Question

[Phạm Thị Kim Anh]

(1+1/2+1/4+1/8+1/16)/(1-1/2+1/4+1/8+1/16)

tính

Answer 1

[Yuan Bing Yan _ Viên Băng Nghiên]

\(\frac{\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)}{\left(1-\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)}=\frac{\left(\frac{16}{16}+\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)}{\left(\frac{16}{16}-\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)}=\frac{\frac{31}{16}}{\frac{15}{16}}=\frac{31}{16}:\frac{15}{16}=\frac{31}{16}\times\frac{16}{15}=\frac{31}{15}\)

Answer 2

[Nguyễn Ngọc Quý]

nhầm gì đúng đề mà