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8 tháng 8 2017
1) 2x2-8xy-5x+20y
=2x(x-4y)-5(x-4y)
=(2x-5)(x-4y)
2) x3-x2y-xy+y2
=x2(x-y)-y(x-y)
=(x2-y)(x-y)
3) x2-2xy-4z2+y2
=(x-y)2-(2z)2
=(x-y-2z)(x-y+2z)
4) a3+a2b-a2c-abc
=a2(a+b)-ac(a+b)
=(a2-ac)(a+b)
=a(a-c)(a+b)
5) x3+y3+3x2y+3xy2-x-y
=(x+y)(x2-xy+y2)+3xy(x+y)-(x+y)
=(x+y)(x2-xy+y2+3xy-1)
=(x+y)[(x+y)2-1)]
=(x+y)(x+y+1)(x+y-1)
6) x3+x2y-x2z-xyz
=x2(x+y)-xz(x+y)
=(x2-xz)(x+y)
=x(x-z)(x+y)
7) =[x(y+z)2-2xyz]+[y(z+x)2-2xyz]+z(x+y)2
=x(y2+z2)+y(z2+x2)+z(x+y)2
=xy(x+y)+z2(x+y)+z(x+y)2
=(x+y)(xy+z2+zx+zy)
=(x+y)(x+z)(y+z)
8) x3(z-y)+y3(x-z)+z3(y-x)
Tách x-z= -[z-y+y-x]
8 tháng 8 2017
1, 2x2 - 8xy - 5x + 20y
= (2x2 - 5x) - (8xy - 20y)
= x(2x - 5) - 4y(2x - 5)
= (2x - 5) (x - 4y)
2, x3 - x2y - xy + y2
= (x3 - xy) - (x2y - y2)
= x(x2 - y) - y(x2 - y)
= (x2 - y) (x - y)
3, x2 - 2xy - 4z2 + y2
= (x2 - 2xy + y2) - 4z2
= (x - y)2 - (2z)2
= (x - y - 2z) (x - y + 2z)
4, a3 + a2b - a2c - abc
= (a3 - a2c) + (a2b - abc)
= a2(a - c) + ab(a - c)
= (a - c) (a2 + ab)
5, x3 + y3 + 3x2y + 3xy2 - x - y
= (x3 + 3x2y + 3xy2 + y3) - (x + y)
= (x + y) 3 - (x + y)
= (x + y) [(x + y)2 - 1]
= (x + y) (x + y - 1) (x + y + 1)
PT
11 tháng 9 2018
a) \(A=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)
\(A=x^2+2x+y^2-2y-2xy+37\)
\(A=\left(x^2-2xy+y^2\right)+\left(2x-2y\right)+37\)
\(A=\left(x-y\right)^2+2\left(x-y\right)+37\)
\(A=\left(x-y\right)^2+2\left(x-y\right)+1+36\)
\(A=\left(x-y+1\right)^2+36\)
Thay x - y = 7 vào A
\(A=\left(7+1\right)^2+36\)
\(A=8^2+36\)
\(A=64+36\)
\(A=100\)
b) \(B=x^3+x^2-y^3+y^2+xy-3x^2y+3xy^2-3xy-9\)
\(B=\left(x^3-3x^2y+3xy^2-y^3\right)+\left(x^2+xy-3xy+y^2\right)-9\)
\(B=\left(x-y\right)^3+\left(x^2-2xy+y^2\right)-9\)
\(B=\left(x-y\right)^3+\left(x-y\right)^2-9\)
Thay x - y = 7 vào B
\(B=7^3+7^2-9\)
\(B=343+49-9\)
\(B=383\)
c) \(C=x^3-x^2-y^3-y^2-3xy\left(x-y\right)+2xy\)
\(C=\left[x^3-y^3-3xy\left(x-y\right)\right]-\left(x^2-2xy+y^2\right)\)
\(C=\left(x-y\right)^3-\left(x-y\right)^2\)
Thay x - y = 7 vào C
\(C=7^3-7^2\)
\(C=343-49\)
\(C=294\)
d) \(D=x^2\left(x+1\right)-y^2\left(y-1\right)+xy-3xy\left(x-y+1\right)-95\)
\(D=x^3+x^2-y^3+y^2+xy-3x^2y+3xy^2-3xy-95\)
\(D=\left(x^3-3x^2y+3xy^2-y^3\right)+\left(x^2-2xy+y^2\right)-95\)
\(D=\left(x-y\right)^3+\left(x-y\right)^2-95\)
Thay x - y = 7 vào D
\(D=7^3+7^2-95\)
\(D=343+49-95\)
\(D=297\)
27 tháng 11 2022
a: \(=\dfrac{4x^2+4x+1-4x^2+4x-1}{\left(2x+1\right)\left(2x-1\right)}\cdot\dfrac{5\left(2x-1\right)}{4x}\)
\(=\dfrac{8x\cdot5}{4x\left(2x+1\right)}=\dfrac{10}{2x+1}\)
b: \(=\left(\dfrac{1}{x^2+1}+\dfrac{x-2}{x+1}\right):\dfrac{1+x^2-2x}{x}\)
\(=\dfrac{x+1+x^3+x-2x^2-2}{\left(x+1\right)\left(x^2+1\right)}\cdot\dfrac{x}{\left(x-1\right)^2}\)
\(=\dfrac{x^3-2x^2+2x-1}{\left(x+1\right)\left(x^2+1\right)}\cdot\dfrac{x}{\left(x-1\right)^2}\)
\(=\dfrac{\left(x-1\right)\left(x^2-x+1\right)}{\left(x+1\right)\left(x^2+1\right)}\cdot\dfrac{x}{\left(x-1\right)^2}\)
\(=\dfrac{x\left(x^2-x+1\right)}{\left(x^2-1\right)\left(x^2+1\right)}\)
c: \(=\dfrac{1}{x-1}-\dfrac{x^3-x}{x^2+1}\cdot\left(\dfrac{1}{\left(x-1\right)^2}-\dfrac{1}{\left(x-1\right)\left(x+1\right)}\right)\)
\(=\dfrac{1}{x-1}-\dfrac{x\left(x-1\right)\left(x+1\right)}{x^2+1}\cdot\dfrac{x+1-x+1}{\left(x-1\right)^2\cdot\left(x+1\right)}\)
\(=\dfrac{1}{x-1}-\dfrac{x}{x^2+1}\cdot\dfrac{2}{\left(x-1\right)}\)
\(=\dfrac{x^2+1-2x}{\left(x-1\right)\left(x^2+1\right)}=\dfrac{x-1}{x^2+1}\)
YN
24 tháng 10 2021
\(x^2-3x+xy-3y\)
\(=\left(x^2+xy\right)-\left(3x+3y\right)\)
\(=x.\left(x+y\right)-3.\left(x+y\right)\)
\(=\left(x-3\right).\left(x+y\right)\)
\(2x^2-x+2xy-y\)
\(=2x^2-\left(x-2xy+y\right)\)
\(=2x^2-\left(x-y\right)^2\)
\(=\left(\sqrt{2}x\right)^2-\left(x-y\right)^2\)
\(=\left(\sqrt{2}x-x+y\right).\left(\sqrt{2}x+x-y\right)\)
\(x^4+x^3+2x^2+x+1\)
\(=\left(x^4+2x^2+1\right)+\left(x^3+x\right)\)
\(=\left(x^2+1\right)^2+x.\left(x^2+1\right)\)
\(=\left(x^2+1\right).\left(x^2+1+x\right)\)
\(16+2xy-x^2-y^2\)
\(=16-x^2+2xy-y^2\)
\(=16-\left(x^2-2xy+y^2\right)\)
\(=4^2-\left(x-y\right)^2\)
\(=[4-\left(x-y\right)].[4+\left(x-y\right)]\)
\(=\left(4-x+y\right).\left(4+x-y\right)\)
23 tháng 5 2022
1: \(=x^2+6x+9-y^2\)
\(=\left(x+3\right)^2-y^2\)
\(=\left(x+3+y\right)\left(x+3-y\right)\)
2: \(x^2-2xy+y^2-25\)
\(=\left(x-y\right)^2-25\)
\(=\left(x-5-y\right)\left(x+5-y\right)\)
4: \(=y\left(x-y\right)-5\left(x-y\right)=\left(x-y\right)\left(y-5\right)\)
5: \(=x^3\left(x+3\right)-9\left(x+3\right)\)
\(=\left(x+3\right)\left(x^3-9\right)\)
XO
15 tháng 9 2020
A = x3 + 3x2 + 3x - 899
= (x3 + 3x2 + 3x + 1) - 900
= (x + 1)3 - 900
= (29 + 1)3 - 900 = 303 - 900 = 26100
B = x3 - 6x2 + 12x + 10
= (x3 - 6x2 + 12x - 8) + 18
= (x - 2)3 + 18
= (12 - 2)3 + 18 = 103 + 18 = 1000 + 18 = 1018
c) C = 8x3 - 27y3
= (2x)3 - (3y)3
= (2x - 3y)(4x2 + 6xy + 9y2)
= (2x - 3y)(4x2 - 12xy + 9y2) + (2x - 3y).18xy
= (2x - 3y)(2x - 3y)2 + (2x - 3y).18xy
= (2x - 3y)3 + (2x - 3y).18xy
= 53 + 5.18.4
= 125 - 360
= -235
D = x3 + y3 + 3xy(x2 + y2) + 6x2y2(x + y)
= (x + y)(x2 - xy + y2) + 3x3y + 3xy3 + 6x2y2
= x2 + y2 - xy + 3x3y + 3xy3 + 6x2y2
= (x + y)2 - 3xy + 3x3y + 3xy3 + 6x2y2
= 1 - 3xy(2xy - 1) + 3xy(x2 + y2)
= 1 - 3xy(x2 + y2 + 2xy - 1)
= 1 - 3xy[(x + y)2 - 1]
= 1 - 0 = 1
`@` `\text {Ans}`
`\downarrow`
`a,`
`-1/2xy^2*3x^3y`
`= (-1/2*3)(x*x^3)(y^2*y)`
`= -3/2x^4y^3`
`b,`
`(xy)^2*(-3xy^2z)`
`= (-3)(x^2*x)(y^2*y^2)(z)`
`= -3x^3y^4z`
`c,`
`(2xy)*(-1/4x^2)*y^3`
`= (2*-1/4)(x*x^2)(y*y^3)`
`= -1/2x^3y^4`
a: =-1/2*3*x^3*x*y^2*y=-3/2x^4y^3
b: =x^2y^2*(-3)xy^2z=-3x^3y^4z
c: =2*(-1/4)*xy*x^2*y^3=-1/2x^3y^4