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a) Ta có : \(\frac{2010}{2011}>\frac{2010}{2011+2012}\)
\(\frac{2011}{2012}>\frac{2011}{2011+2012}\)
Nên \(\frac{2010}{2011}+\frac{2011}{2012}>\frac{2010+2011}{2011+2012}\)=> M > N
b) P = \(\frac{2011.2012-2}{2010.2011+4020}=\frac{2011.\left(2010+2\right)-2}{2010.2011+4020}=\frac{2011.2010+2011.2-2}{2010.2011+4020}=\)\(\frac{2011.2010+4020}{2010.2011+4020}=1\)
Nên P = 1
câu b sửa lại:\(P=\frac{2011.2012-2}{2010.2011+4020}=\frac{2011.2010+4022-2}{2010.2011+4020}=\frac{2010.2011+4020}{2010.2011+4020}=1\)
\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)
\(=1:\frac{5}{6}\)
\(=1\times\frac{6}{5}\)
\(=\frac{6}{5}\)
\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)
\(=1:\frac{5}{6}\)
\(=1\times\frac{6}{5}\)
\(=\frac{6}{5}\)
\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)
\(=1+\frac{1}{6}\)
\(=\frac{7}{6}\)
Hok tốt!~
Bạn thử rút gọn các phân số đi
Sau đó bạn đi tính
Như vậy kết quả sẽ nhỏ hơn đấy
24 x \(\frac{4}{6}\)x \(\frac{3}{4}\) = \(\frac{24}{1}\) x \(\frac{4}{6}\) x \(\frac{3}{4}\)
= \(\frac{24x4x3}{1x6x4}\)
= \(\frac{6x4x4x3}{1x6x4}\)
= 3
\(\frac{5}{6}:\frac{8}{9}-\frac{3}{4}:\frac{8}{9}\)
\(=\left(\frac{5}{6}-\frac{3}{4}\right):\frac{8}{9}\)
\(=\frac{1}{12}:\frac{8}{9}\)
\(=\frac{1}{12}\times\frac{9}{8}\)
\(=\frac{3}{32}\)
(\(\frac{5}{6}\)-\(\frac{3}{4}\)) : \(\frac{8}{9}\)
=\(\frac{1}{12}\): \(\frac{8}{9}\)
=\(\frac{3}{32}\)
k nhé, sau đó kb lun!
4/5 : 2/9 x 2/9 : 4/5
= 4/5 x 9/2 x 2/9 x 5/4
= ( 4/5 x 5/4 ) x ( 9/2 x 2/9 )
= 1x1
= 1
\(\frac{4}{5}:\frac{2}{9}\times\frac{2}{9}:\frac{4}{5}\)
\(=\frac{4}{5}\times\frac{9}{2}\times\frac{2}{9}\times\frac{5}{4}\)
\(=\left(\frac{4}{5}\times\frac{5}{4}\right)\times\left(\frac{2}{9}\times\frac{9}{2}\right)\)
\(=1\times1\)
\(=1\)
Đề là gì
\(\frac{637\times527-189}{637\times526+448}\)
\(=\frac{637\times526+637-189}{637\times526+448}\)
\(=\frac{637\times526+448}{637\times526+448}\)
\(=1\)
\(\frac{2005\times2006+6}{2005\times2005+2011}\)
\(=\frac{2005\times2005+2005+6}{2005\times2005+2011}\)
\(=\frac{2005\times2005+2011}{2005\times2005+2011}\)
\(=1\)