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Dễ mà ^_^: 3x2-7x+2=3x2 -x-6x+2=(3x2-x)-(6x-2)=x(3x-1)-2(3x-1)=(3x-1)(x-2)
Ta có : \(M=\left(x^2+3x+2\right)\left(x^2+7x+12\right)+1=\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)+1\)
\(=\left[\left(x+1\right)\left(x+4\right)\right].\left[\left(x+2\right)\left(x+3\right)\right]+1=\left(x^2+5x+4\right)\left(x^2+5x+6\right)+1\)
Đặt \(t=x^2+5x+5\) \(\Rightarrow M=\left(t-1\right)\left(t+1\right)+1=t^2-1+1=t^2\)
Vậy \(M=\left(x^2+5x+5\right)^2\)
\(a.=x^3-2x^2+x^2-2x+x-2=x^2\left(x-2\right)+x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(x^2+x+2\right)\)
b.\(=2x^3+x^2-2x^2-x-2x-1=x^2\left(2x+1\right)-x\left(2x-1\right)-\left(2x-1\right)\)\(=\left(2x-1\right)\left(x^2-x-1\right)\)
c.\(3x^3-x^2+6x^2-2x-12x+4=x^2\left(3x-1\right)+2x\left(3x-1\right)-4\left(3x-1\right)\)\(=\left(3x-1\right)\left(x^2+2x-4\right)\)
d.\(3x^3-x^2-6x^2+2x+15x-5=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)\(=\left(3x-1\right)\left(x^2-2x+5\right)\)
t i c k cho mình nha
\(x^2\left(x+1\right)-\left(x+1\right)\left(3x+1\right)+7x-x^2\)
\(=x^3+x^2-3x^2-4x-1+7x-x^2\)
\(=x^3-3x^2+3x-1\)
\(=\left(x-1\right)^3\)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
\(3x^3-7x^2+17x-5.\)
\(=3x^3-x^2-6x^2+2x-15x+5\)
\(=\left(3x^3-x^2\right)-\left(6x^2-2x\right)-\left(15x-5\right)\)
\(=x^2\left(3x-1\right)-2x\left(3x-1\right)-5\left(3x-1\right)\)
\(=\left(3x-1\right)\left(x^2-2x-5\right)\)
7x2 - 28 = 7(x2 - 4) = 7(x - 2)(x + 2)
2x3 + 3x2 - 18x - 27 = x2(2x + 3) - 9(2x + 3) = (2x + 3)(x2 - 9) = (2x + 3)(x - 3)(x + 3)
B= 2x^2+2x+3x+3
= 2x(x+1)+3(x+1)
=(x+1)( 2x+3)
C=3x^2-6x-x+2
=3x(x-2)-(x-2)
=(x-2)(3x-1)
\(3x^2+7x+2\)
\(=3x^2+6x+x+2\)
\(=3x\left(x+2\right)+\left(x+2\right)\)
\(=\left(3x+1\right)\left(x+2\right)\)
\(3x^2+7x+2\)
\(=3x^2+x+6x+2\)
\(=x\left(3x+1\right)+2\left(3x+1\right)\)
\(=\left(3x+1\right).\left(x+2\right)\)