2
{[(32+1).10-(8:2+6)]:2}+55-(10:5)3
={(9+1).10-10]:2}+55-23
=[(10.10-10):2]+55-8
=(90:2)+55-8
=45+55-8
=100-8
=92
1) (96 + 97) : 95
=96:95+97:95
=5 + 52
=5+25
=30
2) .......(tự chép đè nhé)....
4A = 4 x 42 x 43 x 44 +...+ 420 + 421
4A - A = 421 - 4
3A = 421- 4
A = (421 - 4 ) : 3
bài này mình làm rùi , yên tâm.
k nha
Ai giúp nguyen phan thu ngan
thì hãy cho mình 1 k
cảm ơn các bjan nhìu!!
a)
\(A=\frac{6^3+3.6^3+3^3}{-13}=\frac{3^3.2^3+3^3.2^2+3^3}{-13}=\frac{3^3\left(8+4+1\right)}{-13}=\frac{27.13}{-13}=-27\)
b)
A=1+5+52+53+...+550
5A=5+52+53+...551
5A-A=(5+52+53+...+551)-(1+5+52+...+550)
4A=551-1
A=\(\frac{5^{51}-1}{4}\)
c)
A=2100-299+298-...+22-2
2A=2101-2100+299-...+23-22
2A+A=(2101-2100+...+23-22)+(2100-299+...+22-2)
3A=2101-2
A=\(\frac{2^{101}-2}{3}\)
b.
\(A=1+5+5^2+5^3+...+5^{49}+5^{50}\)
\(5A=5+5^2+5^3+...+5^{50}+5^{51}\)
\(5A-A=\left(5+5^2+5^3+...+5^{50}+5^{51}\right)-\left(1+5+5^2+..+5^{50}\right)\)
\(4A=5^{51}-1\)
\(A=\frac{5^{51}-1}{4}\)
a. 52 + (x+3) = 52
=> x + 3 = 52 - 52
=> x + 3 = 0
=> x = -3
b. 23 + (x-32) = 53 - 43
=> 8 + (x-9) = 125 - 64
=> x - 9 = 125 - 64 - 8
=> x - 9 = 53
=> x = 53 + 9
=> x = 62
a)5x-2 - 32 = 24 - ( 28 * 24- 210 * 22 )
=> 5x-2-32=16
=> 5x-2=25
=> (5x)2=25
=> 5x=5
=> x=1
b) ( 3 * x - 24 ) * 73 = 8 * 74
=> (3.x-16)=8.74:73
=> 3x-16=56
=> 3x=72
=> x=24
c) x15 = x
=> x15:x=1
=> x14=1
=> x=1
d) ( x - 5 )4 =( x - 5 )6
=> (x-5)6:(x-5)4=1
=> (x-5)2=1
=> x-5=1
=> x=6
Bài 1 tự làm!
Bài 2:
a, \(\left(3x-4\right)\left(x-1\right)^3=0\Rightarrow\left[{}\begin{matrix}3x-4=0\\\left(x-1\right)^3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=1\end{matrix}\right.\)
b, \(2^{2x-1}:4=8^3\Rightarrow2^{2x-1}:2^2=2^9\)
\(\Rightarrow2x-1-2=9\Rightarrow2x-3=9\Rightarrow2x-12\Rightarrow x=6\)
c, Đề chưa rõ
d, \(\left(x+2\right)^5=2^{10}\Rightarrow\left(x+2\right)^5=4^5\Rightarrow x+2=4\Rightarrow x=2\)
e, \(\left(3x-2^4\right).7^3=2.7^4\Rightarrow3x-2^4=2.7^4:7^3\Rightarrow3x-16=2.7=14\)
\(\Rightarrow3x=14+16=30\Rightarrow x=\dfrac{30}{3}=10\)
f, \(\left(x+1\right)^2=\left(x+1\right)^0\Rightarrow\left(x+1\right)^2=1\) (vì x0 = 1)
\(\Rightarrow x+1=1\Rightarrow x=0\)
Bài 1 :
a/ \(a^3.a^9=a^{3+9}=a^{12}\)
b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)
c/ \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)
d/ \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)
e/ \(5^6:5^3+3^3.3^2\)
\(=5^3+3^5=125+243=368\)
i/ \(4.5^2-2.3^2\)
\(=2^2.5^2-2.3^2\)
\(=2^2.25-2^2.14\)
\(=2^2.\left(25-14\right)\)
\(=2^2.11\)
\(=4.11=44\)
a)
\(\dfrac{7}{5}+\dfrac{5}{6}:5-\dfrac{3}{8}\cdot\left(-3\right)\\ =\dfrac{7}{5}+\dfrac{1}{6}+\dfrac{9}{8}\\ =\dfrac{168+20+135}{120}\\ =\dfrac{323}{120}\)