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1) Tim x biet :
a) 88 - 3 ( 7 + x ) = 64 b) 131 . x - 941 = 27 . 23 c) [ ( x + 32 ) - 17 ] . 2 = 42 d) [ ( x2 + 54 ) - 32 ] : 2 = 61
3(7+x)=88-64 131 . x - 941=1024 [ ( x + 32 ) - 17 ] =42:2 [ ( x2 + 54 ) - 32 ]=61x2
3(7+x)=24 131.x=1024+941 [ ( x + 32 ) - 17 ] =21 [ ( x2 + 54 ) - 32 ]=122
7+x=24:3 131.x=1965 x+32=21+17 x2 + 54 =122+32
7+x=8 x=1965:131 x+23=38 x2 + 54 =154
x=8-7 x=15 x=38-23 x2 =154-54
x=1 x=15 x2=100
x=10 hoặc x= -10
d)
\(152-3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=-4\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=152-\left(-4\right)\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=156\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=156\div3\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=52\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=52-42\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=10\)
\(\Rightarrow2\left(36\div x^2+7\right)=32-10\)
\(\Rightarrow2\left(36\div x^2+7\right)=22\)
\(\Rightarrow36\div x^2+7=22\div2\)
\(\Rightarrow36\div x^2+7=11\)
\(\Rightarrow36\div x^2=11-7\)
\(\Rightarrow36\div x^2=4\)
\(\Rightarrow x^2=36\div4\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x^2=3^2\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
bài 1
a)
=> 3(x-2)=60-51
=> 3(x-2) =9
=> x-2 =9:3
=> x-2 =3
=> x =3+2
=> x =5
b)
=>4x-20=25-2
=>4x-20=23
=>4x-20=8
=>4x=8+20
=>4x=28
=>x=28:4
=>x=7
c)
=> 25+x.5-64=251
=> x.5-64 =251-25
=> x.5-64 =226
=> x.5 =226+64
=> x.5 =290
=> x =290:5
=> x =58
d)
=> [(14)2 - (12)2].2x=1872
=> 52.2x =1872
=> 104x =1872
=> x = 1872:104
=> x=18
e)
x10=x
=> x10-x=0
=>x(x9-1)=0
=>\(\orbr{\begin{cases}x=0\\x^9-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x^9=1\Rightarrow x=1\end{cases}}}\)
nha
mình sẽ làm típ
T I C K cho mình mình sẽ làm típ
\(a)88-3(7+x)=64\) \(c)[(x+32)-17]\div2=42\)
\(\Rightarrow3(7+x)=88-64\) \(\Rightarrow(x+32)-17=42.2\)\(\Rightarrow x+32-17=84\)
\(\Rightarrow3(7+x)=24\) \(\Rightarrow x=84+17-32\)
\(\Rightarrow7+x=24\div3\) \(\Rightarrow x=69\)
\(\Rightarrow7+x=8\)
\(\Rightarrow x=8-7\)
\(\Rightarrow x=1\)
\(b)131.x-941=2^7.2^3\) \(d)[(x^2+54)-32]\div2=61\)
\(\Rightarrow131.x-941=2^{10}\) \(\Rightarrow(x^2+54)-32=61.2\)
\(\Rightarrow131.x=1024+941\) \(\Rightarrow x+54-32=122\)
\(\Rightarrow131.x=1965\) \(\Rightarrow x=122+32-54\)
\(\Rightarrow x=1965\div131\) \(\Rightarrow x=100\)
\(\Rightarrow x=15\)
A) 88-3(7+x)=64
3(7+x)=88-64
3(7+x)=24
7+x=24:3
7+x=8
X=8-7
X=1