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4. \(\frac{64^3.36^2}{16^4.18^5}=\frac{\left(2^6\right)^3.\left(2^2.3^2\right)^2}{\left(2^4\right)^4.\left(2.3^2\right)^5}=\frac{2^{18}.\left(2^2\right)^2.\left(3^2\right)^2}{2^{16}.2^5.\left(3^2\right)^5}\)
\(=\frac{2^{18}.2^4.3^4}{2^{16}.2^5.3^{10}}=\frac{2^{22}.3^4}{2^{21}.3^{10}}=\frac{2}{3^6}\)
5. \(\frac{34^{18}.68^{24}}{17^{30}.2^{16}}=\frac{\left(2.17\right)^{18}.\left(2^2.17\right)^{24}}{17^{30}.2^{16}}=\frac{2^{18}.17^{18}.\left(2^2\right)^{24}.17^{24}}{17^{30}.2^{16}}\)
\(=\frac{2^{18}.17^{18}.2^{48}.17^{24}}{17^{30}.2^{16}}=\) \(\frac{2^{66}.17^{42}}{17^{30}.2^{16}}=2^{50}.17^{12}\)
a) \(\frac{16.64.8^2}{4^3.2^5.16}=\frac{16.4^3.\left(2^3\right)^2}{4^3.2^5.16}=\frac{16.4^3.2^6}{4^3.2^5.16}=2\)
\(\frac{64^2.81^3.34}{2^{13}.3^9.17}=\frac{\left(2^6\right)^2.\left(3^4\right)^3.2.17}{2^{13}.3^9.17}=\frac{2^{13}.3^{12}.17}{2^{13}.3^9.17}=3^3=27\)
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Bạn kiểm tra lại giùm mình đi nha:
15.37.4+120.21+21.5.12 16.64+76.34
=15.37.4+(6.7).4.(5.3)+(3.5).(7.3).4 =
=15.37.4+42.4.15+15.21.4
=15.4.(37+42+21)
=60.100
=6000
=>x^2-6x+9=\(\frac{4\left(4^{16}+16\right)}{4^{16}+16}\)
=>x^2-6x+9=4
=>x^2-6x+5=0
=>(x^2-x)-(5x-5)=0
=>x(x-1)-5(x-1)=0
=>(x-1)(x-5)=0
=>\(\orbr{\begin{cases}x-1=0\\x-5=0\end{cases}}\)
=>\(\orbr{\begin{cases}x=1\\x=5\end{cases}}\)
vậy x=1;x=5
4^2 . 120 - 64 . 17 + 16 . 34
=16 . 120 - 64 . 17 + 16 . 34
=16.(120+34)-64.17
=16.154-64.17
=2464-1088
=1376