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a)410x220x830 b)56x53+32x33
=(22)10x220x(23)30 =56+3+32+3
=220x220x290 =59+35
=220+20+90 =1953125+243
=2130 =1953368.
c)13+23+33+43+53 d)225:324
=1+8+27+64+125 =225 :(25)4
=9+27+64+125 =225:220
=36+64+125 =225-20
=100+125 =25
=225
a)\(\left(2^2\right)^{10}.2^{20}.\left(2^3\right)^{30}=2^{20}.2^{20}.2^{90}=2^{130}\)
b)\(5^{6+3}+3^{2+3}=5^9+3^5\)
c)\(1^3+2^3+3^3+4^3+5^3=\left(1+2+3+4+5\right)^2=15^2=225\)
d)\(2^{25}:32^4=2^{25}:\left(2^5\right)^4=2^{25}:2^{20}=2^{25-20}=2^5=32\)
a)A=\(\frac{\left(8+100\right).\left[\left(100-8\right):4+1\right]}{2}=\frac{108.242}{2}=13068\)
b) \(5B=5^2+5^3+...+5^{101}\)
\(5B-B=5^{101}-5\)
\(B=\frac{5^{101}-5}{4}\)
a. \(3.5^2+15.2^2-26:2\)
\(=3.25+15.4-26:2\)
\(=75+60-13\)
\(=122\)
b. \(5^3.2-100:4+2^3.5\)
\(=125.2-100:4+8.5\)
\(=250-25+40\)
\(=265\)
c. \(6^2:9+50.2-3^3.3\)
\(=36:9+50.2-27.3\)
\(=4+100-81\)
\(=23\)
d. \(3^2.5+2^3.10-81:3\)
\(=9.5+8.10-81:3\)
\(=45+80-27\)
\(=98\)
e. \(5^{13}:5^{10}-25.2^2\)
\(=5^3-25.4\)
\(=125-100\)
\(=25\)
f. \(20:2^2+5^9:5^8\)
\(=20:4+5\)
\(=5+5=10\)
Bài 1:
a) 12.18 + 14.3 - 255 : 17
= 216 + 42 - 15
= 258 - 15
= 243
b) 15.8 - (83 - 30 + 17) - 144 : 6
= 15.8 - (53 + 17) - 144 : 6
= 15.8 - 70 - 144 : 6
= 120 - 70 - 144 : 6
= 120 - 70 - 24
= 50 - 24
= 26
c) 24.(15 + 30 + 85 - 120) : 10
= 24.(45 + 85 - 120) : 10
= 24.(130 - 120) : 10
= 24.10 : 10
= 24.1
= 24
d) 15 - 25.8 : (100.2)
= 15 - 25.8 : 200
= 15 - 200 : 200
= 15 - 1
= 14
e) 32.5 - 22.7 + 1.5
= 9.5 - 4.7 + 1.5
= 45 - 28 + 5
= 17 + 5
= 22
g) (24.5 - 52.2) : (5.2) - 3
= (24.5 - 25.2) : (5.2) - 3
= (120 - 50) : 10 - 3
= 70 : 10 - 3
= 7 - 3
= 4
h) [(52.23 - 72.2) : 2].6 - 7.25
= [(25.8 - 49.2) : 2].6 - 7.32
= [(200 - 98) : 2].6 - 224
= [102 : 2].6 -224
= 51.6 - 224
= 306 - 224
= 82
i) 27 : 22 + 54 : 53.24 - 3.25
= 25 + 5.24 - 3.25
= 32 + 5.16 - 3.32
= 32 + 80 - 96
= 112 - 96
= 16
k) (37.35) : 310 + 5.24 - 73 : 7
= 312 : 310 + 5.24 - 72
= 32 + 5.24 - 72
= 9 + 5.16 - 49
= 9 + 80 - 49
= 89 - 49
= 40
Bài 2:
a) 547 + 389 + 453 + 211
= (547 + 453) + (389 + 211)
= 1000 + 600
= 1600
b) 125.98.2.8.25
= (125.8).(25.2.98)
= 1000.4900
= 4900000
c) 8466.15 + 170.4233
= 4233.2.15 + 170.4233
= 4233.30 + 170.4233
= 4233.(30 + 170)
= 4233. 200
= 846600
d) (62007 - 62006) : 62006
= 62007 : 62006 - 62006 : 62006
= 6 - 1
= 5
e) (112003 + 112002) : 112002
= 112003 : 112002 + 112002 : 112002
= 11 + 1
= 12
f) 4.24.52 - (33.18 + 33.12)
= 4.24.25 - [33.(18 + 12)]
= 4.25.24 - [27.30]
= 100.24 - 810
= 2400 - 810
= 1590
g) 23.7.53- (52.65 + 52.35)
= 8.7.125 - (25.65 + 25.35)
= 8.125.7 - [25.(65 + 35)]
= 1000.7 - [25.100]
= 7000 - 2500
= 4500
Xin lỗi nha, nhìu quá mk lm ko hết, thông cảm cho mk.
2.Gọi số cần tìm là \(x\left(x\ne0,x>9\right)\)
Ta có:
\(53=mx+2\left(m\in N\right)\\ \Rightarrow51=mx\\ \Rightarrow x\inƯ\left(51\right)\left(1\right)\\ 77=nx+9\left(n\in N\right)\\ \Rightarrow68=nx\\ \Rightarrow x\inƯ\left(68\right)\left(2\right)\)
Từ (1) và (2) ta có:
\(x\inƯC\left(51,68\right)\)
\(51=3\cdot17\\ 68=2^2\cdot17\\ \Rightarrow\text{ƯCLN}\left(51,68\right)=17\\ ƯC\left(51,68\right)=Ư\left(17\right)=\left\{1;17\right\}\)
Vì x > 9 nên x = 17
Vậy số chia là 17
3. Làm câu b trước, các câu kia trả lời tương tự hoặc áp dụng điều đã chứng minh
b,
\(a+a^2+a^3+a^4+...+a^{29}+a^{30}\\ =\left(a+a^2\right)+\left(a^3+a^4\right)+...+\left(a^{29}+a^{30}\right)\\ =a\left(1+a\right)+a^3\left(1+a\right)+...+a^{29}\left(1+a\right)\\ =\left(1+a\right)\left(a+a^3+...+a^{29}\right)⋮a+1\)
Vậy \(a+a^2+a^3+a^4+...+a^{29}+a^{30}⋮a+1\) với a thuộc N
1.
a. Ta có: \(A=2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
\(B=3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
Mà \(8^{100}< 9^{100}\)
\(\Rightarrow A< B\)
b. Ta có: \(A=2^{332}< 2^{333}=2^{3.111}=\left(2^3\right)^{111}=8^{111}\)
\(B=3^{223}>3^{222}=3^{2.111}=\left(3^2\right)^{111}=9^{111}\)
Mà \(8^{111}< 9^{111}\)
\(\Rightarrow A< B\)
c. Ta có: \(A=2^{91}=2^{13.7}=\left(2^{13}\right)^7=8192^7\)
\(B=5^{35}=5^{5.7}=\left(5^5\right)^7=3125^7\)
Mà \(8192^7>3125^7\)
\(\Rightarrow A>B\)
Câu 2:
a: =>(x-6)(x-7)=0
=>x=6 hoặc x=7
b: =>\(x^8\left(x^2-25\right)=0\)
\(\Leftrightarrow x^8\left(x-5\right)\left(x+5\right)=0\)
hay \(x\in\left\{0;5;-5\right\}\)
\(3A=3+3^2+3^3+...+3^{21}\\ 2A=3^{21}-1\\ A=\dfrac{3^{21}-1}{2}\\ 5B=5^2+5^3+...+5^{11}\\ 4B=5^{11}-5\\ B=\dfrac{5^{11}-5}{4}\\ 2C=2^5+2^6+...+2^{31}\\ C=2^{31}-2^4\)
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