Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
bài 1
a, X/Y x 1/5=3/10
X/Y=3/10:1/5
X/Y=3/2
b, 3/4 x X/Y= 6/5
X/Y=3/4:6/5
X/Y=5/8
Bài 2:
a, > b, < c,= d,<
a/\(x-\dfrac{5}{7}-\dfrac{13}{14}=1\)
\(x=1+\dfrac{5}{7}+\dfrac{13}{14}\)
\(x=\dfrac{14}{14}+\dfrac{10}{14}+\dfrac{13}{14}\)
\(x=\dfrac{37}{14}\)
Vậy \(x=\dfrac{37}{14}\)
b/\(\dfrac{3}{5}+x+1\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+\dfrac{3}{5}+\dfrac{6}{5}=\dfrac{11}{3}\)
\(x+\dfrac{9}{5}=\dfrac{11}{3}\)
\(x=\dfrac{11}{3}-\dfrac{9}{5}\)
\(x=\dfrac{55}{15}-\dfrac{27}{15}\)
\(x=\dfrac{28}{15}\)
Vậy \(x=\dfrac{28}{15}\)
#kễnh
a) \(x-\dfrac{5}{7}-\dfrac{13}{14}=1\)
\(x-\dfrac{23}{14}=1\)
\(x=1+\dfrac{23}{14}\)
\(x=\dfrac{37}{14}\)
b) \(\dfrac{3}{5}+x+1\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+1+\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+\dfrac{9}{5}=\dfrac{11}{3}\)
\(x=\dfrac{11}{3}-\dfrac{9}{5}\)
\(x=\dfrac{28}{15}\)
a)\(\frac{21}{11}.\frac{22}{17}.\frac{68}{63}=\frac{21.22.68}{11.17.63}=\frac{21.2.11.4.17}{11.17.3.21}=\frac{\left(11.17.21\right)2.4}{\left(11.17.21\right).3}=\frac{2.4}{3}=\frac{8}{3}\)
b)\(\frac{5}{14}.\frac{7}{13}.\frac{26}{25}=\frac{5.7.26}{14.13.25}=\frac{5.7.13.2}{7.2.13.5.5}=\frac{\left(5.7.13\right).2}{\left(5.7.13\right).2.5}=\frac{2}{2.5}=\frac{1}{5}\)
Ta có \(x.\frac{7}{8}-x.\frac{3}{4}=\frac{2}{3}\)
\(\Rightarrow x.\left(\frac{7}{8}-\frac{3}{4}\right)=\frac{2}{3}\)
\(\Rightarrow x.\frac{1}{8}=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}.8\)
\(\Rightarrow x=\frac{16}{3}\)
'x' là dấu nhân đúng không cậu?
uk