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1 ) \(\left(2x-5\right)+17=6\)
\(\Leftrightarrow2x-5=-11\)
\(\Leftrightarrow2x=-6\)
\(\Leftrightarrow x=-3\)
Vậy \(x=-3.\)
2 ) \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow2+6x=-4\)
\(\Leftrightarrow6x=-6\)
\(\Leftrightarrow x=-1\)
Vậy \(x=-1.\)
3 ) \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow3x+9=-18\)
\(\Leftrightarrow3x=-27\)
\(\Leftrightarrow x=-9\)
Vậy \(x=-9.\)
4 ) \(24:\left(3x-2\right)=-3\)
\(\Leftrightarrow\left(3x-2\right)=-8\)
\(\Leftrightarrow3x=-6\)
\(\Leftrightarrow x=-2\)
Vậy \(x=-2.\)
5 ) \(-45:5.\left(-3-2x\right)=3\)
\(\Leftrightarrow-9\left(-3-2x\right)=3\)
\(\Leftrightarrow18x+27=3\)
\(\Leftrightarrow18x=-24\)
\(\Leftrightarrow x=-\frac{4}{3}\)
Vậy \(x=-\frac{4}{3}.\)
a, (2x - 5) + 17 = 6
=> 2x - 5 + 17 = 6
=> 2x = 6 - 17 + 5
=> 2x = -6
=> x = -3
vậy_
a, (2x - 5) + 17 = 6
2x - 5 = 6 - 17
2x - 5 = -11
2x = -11 + 5
2x = -6
x = -6 : 2 = -3
b) -12 + 3.(-x + 7) = -18
3.(-x + 7) = -18 + 12
3.(-x + 7) = -6
-x + 7 = -6:3
-x + 7 = -2
-x = -2 - 7
-x = -9
x = 9
\(a,\left(2x-5\right)+17=6\)
\(2x-5=6-17\)
\(2x-5=-11\)
\(2x=-11+5\)
\(2x=-6\)
\(x=-3\)
\(b,10-2.\left(4-3x\right)=-4\)
\(2.\left(4-3x\right)=10+4\)
\(2.\left(4-3x\right)=14\)
\(4-3x=14:2\)
\(4-3x=7\)
\(-3x=7-4\)
\(-3x=3\)
\(x=-1\)
\(c,-12+3.\left(-x+7\right)=18\)
\(3.\left(-x+7\right)=18+12\)
\(3.\left(-x+7\right)=30\)
\(-x+7=30:3\)
\(-x+7=10\)
\(x=7-10\)
\(x=-3\)
\(d,24:\left(3x-2x\right)=-3\)
\(24:x=-3\)
\(x=24:\left(-3\right)\)
\(x=-8\)
\(e,-45:5.\left(-3-2x\right)=3\)
\(-9.\left(-3-2x\right)=3\)
\(27+18x=3\)
\(18x=3-27\)
\(18x=-24\)\
\(x=-\frac{4}{3}\)
a) ( 2x - 5 ) + 17 = 6
( 2x - 5 ) = 6 - 17
( 2x - 5 ) = - 11
2x = - 11 + 5
2x = - 6
x = - 6 : 2
x = - 3
Vậy x = - 3
b) 10 - 2( 4 - 3x ) = - 4
2 ( 4 - 3x ) = 10 - ( -4 )
2 ( 4 -3x ) = 10 + 4 = 14
4 - 3x = 14 : 2 = 7
3x = 4 - 7 = -3
x = -3 : 3
x = - 1
Vậy x = - 1
c ) - 12 + 3 ( - x + 7 ) = - 18
3 ( - x + 7 ) = - 18 - ( - 12 )
3 ( - x + 7) = - 18 + 12 = - 6
( - x + 7 ) = - 6 : 3
- x + 7 = - 2
- x = - 2 - 7
- x = - 9
=> x = 9
Vậy x = 9
d) 24 : ( 3x - 2 ) = - 3
3x - 2 = 24 : ( - 3 )
3x - 2 = - 8
3x = - 8 + 2
3x = - 6
x = - 6 : 3
x = - 2
Vậy x = - 2
e ) - 45 : [ 5 . ( - 3 - 2x )] = 3 ( câu này bạn viết thiếu đe nha , làm mình tính mãi không ra )
5 . ( - 3 - 2x ) = - 45 : 3
5 . ( -3 - 2x ) = - 15
- 3 - 2x = - 15 : 5
- 3 - 2x = - 3
2x = - 3 - ( - 3 )
2x = - 3 + 3
2x = 0
=> x = 0
Vậy x = 0
aaloskzjjskwnsnndnajabbdjrbevvdvxujsbskxkkdjdjjdjjsjshsjdjdbdbbdbdbxbfbA
a)=2
b)=0.3333333333
c)=9
d)= chua tinh
e)=33
g)=5
tk minh nha ban nha
a) (2x-5)+17=16
2x-5=16-17
2x-5=-1
2x=-1+5
2x=4
x=4:2
x=2
b) 10-2.(4-3x)=-4
2.(4-3x)=10--4
2.(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
A,-16+23+x=-16
<=>x=-16+16-23
<=>x=-23
B,10-2(4-3x)=-4
<=>10-8+6x=-4
<=>6x=-4-10+8
<=>6x=-6
<=>x=-1
C,-12+3(-x+7)=-18
<=>-12-3x+21=-18
<=>-3x=-18+12-21
<=>-3x=-27
<=>x=9
D,24:(3x-2)=-3
<=>24/(3x-2)=-3
<=>-3(3x-2)=24
<=>3x-2=-8
<=>3x=-6
<=>x=-2
E,|x+8|-7=8
<=>|x+8|=15
<=>x+8=+-15
Chia 2 TH:
TH1:x+8=15
<=>x=7
TH2:x+8=-15
<=>x=-23
F,-45:5(-3-2x)=3
<=>-9(-3-2x)=3
<=>27+18x=3
<=>18x=-24
<=>x=-4/3
G,|x-1|=0
<=>x-1=0
<=>x=1
H,-13|x|=-26
<=>|x|=2
<=>x=+-2
a) -16 + 23 + x = -16
x = -16 + 16 - 23
x = -23
Vậy x = -23
b) 10 - 2. (4 - 3x) = -4
10 - 2 . 4 + 2. 3x = -4
10 - 8 + 6x = -4
6x = -4 - 10 + 8
6x = -6
x = (-6) : 6
x = -1
Vậy x = -1
c) -12 + 3. (-x + 7) = -18
-12 + 3. (-x) + 3. 7 = -18
-12 + (-3x) + 21 = -18
-3x = -18 + 12 - 21
-3x = -27
x = (-27) : (-3)
x = -9
Vậy x = -9
d) 24 : (3x - 2) = -3
3x - 2 = 24 : (-3)
3x - 2 = -8
3x = -8 + 2
3x = -6
x = (-6) : 3
x = -2
Vậy x = -2
e) lx + 8l - 7 = 8
lx + 8l = 8 + 7
lx + 8l = 15
\(\Rightarrow\hept{\begin{cases}x+8=15\\x=18-5\\x=13\end{cases}hay\hept{\begin{cases}x+8=-15\\x=-15-8\\x=-23\end{cases}}}\)
Vậy \(x\in\left\{13;-23\right\}\)
f) (-45) : 5. (-3 - 2x) = 3
(-9). (-3 - 2x) = 3
(-9). (-3) + 9. 2x = 3
27 + 18x = 3
18x = 3 - 27
18x = -24
x = (-24) : 18
x =\(\frac{-4}{3}\)
Vậy x =\(\frac{-4}{3}\)
g) lx - 1l = 0
\(\Rightarrow x-1=0\)
x = 0 + 1
x = 1
Vậy x = 1
h) (-13). lxl = -26
lxl = (-26) : (-13)
lxl = 2
\(\Rightarrow x=2\)
Vậy x = 2
Chúc bạn học tốt!!!
\(\text{ 10-2.(4-3x)=-4 }\)
\(2\left(4-3x\right)=14\)
\(4-3x=14:2\)
\(4-3x=7\)
\(\Rightarrow3x=-3\)
\(\Rightarrow x=-1\)
\(\text{ 24:(3x-2)=-3}\)
\(3x-2=-8\)
\(\Rightarrow3x=-8+2\)
\(3x=-6\)
\(\Rightarrow x=-2\)
\(\text{-12+3(-x+7)=-18}\)
\(3\left(-x+7\right)=-6\)
\(-x+7=-6:3\)
\(-x+7=-2\)
\(\Rightarrow-x=-9\)
\(\Rightarrow x=9\)
\(\text{-45:5.(-3-2x)=3}\)
\(-9\left(-3-2x\right)=3\)
\(\Rightarrow-3-2x=\frac{-1}{3}\)
\(\Rightarrow-2x=\frac{-1}{3}+\left(-3\right)\)
\(-2x=\frac{-10}{3}\)
\(\Rightarrow x=\frac{5}{3}\)
1,
( 2x-5) + 17=6
\(2x-5=6-17\)
\(2x-5=-11\)
\(2x=-11+5\)
\(2x=-6\)
\(x=-6:2\)
\(x=-3\)
Vậy \(x=3\)
2,
10-2(4-3x)=-4
\(-2\left(4-3x\right)=-4-10\)
\(-2\left(4-3x\right)=-14\)
\(4-3x=-14:\left(-2\right)\)
\(4-3x=7\)
\(-3x=7-4\)
\(-3x=3\)
\(x=3:\left(-3\right)\)
\(x=-1\)
Vậy \(x=-1\)
3,
-12+3(-x+7)=-18
\(3\left(-x+7\right)=-18+12\)
\(3\left(-x+7\right)=-6\)
\(-x+7=-6:3\)
\(-x+7=-2\)
\(-x=-2-7\)
\(-x=-9\)
\(x=9\)
\(\text{Vậy }x=9\)
4,
24:(3x -2)=-3
\(3x-2=24:\left(-3\right)\)
\(3x-2=-8\)
\(3x=-8+2\)
\(3x=-6\)
\(x=-6:3\)
\(x=-2\)
\(\text{Vậy }x=-2\)
5,
-45:5.(-3-2x)=3
\(5\left(-3-2x\right)=-45:3\)
\(5\left(-3-2x\right)=-15\)
\(-3-2x=-15:5\)
\(-3-2x=-3\)
\(-2x=-3+3\)
\(-2x=0\)
\(x=0\)
Vậy \(x=0\)
6,
x.(x+7)= 0
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x+7=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
\(\text{Vậy}\left\{{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
7,
( x+ 12 ) .( x-3)=0
\(\Rightarrow\left\{{}\begin{matrix}x+12=0\\x-3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-12\\x=3\end{matrix}\right.\)
\(\text{Vậy }\left\{{}\begin{matrix}x=-12\\x=3\end{matrix}\right.\)
8,
(-x+5).(3-x) =0
\(\Rightarrow\left\{{}\begin{matrix}-x+5=0\\3-x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}-x=-5\\-x=-3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=5\\x=3\end{matrix}\right.\)
Vậy \(x=5\text{ hoặc }x=3\)
9, x.( 2+x).(7-x)=0
\(\Rightarrow\left\{{}\begin{matrix}x=0\\2+x=0\\7-x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)
Vậy \(\left\{{}\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)
10,
(x-1).(x+2).(-x-3)=0
\(\Rightarrow\left\{{}\begin{matrix}x-1=0\\x+2=0\\-x-3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=1\\x=-2\\-x=3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)
Vậy \(\left\{{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)
1)\(10-2\left(4-3x\right)=-4\)
\(\Rightarrow2\left(4-3x\right)=10-\left(-4\right)\)
\(\Rightarrow2\left(4-3x\right)=14\)
\(\Rightarrow4-3x=7\)
\(\Rightarrow3x=-3\)
\(\Rightarrow x=-1\)
Vậy x=-1
2)????
3)\(24:\left(3x-2\right)=-3\)
\(\Rightarrow3x-2=-8\)
\(\Rightarrow3x=-6\)
\(\Rightarrow x=-2\)
Vậy x=-2
4)\(-45:5\left(-3-2x\right)=3\)
\(\Rightarrow5\left(-3-2x\right)=-15\)
\(\Rightarrow-3-2x=-3\)
\(\Rightarrow2x=0\)
\(\Rightarrow x=0\)
Vậy x=0
_Học tốt_