Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}\)
\(=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}\)
\(=\frac{3^{61}}{3^{60}}\)
\(=3^1=3\)
\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)
\(\left(3-2x\right)^3=27=3^3\)
=> 3 - 2x = 3
=> 2x = 3 - 3
=> 2x = 0
=> x = 0
P/s: mk làm từng phần một
\(\left(1-5x\right)^2=25=\left(\pm5\right)^2\)
+) 1 - 5x = 5
=> 5x = 1 - 5
=> 5x = -4
=> x = -4/5
+) 1 - 5x = -5
=> 5x = 6
=> x = 6/5
Vậy,........
\(A=\dfrac{3^6\cdot3^8\cdot5^4-5^{13-9}\cdot3^{13}}{3^{12}\cdot5^6+3^{12}\cdot5^6}\)
\(=\dfrac{3^{14}\cdot5^4-5^4\cdot3^{13}}{3^{12}\cdot5^6\cdot2}\)
\(=\dfrac{3^{13}\cdot5^4\cdot2}{3^{12}\cdot5^6\cdot2}=\dfrac{3}{25}\)
\(B=\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3=1+12^3=1729\)
\(\frac{3^{11}\div5+3^{11}.3}{3^{10}.2^2}=\frac{3^{11}\cdot\frac{1}{5}+3^{11}\cdot3}{3^{10}.2^2}\)
\(=\frac{3^{11}.\left(\frac{1}{5}+3\right)}{3^{10}.2^2}=\frac{3^{11}.\frac{16}{5}}{3^{10}.2^2}=\frac{\frac{48}{5}}{2^2}=\frac{48}{5}\cdot\frac{1}{4}=\frac{12}{5}\)
\(\frac{1}{3^{10}}\div\frac{1}{9^5}=\frac{1}{3^{10}}\div\frac{1}{3^{10}}=1\)
#)Giải :
Câu 2 :
Ta có : \(\frac{1}{9^5}=\frac{1}{\left(3^2\right)^5}=\frac{1}{3^{10}}\)
Vì \(\frac{1}{3^5}=\frac{1}{3^5}\Rightarrow\frac{1}{3^5}=\frac{1}{9^5}\)
311:5+311 .3/310.22(Câu 1)
\(=\frac{8.3^{11}}{3^{10}.4}=6\)
1/310 : 1/95 (Câu 2)
\(=\frac{1}{3^{10}}.3^{10}=1\)
(-25/36)5:5/62 (câu 3)
\(=\frac{-5^5}{6^{10}}.\frac{6^2}{5}=-\frac{5^4}{6^8}\)