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\(\left(125^{100}.2^{160}\right):\left(5^{289}.4^{80}\right)\)\(=\frac{\left(5^3\right)^{100}.2^{100}}{5^{289}.\left(2^2\right)^{80}}\)\(=\frac{5^{300}.2^{100}}{5^{289}.2^{160}}\)\(=\frac{5^{11}}{2^{60}}\)
\(\left(9^8.5^8\right):\left(3^7.27^3.5^4\right)\)\(=\frac{\left(3^2\right)^8.5^8}{3^7.\left(3^3\right)^3.5^4}=\frac{3^{16}.5^4}{3^7.3^9}=\frac{3^{16}.5^4}{3^{16}}=5^4=625\)
\(\left(1024.27^8\right):\left(2^9.3^{23}\right)=\frac{2^{10}.\left(3^3\right)^8}{2^9.3^{23}}=\frac{2.3^{24}}{3^{23}}=2.3=6\)
\(\left(625.2^7+25^2.64\right):\left(2^6.5^4.3\right)=\frac{25^2.128+25^2.64}{2^6.\left(5^2\right)^2.3}=\frac{25^2.\left(128+64\right)}{64.25^2.3}=\frac{192}{192}=1\)
a,\(3^3.3^2-3^5+5^8.1-5^{12}:5^4\)
=\(3^5-3^5+5^8-5^8\)
=0
9!-8!-7! :\(8^2\)
=8!.9-8!-8!.8
=8!.(9-1-8)
=8!.0
=0
xin lỗi nha mình ko đọc được => mình cũng không trả lời được, bạn cho chữ to lên đi.
bn ra đề như vậy kết quả toàn số to thôi mà cũng ko lấy xấp xỉ đc nữa
Đặt \(A=5+5^3+5^5+....+5^{47}+5^{49}\)
\(\Rightarrow5^2A=5^3+5^5+5^7+.....+5^{49}+5^{51}\)
\(\Rightarrow5^2A-A=\left(5^3+5^5+5^7+....+5^{49}+5^{51}\right)-\left(3+3^3+3^5+....+5^{47}+5^{49}\right)\)
\(\Rightarrow24A=5^{51}-5\)
\(\Rightarrow A=\dfrac{5^{51}-5}{24}\)
Vậy ............................................................
1)a) \(\left(3x-7\right)^5=32\Rightarrow\left(3x-7\right)^5=2^5\)
\(\Rightarrow3x-7=2\Rightarrow3x=9\Rightarrow x=3\)
Vậy \(x=3\)
b) \(\left(4x-1\right)^3=-27.125\)
\(\Rightarrow\left(4x-1\right)^3=-3^3.5^3=-15^3\)
\(\Rightarrow4x-1=-15\Rightarrow4x=-14\Rightarrow x=-3,5\)
Vậy \(x=-3,5\)
c) \(3^{4x+4}=81^{x+3}\Rightarrow3^{4x+4}=3^{4x+12}\)
\(\Rightarrow4x+4=4x+12\)
\(\Rightarrow4x=4x+8\)
\(\Rightarrow x\in\varnothing\)
d) \(\left(x-5\right)^7=\left(x-5\right)^9\)
\(\Rightarrow\left(x-5\right)^7-\left(x-5\right)^9=0\)
\(\Rightarrow\left(x-5\right)^7.\left[1-\left(x-5\right)^2\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(x-5\right)^7=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x-5=-1\\x-5=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=4\\x=6\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=5\\x=4\\x=6\end{matrix}\right.\)
Bài này mk vừa học xong nè :
a) 23.46.162 = 23.(22)6.(24)2 = 23.212.28 = 223.
b) 86 : 23 = (23)6 : 23 = 218 : 23 = 215.
c) 273 : 33 = (33)3 : 33 = 39 : 33 = 36.
d) 153 : 53 = (3.5)3 : 53 = 33.
e) 510.1254 = 510.(53)4 = 510.512 = 510+12 = 522.
g) 75.492 = 75.(72)2 = 75.74 = 78.
Nếu thấy đúng thì k mk nha.
a) \(2^3.4^6.16^2=2^3.\left(2^2\right)^6.\left(2^4\right)^2=2^3.2^{12}.2^8=2^{23}\)
b)\(8^6:2^3=\left(2^3\right)^6:2^3=2^{18}:2^3=2^{15}\)
c)\(27^3:3^3=\left(27:3\right)^3=9^3=729\)
d)\(15^3:5^3=\left(15:5\right)^3=3^3=27\)
e)\(5^{10}:125^4=5^{10}:\left(5^3\right)^4=5^{10}:5^{12}=5^{-2}=\frac{1}{5^2}=\frac{1}{25}\)
g)\(7^5.49^2=7^5.\left(7^2\right)^2=7^5.7^4=7^9\)