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Giải:
\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\left(-\dfrac{47}{60}\right).\dfrac{24}{47}\)
\(=\dfrac{7}{5}+\left(-\dfrac{2}{5}\right)\)
\(=\dfrac{7}{5}-\dfrac{2}{5}\)
\(=1\)
Vậy ...
\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\\ =\dfrac{28}{15}.0,25.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\\ =\dfrac{7}{15}.3+\dfrac{-47}{60}:\dfrac{47}{24}\\ =\dfrac{7}{5}+\dfrac{-2}{5}\\ =\dfrac{5}{5}=1\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2+3\cdot\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4}+3\cdot\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3\cdot\dfrac{37}{20}\cdot\dfrac{24}{47}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}=\dfrac{2327}{705}\)
\(1\dfrac{13}{15}.\left(0,5\right)^2+3.\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}+3.\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3.\dfrac{37}{20}:\dfrac{47}{24}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}\)
\(=\dfrac{2327}{705}\)
mik ko hiểu chỗ 1 19/60 và 1 23/24 là s bạn có f vầy ko :( sau thì ib để mik sửa ạ
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right):1\frac{23}{24}\)
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot\frac{3}{1}+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{39}{60}+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(\frac{32}{60}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(-\frac{47}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(-\frac{2}{5}\right)\)
\(B=\frac{13}{20}+\left(-\frac{8}{20}\right)\)
\(B=\frac{5}{20}=\frac{1}{4}\)