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a)x2-2xy+y2+3x-3y-10
=(x2-2xy+y2)+(3x-3y)-10
=(x-y)2+3(x-y)-10
=(x-y).(x-y+3)-10
1a) a2 + b2 + c2 + 2ab + 2bc + 2ca + a2 + b2 + c2
= ( a2 + 2ab +b2 ) + ( a2 + 2ac + c2 ) + ( b2 + 2bc + c2 )
= ( a + b )2 + ( a + c )2 + ( b + c )2
1b) 2.( ac - ab - bc + b2 ) + 2.( bc - ba - ac + a2 ) + 2.( ba - bc - ca + c2 )
= 2ac - 2ab - 2bc + 2b2 + 2bc - 2ab - 2ac +2a2 + 2ab - 2bc - 2ac + 2c2
= 2a2 + 2b2 + 2c2 - 2ab - 2ac - 2bc
= ( a2 - 2ab + b2 ) + (a2 - 2ac + c2 ) + (b2 - 2bc + c2 )
= (a-b)2 + (a-c)2 + (b-c)2
Tách : \(a-b=-\left(c-a\right)-\left(b-c\right)\)
Ta có : \(a^2b^2\left(a-b\right)+b^2c^2\left(b-c\right)+c^2a^2\left(c-a\right)\)
\(=a^2b^2\left[-\left(c-a\right)-\left(b-c\right)\right]+b^2c^2\left(b-c\right)+c^2a^2\left(c-a\right)\)
\(=-a^2b^2\left(c-a\right)+c^2a^2\left(c-a\right)-a^2b^2\left(b-c\right)+b^2c^2\left(b-c\right)\)
\(=a^2\left(c-a\right)\left(c^2-b^2\right)+b^2\left(b-c\right)\left(c^2-a^2\right)\)
\(=a^2\left(c-a\right)\left(c-b\right)\left(c+b\right)+b^2\left(b-c\right)\left(c-a\right)\left(c+a\right)\)
\(=\left(c-a\right)\left(b-c\right)\left(b^2c+b^2a-a^2c-a^2b\right)\)
\(=\left(c-a\right)\left(b-c\right)\left[-\left(a-b\right)\left(ab+bc+ac\right)\right]\)
\(=-\left(a-b\right)\left(b-c\right)\left(c-a\right)\left(ab+bc+ac\right)\)
a2b2(a-b)+ b2c2(b-c)+ c2a2(c-a)= a3b2-a2b3+b3c2-b2c3+c2a2(c-a)=b3(c2-a2)-b2(c3-a3)+c2a2(c-a)
1. (a2+b2+ab)2-a2b2-b2c2-c2a2
=a4+b4+a2b2+2(a2b2+ab3+a3b)-a2b2-b2c2-c2a2
=a4+b4+2a2b2+2ab3+2a3b-b2c2-c2a2
=(a2+b2)2+2ab(a2+b2)-c2(a2+b2)
=(a2+b2)[(a+b)2-c2]
=(a2+b2)(a+b+c)(a+b-c)
2. a4+b4+c4-2a2b2-2b2c2-2a2c2=(a2-b2-c2)2
3. a(b3-c3)+b(c3-a3)+c(a3-b3)
=ab3-ac3+bc3-ba3+ca3-cb3
=a3(c-b)+b3(a-c)+c3(b-a)
=a3(c-b)-b3(c-a)+c3(b-a)
=a3(c-b)-b3(c-b+b-a)+c3(b-a)
=a3(c-b)-b3(c-b)-b3(b-a)+c3(b-a)
=(c-b)(a-b)(a2+ab+b2)-(b-a)(b-c)(b2+bc+c2)
=(a-b)(c-b)(a2+ab+2b2+bc+c2)
4. a6-a4+2a3+2a2=a4(a+1)(a-1)+2a2(a+1)=(a+1)(a5-a4+2a2)=a2(a+1)(a3-a2+2)
5. (a+b)3-(a-b)3=(a+b-a+b)[(a+b)2+(a+b)(a-b)+(a-b)2]
=2b(3a2+b2)
6. x3-3x2+3x-1-y3=(x-1)3-y3=(x-1-y)[(x-1)2+(x-1)y+y2]
=(x-y-1)(x2+y2+xy-2x-y+1)
7. xm+4+xm+3-x-1=xm+3(x+1)-(x+1)=(x+1)(xm+3-1)
(Đúng nhớ like nhá !)
Minh Hải,Lê Thiên Anh,Nguyễn Huy Tú,Ace Legona,...giúp mk vs mai mk đi hk rùi
Bài 1:
\(A=a^2b^2\left(b-a\right)+b^2c^2\left(c-b\right)+c^2a^2\left(a-c\right)\)
\(=a^2b^2\left(b-c+c-a\right)+b^2c^2\left(c-a+a-b\right)+c^2a^2\left(a-c\right)\)
\(=a^2b^2\left(b-c\right)+a^2b^2\left(c-a\right)+b^2c^2\left(c-a\right)+b^2c^2\left(a-b\right)+c^2a^2\left(a-c\right)\)
\(=\left(c-a\right)\left(a^2b^2+b^2c^2-c^2a^2\right)+b^2\left[a^2\left(b-c\right)+c^2\left(a-b\right)\right]\)
\(=\left(c-a\right)\left(a^2b^2+b^2c^2-c^2a^2\right)+b^2\left(c-a\right)\left(ac-bc-ba\right)\)
\(=\left(c-a\right)\left[a^2b^2+b^2c^2-c^2a^2+b^2\left(ac-bc-ba\right)\right]\)
2/ \(\left(17x-5\right)^2+2\left(17x-5\right)\left(3x-2\right)+\left(3x-2\right)^2=0\)
\(\Leftrightarrow\left(17x-2+3x-2\right)^2=0\)
\(\Leftrightarrow20x-4=0\)
\(\Rightarrow x=\frac{1}{5}\)