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\(b,\left|x-5\right|=\left|-7\right|\\ \left|x-5\right|=7\\ \Rightarrow\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\\ Vậy...\\ c,\left|x-3\right|=\left|5\right|+\left|-7\right|\\ \left|x-3\right|=5+7\\ \left|x-3\right|=12\\ \Rightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\\Vậy...\\ d,\left(7-x\right)-\left(25+7\right)=-25\\ 7-x-32=-25\\ 7-x=-25+32\\ 7-x=7\\ x=7-7\\ x=0\\ Vậy...\\ e,\left|x-3\right|=7-\left(-2\right)\\ \left|x-3\right|=9\\ \Rightarrow\left[{}\begin{matrix}x-3=9\\x-3=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\\ Vậy...\)
a) \(-65-\left(x+15\right)+105=0\)
\(-65-\left(x+15\right)=-105\)
\(x+15=-65-\left(-105\right)\)
\(x+15=40\)
\(x=25\)
b) |-6| + (-9) - (x+1) = 7
-3- (x+1) =7
x+1 = -10
x = -11
c)\(\left|5-x\right|+\left(-25+7\right)=-3-\left(-10\right)\)
\(\left|5-x\right|+\left(-18\right)=7\)
\(\left|5-x\right|=25\)
\(\Rightarrow\orbr{\begin{cases}5-x=25\\5-x=-25\end{cases}\Rightarrow\orbr{\begin{cases}x=-20\\x=30\end{cases}}}\)
d) \(28-\left|x+6\right|+\left(-2\right)=0\)
\(28-\left|x+6\right|=2\)
\(\left|x+6\right|=26\)
\(\Rightarrow\orbr{\begin{cases}x+6=26\\x+6=-26\end{cases}\Rightarrow\orbr{\begin{cases}x=20\\x=-32\end{cases}}}\)
e) \(x-\left(13-15\right)=5+\left(10-x\right)-\left(-1\right)\)
\(x+2=5+10-x+1\)
\(x+2=16-x\)
\(x+x=16-2\)
\(2x=14\)
\(x=7\)
f) \(-120-\left(x-5\right)=125\)
\(x-5=-120-125\)
\(x-5=-245\)
\(x=-240\)
g) \(10-\left(-5+2\right)+\left(-9\right)=\left(-20+7\right)-x\)
\(-16=-13-x\)
\(x=-13+16\)
\(x=3\)
9-25=(7-x)-(25+7)
-16=7-x-32
7-x-32=16
7-x=-16+32
7-x=16
x=16+7
x=23
B,35-3.|x|=5.(2^3-4)
35-3.x=5.(8-4)
35-3.x=5.4
35-3.x=20
3.x=35-20
3.x=15
X=15:3
x =5
C, -6x=18
-6.x=18
X=18:(-6)
X= -3
D,10+2.|x|=2.(3^2-1)
10+2.x=2.8
10+2.x=16
2.x=16-10
2.x =6
X=6:2
x=3
Ok k mk nha
a) 9 - 25 = ( 7 - x) - (25+7)
- 16 = 7-x - 32
7 - x - 32 = -16
7 - x = -16 + 32
7 - x = 16
x = 16 + 7
x = 23
b) -6x = 18
- 6 .x = 18
x = 18 : (-6)
x = -3
a) 10-x-5=-5-7-11
=> 5 - x = -23
=> x = 28
b) |x| -3=0
=> |x| = 3
=> x = 3 hoặc x -3
c) ( 7-|x| ) .(2x-4)=0
=> 7 - |x| = 0 hoặc 2x - 4 = 0
=> |x| = 7 hoặc 2x = 4
=> x = 7 hoặc x = - 7 hoặc x = 2
c)2+3x=-15-19
=> 2 + 3x = -34
=> 3x = 36
=> x = 12
\(a,\frac{62}{7}:x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}:x=\frac{1624}{27}\)
\(x=\frac{62}{7}:\frac{1624}{27}=\frac{837}{5684}\)
\(b,\frac{1}{5}:x=\frac{1}{5}-\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{2}{35}\)
\(x=\frac{1}{5}:\frac{2}{35}=\frac{7}{2}\)
\(c,\frac{2}{3}.x-\frac{4}{7}=\frac{1}{7}\)
\(\frac{2}{3}.x=\frac{1}{7}+\frac{4}{7}=\frac{5}{7}\)
\(x=\frac{5}{7}:\frac{2}{3}=\frac{15}{14}\)
\(d,\frac{2}{7}-\frac{8}{9}.x=\frac{2}{3}\)
\(\frac{8}{9}.x=\frac{2}{7}-\frac{2}{3}=-\frac{8}{21}\)
\(x=-\frac{8}{21}:\frac{8}{9}=-\frac{3}{7}\)
\(e,\frac{4}{7}+\frac{5}{9}:x=\frac{1}{5}\)
\(\frac{5}{9}:x=\frac{1}{5}-\frac{4}{7}=-\frac{13}{35}\)
\(x=\frac{5}{9}:-\frac{13}{35}=\frac{175}{117}\)
\(i,\frac{2}{5}-\frac{2}{5}.x=\frac{2}{5}\)
\(\frac{2}{5}.\left(1-x\right)=\frac{2}{5}\)
\(1-x=\frac{2}{5}:\frac{2}{5}=1\)
\(x=1-1=0\)
\(g,\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\frac{1}{3}:x=-1-\frac{2}{3}=-\frac{5}{3}\)
\(x=\frac{1}{3}:-\frac{5}{3}=-\frac{1}{5}\)
học tốt nha
1,x(x + 7) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-7\end{cases}}}\)
2, \(\left(x+12\right).\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+12=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-12\\x=3\end{cases}}}\)
3. \(\left(-x+5\right).\left(3-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}-x+5=0\\3-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=3\end{cases}}}\)
4. \(x\left(2+x\right).\left(7-x\right)=0\)
=> x = 0 ; 2 + x = 0; 7 - x = 0 => x = 0; x = -2 hoặc x = 7
5 , tự làm
x.(x+7)=0
x=0 hoặc x+7=0
x=0hoặc x=0-7
x=0 hoặc x=-7
vậy x thuộc 0 hoặc 7
a,|x+2|=0
=》x+2=0
=》x=0-2
=>x=-2
b,|x-5|=|-7|
=>|x-5|=7
=>x-5=7 hoặc x-5=-7
+) với x-5=7. +) với x-5=-7
x=12. x=-2
vậy x€{12,-2}
c,|x-3|=7-(-2)
|x-3|=7+2
|x-3|=9
=>X-3=-9 hoặc x-3=9
+) x-3=-9. x-3=9
x=-6. x=12
vậy x€{-6,12}
d,(7-x)-(25+7)=-25
(7-x)-32=-25
(7-x)=7
x=0
vẫy=0
e,|x-3|=|5|+|-7|
|X-3|=5+7
|x-3|=12
=>x-3=12 HOẶC x-3=-12
+) x-3=12. x-3=-12
x=15. x=-9
vậy x€{15,-9}