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a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
a) 25 + 3 . ( x - 7 ) = 106
3 . ( x - 7 ) = 106 -25
3 . ( x - 7 ) = 81
( x - 7 ) = 81 : 3
x - 7 = 27
x = 27 + 7
x = 34
b) 32 . ( x + 4 ) - 52 = 5. 22
32 . ( x + 4 ) - 52 = 20
32 . ( x + 4 ) = 20 + 52
32 . ( x + 4 ) = 45
( x + 4 ) = 45 : 32
( x + 4 ) = 5
x = 5 - 4
x = 1
c) 4 . ( x - 3 ) = 72 - 110
4 . ( x - 3 ) = 48
( x - 3 ) = 48 : 4
x - 3 = 12
x = 12 + 3
x = 15
tk cho mk nha
a) 25 + 3 . ( x - 7 ) =106
3 . ( x - 7 ) = 106 - 25
3 . ( x -7 ) =81
x - 7 = 81 :3
x - 7 = 27
x = 27 - 7
x =20
b) 9 . ( x+ 4 ) - 25 = 5.4
9 . ( x + 4 ) - 25 = 20
9 . (x + 4 ) = 25 + 20
9 . ( x + 4 ) = 45
x + 4 = 45 :9
x +4 = 5
x = 5 -4
x = 1
c) 4. ( x - 3 ) = 49 -1
4 . ( x - 3 ) = 48
x - 3 = 48 : 4
x -3 =24
x = 24 + 3
x = 27
25+3(x-8)=106
25+3x-24=106
3x=106-25+24
3x=105
x=105/3
x=35
Vậy x=35
\(3^2\left(x+4\right)-5^2=5.2^2\)
\(9\left(x+4\right)-25=20\)
\(9x+36-25=20\)
\(9x=20-36+25\)
\(9x=9\)
\(x=1\)
Vậy x=1
25+3(x-8)=106
3(x-8)=106-25
3(x-8)=81
x-8=81:3
x-8=27
x=27+8
x=35
Bài 2
3^2(x+4)-5^2=5.2^2
9(x+4)-25=5.4
9(x+4)-25=20
9(x+4)=25+20
9(x+4)=45
x+4=45:9
x+4=5
x=5-4
x=1
Nếu saj cko mjk xl nke!
a)410x220x830 b)56x53+32x33
=(22)10x220x(23)30 =56+3+32+3
=220x220x290 =59+35
=220+20+90 =1953125+243
=2130 =1953368.
c)13+23+33+43+53 d)225:324
=1+8+27+64+125 =225 :(25)4
=9+27+64+125 =225:220
=36+64+125 =225-20
=100+125 =25
=225
a)\(\left(2^2\right)^{10}.2^{20}.\left(2^3\right)^{30}=2^{20}.2^{20}.2^{90}=2^{130}\)
b)\(5^{6+3}+3^{2+3}=5^9+3^5\)
c)\(1^3+2^3+3^3+4^3+5^3=\left(1+2+3+4+5\right)^2=15^2=225\)
d)\(2^{25}:32^4=2^{25}:\left(2^5\right)^4=2^{25}:2^{20}=2^{25-20}=2^5=32\)
1.
a. Ta có: \(A=2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
\(B=3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
Mà \(8^{100}< 9^{100}\)
\(\Rightarrow A< B\)
b. Ta có: \(A=2^{332}< 2^{333}=2^{3.111}=\left(2^3\right)^{111}=8^{111}\)
\(B=3^{223}>3^{222}=3^{2.111}=\left(3^2\right)^{111}=9^{111}\)
Mà \(8^{111}< 9^{111}\)
\(\Rightarrow A< B\)
c. Ta có: \(A=2^{91}=2^{13.7}=\left(2^{13}\right)^7=8192^7\)
\(B=5^{35}=5^{5.7}=\left(5^5\right)^7=3125^7\)
Mà \(8192^7>3125^7\)
\(\Rightarrow A>B\)
Câu 2:
a: =>(x-6)(x-7)=0
=>x=6 hoặc x=7
b: =>\(x^8\left(x^2-25\right)=0\)
\(\Leftrightarrow x^8\left(x-5\right)\left(x+5\right)=0\)
hay \(x\in\left\{0;5;-5\right\}\)
a) 100 - 7.(x-5) = 68
7.(x - 5) = 100 - 68 = 32
x - 5 = \(\frac{32}{7}\)
x = \(\frac{32}{7}+5=\frac{67}{7}\)
b) 2(x-6)+2227:17=151
2( x -6) + 131 = 151
2 (x - 6) = 20
x - 6 = 20 : 2 = 10
x = 10 + 6 = 16
c)
\(4\left(3x-4\right)-2=18\)
<=> \(12x-16-2=18\)
<=> \(12x=36\)
<=> \(x=3\)
Vậy x=3
d)
\(\left(3x-10\right):10=50\)
<=> \(3x-10=500\)
<=> \(3x=510\)
<=> x= \(170\)
Vậy x= 170
f)
\(x-\left[42+\left(-25\right)\right]=-8\)
<=> \(x-17=-8\)
<=> x= \(9\)
Vậy x=9
h)
\(x+5=20-\left(12-7\right)\)
<=> \(x+5=15\)
<=> \(x=10\)
Vậy x= 10
k)
\(\left|x-5\right|=7-\left(-3\right)\)
<=> \(\left|x-5\right|=10\)
* Với \(x>=5\) ; ta được:
\(x-5=10\)
<=> x= 15 (thoả mãn điều kiện )
*Với \(x< 5\) ; ta được:
\(-\left(x-5\right)=10\)
<=> \(-x+5=10\)
<=> \(-x=5\)
<=> \(x=-5\) (thoả mãn điều kiện)
Vậy x=15 ; x= -5
i)
\(\left|x-5\right|=\left|7\right|\)
<=> \(\left|x-5\right|=7\)
*Với \(x>=5\) ; ta được:
\(x-5=7\)
<=> \(x=12\) (thoả mãn)
*Với \(x< 5\) ; ta được:
\(-\left(x-5\right)=7\)
<=> \(-x=2\)
<=> \(x=-2\) (thoả mãn)
Vậy x= 12; x= -2
m)
\(2^{x+1}.2^{2009}=2^{2010}\)
<=> \(2^{x+1+2009}=2^{2010}\)
<=> \(2^{x+2010}=2^{2010}\)
=> \(x+2010=2010\)
=> \(x=0\)
Vậy x=0
n)
\(10-2x=25-3x\)
<=>\(x=15\)
Vậy x=15
\(a,\)\(25+3\left(x-8\right)=106.\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow3x=105\)\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9\left(x+4\right)-25=110\)
\(\Rightarrow9x+36-25=110\)
\(\Rightarrow9x+11=110\)
\(\Rightarrow9x=99\Leftrightarrow x=11\)
\(a,25:3\left(x-8\right)=106\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9x+36-25=110\)
=\(9x+11=110\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=11\)