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a) \(2^{x+1}=8^2\)
\(2^{x+1}=\left(2^3\right)^2\)
\(2^{x+1}=2^6\)
\(\Rightarrow x+1=6\)
\(x=5\)
b) \(5^{x-1}=25^2\)
\(5^{x-1}=\left(5^2\right)^2\)
\(5^{x-1}=5^4\)
\(\Rightarrow x-1=4\)
\(x=5\)
a) Ta có : \(2^{x+1}=8^2\Rightarrow2^x.2=\left(2^3\right)^2\Rightarrow2^x=2^6:2\Rightarrow2^x=\) \(2^5\) \(\Rightarrow x=5\)
b) \(5^{x-1}=25^2\Rightarrow5^x:5=\left(5^2\right)^2\Rightarrow5^x:5=5^4\Rightarrow5^x=5^4.5\Rightarrow5^x=5^5\Rightarrow x=5\)
a)\(2^{x+3}+2^{x+2}-2^{x+1}-2^x=72\)
\(\Rightarrow2^x.2^3+2^x.2^2-2^x.2-2^x=72\)
\(\Rightarrow2^x.\left(2^3+2^2-2-1\right)=72\)
\(\Rightarrow2^x.9=72\Rightarrow2^x=72:9\)
\(\Rightarrow2^x=8=2^3\Rightarrow x=3\)
b) \(2^{x-3}+2^{x-1}+2^x=51\)
\(\Rightarrow2^x:2^3+2^x:2+2^x=51\)
\(\Rightarrow2^x.\frac{1}{2^3}+2^x.\frac{1}{2}+2^x=51\)
\(\Rightarrow2^x.\left(\frac{1}{2^3}+\frac{1}{2}+1\right)=51\)
\(\Rightarrow2^x.\frac{13}{8}=51\)
\(\Rightarrow2^x=51:\frac{13}{8}=\frac{408}{13}\)
\(a, 2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(\Leftrightarrow2^x.2^{-1}+5.2^x.2^{-2}=\frac{7}{32}\)
\(\Leftrightarrow2^x.2^{-1}\left(1+5.2^{-1}\right)=\frac{7}{32}\)
\(\Leftrightarrow2^x.\frac{1}{2}.\frac{7}{2}=\frac{7}{32}\)
\(\Leftrightarrow2^x=\frac{1}{8}=2^{-3} \Rightarrow x=-3\)
\(b, 2^{5x-1}:8^x=32^5\)
\(\Leftrightarrow32^x.2^{-1}.8^{-x}=32^5\)
\(\Leftrightarrow2^{2x}.2^{-1}=32^5\)
\(\Leftrightarrow2^{2x-1}=2^{25}\)
\(\Leftrightarrow2x-1=25 \Rightarrow x=13\)
Ta có : \(x^2-3x-13⋮x-3\)
=> \(x\left(x-3\right)-13⋮x-3\)
Mà \(x\left(x-3\right)⋮x-3\)
=> \(-13⋮x-3\)
=> \(x-3\inƯ_{\left(-13\right)}\)
=> \(x-3\in\left\{1,-1,13,-13\right\}\)
=> \(x\in\left\{4,2,16,-7\right\}\)
Vậy \(x=4,x=2,x=16,x=-7\) .
7x - x=5^21 : 5^19 + 3 . 3^2 -7
6x=5^2+3^3 -7
6x=25+27-7
6x=45
x=7,5
học tốt bạn nhé
a) (2-x-16)3=1000
=> 2-x-16 = 10
2-x = 10+16
2-x = 26
x = 2-26
x = -24
(x+1)5=1
=> x+1=1
x = 1-1
x = 0
c) 3x.3x+1=319
<=> 32x+1 = 319
=> 2x+1 = 19
2x = 19-1
2x = 18
x = 18:2
x = 9
d) 13x+32=33
13x = 33-32
13x = 1
=> x = 0
e) 22x-4=1024
=> 22x-4 = 210
<=> 2x-4 = 10
2x = 10+4
2x = 14
x = 14:2
x = 7
a.(x-14)^3=1000
(x-14)^3=10^3
=x-14=10
x=24
b,(x+1)^5=1
(x+1)^=1^5
x+1=1
x=0
c,3^x+3^x+1=3^19
=3^x+2=3^19
=x+2=19
x=17
d,13^x+32=33
13^x=1
x=0
e,2^2x-4=1024
2^2x-4=2^10
2x-4=10
2x=6
x=3
2x : 23 + 2x : 2 + 2x = 52
2x.1/8 + 2x.1/2 + 2x = 52
2x . (1/8 +1/2 + 1 ) = 52
2x . 13/8 = 52
2x = 52: 13/8
2x = 32
2x = 25
=> x = 5
Vậy x = 5