K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
PT
0
29 tháng 4 2015
a.11/7.8/13+8/13.3/7+8/13
=8/13.(11/7+3/7+1)
=8/13.3
=24/13
b.5/7.8/13+8/13.9/7-8/13
=8/13.(5/7+9/7-1)
=8/13.1
=8/13
c.157.199-56.199-199
=199.(157-56-1)
=199.100
19900
S
5 tháng 3 2017
a) \(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}\)
\(=\frac{4}{5}\times\frac{1}{4}\)
\(=\frac{4}{20}=\frac{1}{5}\)
\(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}=\frac{1}{5}\times\frac{1}{4}+\frac{3}{5}\times\frac{1}{4}\)
\(=\frac{1}{20}+\frac{3}{20}\)
\(=\frac{4}{20}=\frac{1}{5}\)
b) \(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}\)
\(=\frac{5}{9}\times\frac{3}{2}\)
\(=\frac{15}{18}=\frac{5}{6}\)
\(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}=\frac{7}{9}\times\frac{3}{2}-\frac{2}{9}\times\frac{3}{2}\)
\(=\frac{21}{18}-\frac{6}{18}\)
\(=\frac{15}{18}=\frac{5}{6}\)
c) \(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}\)
\(=\frac{2}{13}\times\frac{39}{21}\)
\(=\frac{78}{273}=\frac{2}{7}\)
\(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}=\frac{11}{13}\times\frac{39}{21}-\frac{9}{13}\times\frac{39}{21}\)
\(=\frac{429}{273}-\frac{351}{273}\)
\(=\frac{78}{273}=\frac{2}{7}\)
DV
5 tháng 3 2017
a,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4}{20}\)
=\(\frac{1}{5}\)
,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4x1}{5x4}\)
=\(\frac{1x1}{5x1}\)
=\(\frac{1}{5}\)
H
27 tháng 1 2023
\(\dfrac{9}{2}+\dfrac{6}{13}+\dfrac{5}{8}-\dfrac{7}{2}+\dfrac{3}{8}-\dfrac{5}{13}\\ =\left(\dfrac{9}{2}-\dfrac{7}{2}\right)+\left(\dfrac{6}{13}-\dfrac{5}{13}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)\\ =\dfrac{2}{2}+\dfrac{1}{13}+\dfrac{8}{8}\\ =1+1+\dfrac{1}{13}\\ =2+\dfrac{1}{13}\\ =\dfrac{2.13+1}{13}\\ =\dfrac{27}{13}\)
27 tháng 1 2023
\(\dfrac{9}{2}\)+\(\dfrac{6}{13}\)+\(\dfrac{5}{8}\)-\(\dfrac{7}{2}\)+\(\dfrac{3}{8}\)-\(\dfrac{5}{13}\)
=(\(\dfrac{9}{2}\) -\(\dfrac{7}{2}\))+(\(\dfrac{6}{13}\)-\(\dfrac{5}{13}\))+(\(\dfrac{5}{8}\)+\(\dfrac{3}{8}\))
= 1 + \(\dfrac{1}{13}\) + 1
= (1 + 1)+\(\dfrac{1}{13}\)
= 2 +\(\dfrac{1}{13}\)
= \(\dfrac{26}{13}\) +\(\dfrac{1}{13}\)
= \(\dfrac{27}{13}\)
NT
2
27 tháng 8 2020
\(A=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}+\frac{2}{11\cdot13}+\frac{2}{13\cdot15}\)
\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}=1-\frac{1}{15}=\frac{14}{15}\)
NC
27 tháng 8 2020
Bài làm:
Ta có: \(A=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(A=1-\frac{1}{15}\)
\(A=\frac{14}{15}\)
2 tháng 3 2020
Ta có :
\(\frac{5}{9}\times\frac{2}{7}=\frac{10}{63};\frac{2}{3}+\frac{5}{6}=\frac{3}{2}\) \(5-\frac{13}{17}=\frac{72}{17};\frac{9}{11}:\frac{5}{13}=\frac{117}{55}\)
\(5+\frac{9}{14}=\frac{79}{14};\frac{6}{54}:8=\frac{1}{72}\) \(\frac{24}{72}-\frac{202}{909}=\frac{1}{9};\frac{9}{11}:\frac{5}{13}=\frac{117}{55}\)
Học tốt nha !
#Sơn#
2 tháng 3 2020
5/9\(\times\)2/7=10/63
2/3+5/6=4/6+5/6=9/6=3/2
5+9/14=70/14+9/14=79/14
6/54:8=1/9:8=1/9\(\times\)1/8=1/72
5-13/17=85/17-13/17=72/17
3:9/10=3\(\times\)10/9=30/9=10/3
24/72-202/909=1/9
9/11:5/13=9/11\(\times\)13/5=117/55
O
19 tháng 4 2019
Câu 1
a)\(\frac{35}{8}\);\(\frac{21}{8}\);\(\frac{13}{13}\);\(\frac{9}{15}\);\(\frac{7}{15}\)
b)\(\frac{35}{8}\);\(\frac{21}{8}\);\(\frac{13}{13}\);\(\frac{9}{15}\);\(\frac{7}{15}\)
c)\(\frac{35}{8}\);\(\frac{21}{8}\);\(\frac{13}{13}\);\(\frac{9}{15}\);\(\frac{7}{15}\)
14 tháng 6 2018
\(\frac{5}{7}+\frac{7}{13}+\frac{19}{13}+\frac{6}{5}+\frac{9}{7}+\)\(\frac{9}{5}\)
\(=\left(\frac{5}{7}+\frac{9}{7}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{6}{5}+\frac{9}{5}\right)\)
\(=2+2+3\)
\(=7\)
14 tháng 6 2018
a, 5/7+7/13+19/13+6/5+9/7+9/5
= (5/7 + 9/7) + ( 7/13 + 19/13) + ( 6/5 + 9/5)
= 2 + 2 + 3
= 7
\(=\dfrac{5}{9}\cdot\left(-\dfrac{2}{13}+\dfrac{-7}{13}\right)-\dfrac{8}{13}=\dfrac{5}{9}\cdot\dfrac{-9}{13}-\dfrac{8}{13}=-\dfrac{5}{13}-\dfrac{8}{13}=-\dfrac{13}{13}=-1\)
\(\dfrac{5}{9}\cdot\dfrac{-2}{13}+\dfrac{5}{9}\cdot\dfrac{-7}{13}+\dfrac{-8}{13}=\dfrac{5}{9}\cdot\left(\dfrac{-2}{13}+\dfrac{-7}{13}\right)-\dfrac{8}{13}=\dfrac{5}{9}\cdot\dfrac{-9}{13}-\dfrac{8}{13}=\dfrac{-5}{13}-\dfrac{8}{13}=\dfrac{-13}{13}=-1\)