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a,5x +5x+2=650
5x + 5x.52=650
5x(1+25)=650
5x.26=650
5x=25
x=2
các câu b,c,d,e,f tương tự
câu g, x=1 hoặc x=0
câu h, x-1=1 hoặc x-1=0
\(\Rightarrow\)x=2 hoặc x=1
câu i tương tự câu h
câu k,33x+2=9x+3
33x+2=(32)x+3
33x+2=32x+3
3x+2=2x+3
x=4
câu i, 53x+2=25x+7 tương tự câu k
k cho mk nhé thanks..^_^
a)x10=1x
=>x10=1
=>x=-1,1
b)(x-3)5=(x-3)8
=>(x-3)8-(x-3)5=0
=>(x-3)5.[(x-3)3-1]=0
=>(x-3)5=0=>x-3=0=>x=3
hoặc (x-3)3-1=0=>(x-3)3=1=>x-3=1=>x=4
Vậy x=3,4
c)2x+3.3+5.2x=928
=>2x.23.3+5.2x=928
=>2x.8.3+5.2x=928
=>2x.24+5.2x=928
=>2x.(24+5)=928
=>2x.29=928
=>2x=928:29
=>2x=32=25
=>x=5
7x-x =521: 519. 3.22-70
=>6x =521: 519+3.22-70
=> 6x = 52 + 3.4-1
=> 6x =25+3.2-1
=> 6x = 25+6-1
=> 6x = 30
=> x = 30:6
=> x = 5
a)9x-1=9
9x-1=91
x-1=1
x=2
Vây x=2
b)7x-x=521:519+3.22-70
6x=52+12-1
6x=25+11
6x=36
x=6
Vậy x=6
\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
9\(^{x-1}\)=3\(^4\) 9\(^{x-1}\)=9\(^2\) suy ra:x-1=2 x=1+2 x=3
x\(^2\)+7\(^0\)=5\(^{21}\):5\(^{19}\)+3x2\(^2\) x\(^2\)+1=5\(^2\)+3x4 x\(^2\)+1=25+12 x\(^2\)+1=37 x\(^2\)=37-1 x\(^2\)=36 x\(^2\)=6\(^2\)hoặc x\(^2\)=(-6)\(^2\) suy ra x=6 hoặc x=-6
2x+5 - 3.2x = 928
2x.32 - 3.2x = 928
2x.(32-3) = 928
2x. 29 = 928
2x = 32= 25
=> x = 5
2x+5-3.2x=928
2x.25-3.2x=928
2x.(25-3)=928
2x.(32-3)=928
2x.29 =928
2x =928:29
2x =32
2x =25
=> x=5
hok tot nhe!