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\(95-105:x=60\)
\(105:x=95-60\)
\(105:x=35\)
\(x=105:35\)
\(x=3\)
1) 9 . (x + 7) - 12 = 24
9 . (x + 7) = 24 + 12
9 . (x + 7) = 36
x + 7 = 36 : 9
x + 7 = 4
x = 4 - 7
x = -3
2) 12 - 3x = -30
3x = 12 - (-30)
3x = 12 + 30
3x = 42
x = 42 : 3
x = 14
3) 95 - 105 : x = 60
105 : x = 95 - 60
105 : x = 35
x = 105 : 35
x = 3
4) x + 35 = 12
x = 12 - 35
x = -23
5) (-24) - (10 - x) = 43
-24 - 10 + x = 43
-34 + x = 43
x = 43 - (-34)
x = 43 + 34
x = 77
6) 6 - (17 + x) = -16
6 - 17 - x = -16
-11 - x = -16
x = -11 - (-16)
x = -11 + 16
x = 5
7) (x - 18) - (-3) = 0
x - 18 + 3 = 0
x - 18 = 0 - 3
x - 18 = -3
x = -3 + 18
x = 15
8) 25 - (x - 6) = -1
25 - x + 6 = -1
25 - x = -1 - 6
25 - x = -7
x = 25 - (-7)
x = 25 + 7
x = 32
1)9.(x+7)-12=24
9.(x+7)=24+12
9.(x+7)=36
x+7=36:9
x+7=4
x=4-7
x=-3
a) (-95)+(-105)=-200
b) 38+(-85)=-47
c) 47-107=-60
e) 25+(-8)+(-25)+(-2)
=(-25+25) + [-8+(-2)]
=0 + (-10)
=-10
f) 18-(-2)=18+2=20
g) -16-5--21
=-16-5+21
=-21+21
=0
h) -11+23-(-21)
=-11+23+21
=12+21
=33
i) -13-15+5
=-18+5
=-13
Học Tốt
\(a.83-\left(-756-17\right)+\left(50-756\right)=83+756+17+50-756=\left(83+17\right)+50+\left(756-756\right)=100+50=150\)
\(b.-105+\left(-34-95\right)-166=-105+\left(-34\right)-95-166=\left(-105-95\right)-\left(34+166\right)=\left(-200\right)-200=-400\)
\(c,-\left(39+228-407\right)+\left(118-161\right)=-39-228+407+118-161=\left(-39-161\right)-\left(228-118\right)+407=\left(-200\right)-110=-310\)
\(d,5^{10}:5^8+60:12+\left(-10\right)=5^2+5+\left(-10\right)=5\left(5+1-2\right)=5.4=20\)
\(e,-342-\left(161-342\right)-39=-342-161+342-39=\left(-342+342\right)-\left(161+39\right)=-200\)\(g,7^5:7^3+\left(-187-149\right)-213=7^2+\left(-187\right)-149-213=\left(49-149\right)-\left(187+213\right)=\left(-100\right)-400=-500\)
18576: {\(105^0\)+[2.(102+101−100−99+98+97−96−95+.........+6+5−4−3+2+1)−201]}^3
Đặt A=102+101−100−99+98+97−96−95+...............+6+5−4−3+2+1
A=(102+101−100−99)+(98+97−96−95)+........+(6+5−4−3)+2+1
A=4+4+...........+4+3
A=4.25+3
A=103
⇒18576:{1050+[2.(102+101−100−99+98+97−96−95+.........+6+5−4−3+2+1)−201]}^3
=18576:[1+(2.103)−201]^3
=18576:63
=18576:216
=86
\(\sqrt[]{^{ }_{ }_{ }|^{ }_{ }\left[{}\begin{matrix}\\\\\\\end{matrix}\right.\begin{matrix}&&&&&\\&&&&&\\&&&&&\\&&&&∄&\\&&&&&\end{matrix}\right.ℤ}\)
105 - 5 ( x - 5 ) = 95
5 ( x - 5 ) = 105 - 95
5 ( x - 5 ) = 10
x - 5 = 10 : 5
x - 5 = 5
x = 5 + 5
x = 10