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\(\frac{2}{3}:\frac{5}{6}=\frac{4}{5}\)
\(\frac{4}{5}\cdot\frac{2}{3}=\frac{8}{15}\)
Vậy : \(\frac{2}{3}:\frac{5}{6}< \frac{4}{5}x\cdot\frac{2}{3}\)nên \(\frac{4}{5}< \frac{8}{15}\)
Mình làm câu A
\(\frac{1}{2}\cdot\frac{3}{4}=\frac{3}{8}\)\(;\frac{5}{8}:\frac{6}{8}=\frac{5}{6}\)
Vậy \(\frac{1}{2}\cdot\frac{3}{4}< \frac{5}{8}:\frac{6}{8}\)
Nên : \(\frac{3}{8}< \frac{5}{6}\)
A.\(\frac{12}{15}>\frac{8}{15}\)
B.\(\frac{3}{8}< \frac{5}{6}\)
C.\(\frac{6}{7}< \frac{14}{3}\)
D.\(\frac{143}{144}>\frac{99}{100}\)
Nhớ k mình nha
\(a)9+\frac{24}{25}=\frac{9\cdot25+24}{25}=\frac{249}{25}\)
\(b)\frac{1}{20}+\frac{1}{4}+\frac{2}{5}=\frac{1}{20}+\frac{5}{20}+\frac{8}{20}=\frac{1+5+8}{20}=\frac{14}{20}=\frac{7}{10}\)
\(c)\frac{7}{12}+4=\frac{7}{12}+\frac{4}{1}=\frac{7+48}{12}=\frac{55}{12}\)
\(d)10+\frac{9}{8}=\frac{10}{1}+\frac{9}{8}=\frac{80+9}{8}=\frac{89}{8}\)
\(e)\frac{1}{4}+\frac{2}{25}+\frac{9}{100}=\frac{25}{100}+\frac{8}{100}+\frac{9}{100}=\frac{25+8+9}{100}=\frac{42}{100}=\frac{21}{50}\)
Còn 3 câu làm tương tự
Ba câu còn lại mình làm luôn :D
\(f)\frac{28}{90}+6=\frac{14}{45}+6=\frac{14}{45}+\frac{6}{1}=\frac{14+270}{45}=\frac{284}{45}\)
\(g)\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}=(\frac{3}{7}+\frac{4}{7})+\frac{4}{9}+\frac{4}{11}=1+\frac{4}{9}+\frac{4}{11}\)
\(=\frac{7}{7}+\frac{4}{9}+\frac{4}{11}=\frac{693+308+252}{693}=\frac{1253}{693}=\frac{179}{99}\)
\(h)\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}=(\frac{1}{8}+\frac{3}{8})+(\frac{1}{12}+\frac{5}{12})=\frac{4}{8}+\frac{6}{12}=\frac{1}{2}+\frac{1}{2}=1\)
5/7 < 4/3
7/2 > 4/79
2/5 < 6/10
15/23 < 1
1/4 = 3/12
27/9 > 2
27/36 > 2/9
14/15 < 1
7/6 > 7/9
51/17 = 3/1
tk mình nha bạn, mình kp vs bạn r đó. .. ^^
5/7 < 4/3 7/2 > 4/79 2/5 < 6/10 15/23 < 1 1/4 = 3/12 27/9 > 2 27/36 > 2/9 14/15 < 1 7/6 > 7/9 51/17 = 3/1
3+6=9;4+7=11;5+8=13;6+9=15;7+10=17;8+11=19
3+6=21
4+7=32
5+8=45
6+9=60
7+10=77
8+11=96